Related
I need execute json_encode() and convert my original number from:
50610101800060384093800100001010000000056199999999
to
"50610101800060384093800100001010000000056199999999"
But it return
5.061010180006E+49
I tried this:
ini_set('precision', 30); //With 1, 30, 50, 100, 1000
ini_set('serialize_precision', -1);
'content' => json_encode($params, JSON_NUMERIC_CHECK)
but doesn't work. Can you help me?
50610101800060384093800100001010000000056199999999 exceeds the value of the maximum integer in PHP and so it is promoted to a float and expressed in scientific notation. The float result may be problematic for various reasons as the Manual explains in warning about floating point precision.
If you wish to express the value as if it were an integer you must encapsulate it in a string. That string you may add zero to it but when you do so the result in scientific notation will refer to a float, as follows:
<?php
$s = "50610101800060384093800100001010000000056199999999";
echo $s,"\n";
$x = $s + 0;
echo $x, "\n",is_float($x);
See here.
For more info in re PHP and floats, see here.
On the other hand, if there were an array of numbers whose digits corresponded to the numerical display in the OP's post, you could write code as follows:
<?php
$a = [5,0,6,1,0,1,0,1,8,0,0,0,6,0,3,8,4,0,9,3,8,0,0,1,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,5,6,1,9,9,9,9,9,9,9,9];
foreach($a as $e) {
$e = (string) $e;
}
$foo = join($a);
var_dump($foo);
$foo = bcadd($foo, 1);
var_dump($foo);
See live code.
The reason this example works is because each array value is converted to a numerical string and then the individual elements are joined to form one very long numerical string. BC Math is an extension in PHP which supports arbitrary precision. In this case, the bcadd() function adds one to the numerical string which results in the display of an incremented numerical string value.
Try This [https://3v4l.org/biNJG][1]
If you want this output "50610101800060384093800100001010000000056199999999"
you may want to pass this Value as string after encoding the value to JSON using json_encode
An integer data type is a non-decimal number between -2,147,483,648 and 2,147,483,647.
Rules for integers:
An integer must have at least one digit
An integer must not have a decimal point
An integer can be either positive or negative
Integers can be specified in three formats: decimal (10-based), hexadecimal (16-based - prefixed with 0x) or octal (8-based - prefixed with 0)
I know of the PHP function floor() but that doesn't work how I want it to in negative numbers.
This is how floor works
floor( 1234.567); // 1234
floor(-1234.567); // -1235
This is what I WANT
truncate( 1234.567); // 1234
truncate(-1234.567); // -1234
Is there a PHP function that will return -1234?
I know I could do this but I'm hoping for a single built-in function
$num = -1234.567;
echo $num >= 0 ? floor($num) : ceil($num);
Yes intval
intval(1234.567);
intval(-1234.567);
Truncate floats with specific precision:
echo bcdiv(2.56789, 1, 1); // 2.5
echo bcdiv(2.56789, 1, 3); // 2.567
echo bcdiv(-2.56789, 1, 1); // -2.5
echo bcdiv(-2.56789, 1, 3); // -2.567
This method solve the problem with round() function.
Also you can use typecasting (no need to use functions),
(int) 1234.567; // 1234
(int) -1234.567; // -1234
http://php.net/manual/en/language.types.type-juggling.php
You can see the difference between intval and (int) typecasting from here.
another hack is using prefix ~~ :
echo ~~1234.567; // 1234
echo ~~-1234.567; // 1234
it's simpler and faster
Tilde ~ is bitwise NOT operator in PHP and Javascript
Double tilde(~) is a quick way to cast variable as integer, where it is called 'two tildes' to indicate a form of double negation.
It removes everything after the decimal point because the bitwise operators implicitly convert their operands to signed 32-bit integers. This works whether the operands are (floating-point) numbers or strings, and the result is a number
reference:
https://en.wikipedia.org/wiki/Double_tilde
What does ~~ ("double tilde") do in Javascript?
you can use intval(number); but if your number bigger than 2147483648 (and your machine/os is x64) all bigs will be truncated to 2147483648. So you can use
if($number < 0 )
$res = round($number);
else
$res = floor($number);
echo $res;
You can shift the decimal to the desired place, intval, and shift back:
function truncate($number, $precision = 0) {
// warning: precision is limited by the size of the int type
$shift = pow(10, $precision);
return intval($number * $shift)/$shift;
}
Note the warning about size of int -- this is because $number is potentially being multiplied by a large number ($shift) which could make the resulting number too large to be stored as an integer type. Possibly converting to floating point might be better.
