im trying to do a post to a php and save in a mysql database
this is the ION.with command:
Ion.with(this)
.load("http_my_page/test.php")
.setBodyParameter("text", "não")
.asString(Charset.defaultCharset())//default=UTF-8
.setCallback(new FutureCallback<String>() {
#Override
public void onCompleted(Exception e, String result) {
}
});
my test.php page:
<?php
$test = $_POST["text"];
$servername = ...;
$username = "..";
$password = "...";
$dbname = "...";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO test (my_test) VALUES ('$test')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
and my MYSQL database has a column called my_test and collation is UTF8_unicode_ci
what im specting to store: "não"
what it really store: "não"
any reason? since im setting all the econdings =(
That was a PHP/MYSQL encoding issue and nothing related to Ion
$conn->set_charset("utf8");
Related
I've been trying to figure out how to insert data into mySQL database for a long time. When I try to insert data, it returns "no database selected". I'm not too sure what's wrong with the code, could someone check it out?
<?php
$servername = "localhost";
$database= "learnsc2_ts";
$username = "learnsc2_admin";
$password = "Ts#123";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
else {
echo "Connection successful";
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
mysqli_query($conn, $query);
if (mysqli_query($conn, $query)) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);?>
Make sure your database name is correct.
i tested it in my local, It's work Just fine.
$servername = "localhost";
$database= "test";
$username = "root";
$password = "";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
$query = mysqli_query($conn, $query);
if ($query) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);
}
You forgot to add database name
$conn = new mysqli($servername, $username, $password, $database);
I figured it out. Something was wrong with the old username I was using. After changing to a new username and database, it worked out!
I have very strange problem. I want to run mysql query as it is shown down below, but it's not working. Connection to database is successful, INSERT query is ok too, because when I run it directly in phpmyadmin Console it works, but it's not working here in PHP code.
Could you tell me what I'm missing?
$servername = "localhost";
$username = "admin";
$password = "admin123";
$dbname = "database1";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO last_visit (ip, lastvisit) VALUES ('123', '123')";
You need to run your $sql, because now your $sql is only a string, it does nothing.
Add this :
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
function inseartinto()
{
$DEL_LOG_REP = $connection->prepare("DELETE FROM test WHERE itemname='111'")$DEL_LOG_REP->execute()$DEL_LOG_REP->close()return $DEL_LOG_REP
}
This is short tutorails on connection in insert query into php...
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
For more better understand..go to http://www.w3schools.com/php/default.asp
What code are you trying to writing man..
This is not a valid code for just not insert but also for connetion..
ya go onto W3School.com as mention by #Sasa.D... it provide you with knowledge from basic to expertise..
Im still new in PHP, I'd like help in a php example where I click a link, a value gets updated in mysql and redirect the user to a page.
Your will be greatly appreciated.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE MyGuests SET lastname='Doe' WHERE id=2";
if ($conn->query($sql) === TRUE) {
// if all ok, redirecting
header("Location: http://example.com/myOtherPage.php");
die();
} else {
echo "Error updating record: " . $conn->error;
}
$conn->close();
?>
I'm not exactly sure what happened but this database and the php effecting it were working just fine until it hit the fourth row and now it won't insert new records at all.
if($_POST)
{
$servername = ******;
$username = ******;
$password = ******;
$db = ******;
$conn = mysqli_connect($servername, $username, $password, $db);
mysqli_select_db($conn,$db);
$uuid = $_POST['uuid'];
$sql = "INSERT INTO uuid VALUES ('$uuid');";
mysqli_query($conn,$sql);
mysqli_close($conn);
}
I'm not sure what happened but this is the relevant code for the mysqli query.
try this
<?php
if(isset($_POST['uuid']))
{
$servername = yourServerName;
$username = username;
$password = password;
$dbname = databaseName;
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$uuid = $_POST['uuid'];
$sql = "INSERT INTO tableName (columnName) VALUES ('$uuid')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
}
?>
Also, I recommend using prepared statements.