You could get fancy with a $base parameter, and sending that to intval(...).
Could (should) also get fancy with error/bounds checking.
An alternative approach would be to treat number as a string, find the decimal point and do a substring at the appropriate place after the decimal based on the desired precision. Relatively speaking, that won't be fast.
For the purpose of the example, var 2 is preset from a database as "147.22" type STRING. var 1 is calculated previously in the script and has 147.22 type FLOAT.
Script:
<?
$var1 = (float)$var1;
$var2 = (float)$var2;
var_dump($var1);
var_dump($var2);
if($var1 < $var2) { echo "hello"; }
?>
My expected results would be that the script NOT echo "hello" since the two values are equal in amount and type.
However here is the output I'm getting:
float(197.22)
float(197.22)
hello
If I do not mess with the types and leave the one a float and the other a string, then it still does not work (this is how I got here in the first place).
If i force the values at the time of execution like this:
$var1 = 147.22;
$var2 = 147.22;
var_dump($var1);
var_dump($var2);
if($var1 < $var2) { echo "hello"; }
?>
I get this, (and it works):
float(197.22)
float(197.22)
Notice no "hello"....
Anyone have any clue wth is going on here?
If one of the floats is calculated numerically, and one is created from string assignment, they could be different. Try the following:
$x = 147.22;
$y = 147.2200000000001;
printf("%.40f\n", $x);
printf("%.40f\n", $y);
var_dump($x);
var_dump($y);
var_dump($x < $y);
outputs
147.2199999999999988631316227838397026062012
147.2200000000001125499693443998694419860840
float(147.22)
float(147.22)
bool(true)
Cast them to a string with a specified precision for comparison.
If you are dealing with floats, then it's not safe to compare them directly, because there may be rounding or representation issues.
You'd better to check if the difference between those numbers is less than some predefined and very minimal epsilon, and then determine if they're equal, or which is the greater one.
This discussion may be worth reading: Is casting to float destructive?
EDIT:
More discussions to read:
PHP: Floating point numbers
php integer and float comparison mismatch
I'm trying to output a value from xml this is what I do -
<?php
echo $responseTemp->Items->Item->CustomerReviews->AverageRating;
?>
This outputs 4.5, but when I change it to the code below it displays as 8. Why isn't it displaying as 9? Thanks.
<?php
echo $responseTemp->Items->Item->CustomerReviews->AverageRating*2;
?>
Try casting the value to a numerical value first.
$num = (double) $responseTemp->Items->Item->CustomerReviews->AverageRating;
echo $num * 2;
See Type Juggling and String Conversion to Numbers on the PHP website for more information.
If you are looking for a decimal value without doing typecasting, you have to multiply by a number with a decimal. Otherwise it will return a regular integer like the number you gave it.
Try multiplying by 2.0
echo $responseTemp->Items->Item->CustomerReviews->AverageRating*2.0;
I am not familiar with PHP at all and had a quick question.
I have 2 variables pricePerUnit and InvoicedUnits. Here's the code that is setting these to values:
$InvoicedUnits = ((string) $InvoiceLineItem->InvoicedUnits);
$pricePerUnit = ((string) $InvoiceLineItem->PricePerUnit);
If I output this, I get the correct values. Lets say 5000 invoiced units and 1.00 for price.
Now, I need to show the total amount spent. When I multiply these two together it doesn't work (as expected, these are strings).
But I have no clue how to parse/cast/convert variables in PHP.
What should I do?
$rootbeer = (float) $InvoicedUnits;
Should do it for you. Check out Type-Juggling. You should also read String conversion to Numbers.
You want the non-locale-aware floatval function:
float floatval ( mixed $var ) - Gets the float value of a string.
Example:
$string = '122.34343The';
$float = floatval($string);
echo $float; // 122.34343
Well, if user write 1,00,000 then floatvar will show error. So -
floatval(preg_replace("/[^-0-9\.]/","",$input));
This is much more reliable.
Usage :
$input = '1,03,24,23,434,500.6798633 this';
echo floatval(preg_replace("/[^-0-9\.]/","",$input));
Dealing with markup in floats is a non trivial task. In the English/American notation you format one thousand plus 46*10-2:
1,000.46
But in Germany you would change comma and point:
1.000,46
This makes it really hard guessing the right number in multi-language applications.
I strongly suggest using Zend_Measure of the Zend Framework for this task. This component will parse the string to a float by the users language.
you can follow this link to know more about How to convert a string/number into number/float/decimal in PHP.
HERE IS WHAT THIS LINK SAYS...
Method 1: Using number_format() Function. The number_format() function is used to convert a string into a number. It returns the formatted number on success otherwise it gives E_WARNING on failure.
$num = "1000.314";
//Convert string in number using
//number_format(), function
echo number_format($num), "\n";
//Convert string in number using
//number_format(), function
echo number_format($num, 2);
Method 2: Using type casting: Typecasting can directly convert a string into a float, double, or integer primitive type. This is the best way to convert a string into a number without any function.
// Number in string format
$num = "1000.314";
// Type cast using int
echo (int)$num, "\n";
// Type cast using float
echo (float)$num, "\n";
// Type cast using double
echo (double)$num;
Method 3: Using intval() and floatval() Function. The intval() and floatval() functions can also be used to convert the string into its corresponding integer and float values respectively.
// Number in string format
$num = "1000.314";
// intval() function to convert
// string into integer
echo intval($num), "\n";
// floatval() function to convert
// string to float
echo floatval($num);
Method 4: By adding 0 or by performing mathematical operations. The string number can also be converted into an integer or float by adding 0 with the string. In PHP, performing mathematical operations, the string is converted to an integer or float implicitly.
// Number into string format
$num = "1000.314";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.1;
Use this function to cast a float value from any kind of text style:
function parseFloat($value) {
return floatval(preg_replace('#^([-]*[0-9\.,\' ]+?)((\.|,){1}([0-9-]{1,3}))*$#e', "str_replace(array('.', ',', \"'\", ' '), '', '\\1') . '.\\4'", $value));
}
This solution is not dependant on any locale settings. Thus for user input users can type float values in any way they like. This is really helpful e.g. when you have a project wich is in english only but people all over the world are using it and might not have in mind that the project wants a dot instead of a comma for float values.
You could throw javascript in the mix and fetch the browsers default settings but still many people set these values to english but still typing 1,25 instead of 1.25 (especially but not limited to the translation industry, research and IT)
I was running in to a problem with the standard way to do this:
$string = "one";
$float = (float)$string;
echo $float; : ( Prints 0 )
If there isn't a valid number, the parser shouldn't return a number, it should throw an error. (This is a condition I'm trying to catch in my code, YMMV)
To fix this I have done the following:
$string = "one";
$float = is_numeric($string) ? (float)$string : null;
echo $float; : ( Prints nothing )
Then before further processing the conversion, I can check and return an error if there wasn't a valid parse of the string.
For the sake of completeness, although this question is ancient, it's worth mentioning the filter_var() set of functions, which should not only handle the formatting bits itself, but also validate or sanitise the output, thus being safer to use in the context of a form being filled in by users (or, eventually, a database that might have some corrupted/inconsistent fields):
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
printf("The total is: %.2f\n", $InvoicedUnits * $pricePerUnit); // both are now floats and the result is a float, formatted to two digits after the decimal sign.
This sanitises the output (which will still remain a string) and will accept the current locale's setting of the decimal separator (e.g. dot vs. comma); also, there are more options on the PHP manual for validation (which will automatically convert the result to a float if valid). The results will be slightly different for different scenarios — e.g. if you know in advance that the $InvoiceLineItem will only have valid digits and symbols for floating-point numbers, or if you need to 'clean up' the field first, getting rid of whitespace, stray characters (such as currency symbols!), and so forth.
Finally, if you wish to have nicely-formatted output — since the total is expressed in a currency — you should also take a look at the built-in NumberFormatter class, and do something like:
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$fmt = new NumberFormatter('de_DE', NumberFormatter::CURRENCY);
echo 'Total is: ' . $fmt->formatCurrency($InvoicedUnits * $pricePerUnit, 'EUR') . PHP_EOL;
This will also handle thousand separators (spaces, dots, commas...) according to the configured locale, and other similar fancy things.
Also, if you wish, you can use '' (the empty string) for the default locale string (set either by the server or optionally by the browser) and $fmt->getSymbol(NumberFormatter::INTL_CURRENCY_SYMBOL) to get the default 3-letter currency code (which might not be what you want, since usually prices are given in a specific currency — these functions do not take currency exchange rates into account!).
If you need to handle values that cannot be converted separately, you can use this method:
try {
// use + 0 if you are accounting in cents
$doubleValue = trim($stringThatMightBeNumeric) + 0.0;
} catch (\Throwable $th) {
// bail here if you need to
}