Decode php encoded json not working - php

Here is my data.php
$global = $pdo->query("SELECT name, age");
$global = $global->fetchAll(PDO::FETCH_ASSOC);
$arr = array('data'=>$global);
echo json_encode($arr, JSON_PRETTY_PRINT);
Here is my index.php
<html>
<?php
$json_url = "data.php";
$json = utf8_encode(file_get_contents($json_url));
$data = json_decode($json, false);
echo "<pre>";
print_r($data);
echo "</pre>";
?>
</html>
I get blank data. What am I doing wrong?


Try this:
$query = "SELECT * FROM table";
$stmt = $pdo->query($query);
$global= $stmt->fetchAll(PDO::FETCH_ASSOC);
$arr = array('data'=>$global);
echo json_encode($arr);
//echo json_encode($arr, JSON_PRETTY_PRINT);


First of all make sure file_get_contents is actually returning something.
If not, check your logs to see what file its actually requesting. Use a full-path ex: http://location/path/to/data.php
I have had issues with reading JSON without setting the Content-Type.
header('Content-Type: application/json')

Related

Returning value from restAPI in php, echo value not showing

I'm trying to return a value from my API using PHP, api can be found here:
code is as follows:
Im not seeing the echo on my page, don't see any errors and I believing im reading the json in correctly. Any help appreciated!
<?php
$titleid = 2;
$url = "http://kmoffett07.lampt.eeecs.qub.ac.uk/serverSide/buildapi.php?id={$titleid}";
$response = file_get_contents($url);
$returnvalue = json_decode($response, true);
echo $returnvalue["Age"];
?>

From what I can tell, the json is not valid on the server side (due to the "connected to db" text in front of the {} part). I think it would be a good idea to fix the server side response json data, if possible!
For now, here is a way to get the value it looks like you are intending to retrieve:
<?php
$titleid = 2;
$url = "http://kmoffett07.lampt.eeecs.qub.ac.uk/serverSide/buildapi.php?id={$titleid}";
$response = file_get_contents($url);
$adjusted_response = str_replace('connected to db', '', $response);
$returnvalue = json_decode($adjusted_response, true);
echo $returnvalue['tv_shows']['Age'];
?>
Output:
$ php example.php
16+
If the server side json data is fixed, I think you could shorten the code to something like this:
<?php
$titleid = 2;
$url = "http://kmoffett07.lampt.eeecs.qub.ac.uk/serverSide/buildapi.php?id={$titleid}";
$response = file_get_contents($url);
$returnvalue = json_decode($response, true);
echo $returnvalue['tv_shows']['Age'];
?>

The thing is that $response is returned as string , in order to fix that you need to edit your backend and make it give the response without "connected to db"

How to output json data in array using curl

I have code here that will get json data using curl. Now I want to echo all data. This will show no output.
<?php
$json = file_get_contents('myurl');
$data = json_decode($json);
print_r($data);
?>
This is json coming from my url:
({"Response_Code":"0000","ResultMobilePrefix":["0917","0905","0906","0915","0916","0926","0927","0937","0935","0817","0936","0922","0923",
"0932","0933","0934","0942","0943","0907","0908","0909","0910","0912","0918","0919","0920","
0921","0928","0929","0930","0938","0939","0948","0949","0925","0989","0999","0947","0998","
0946","0975","0977"]});

All you need is
echo json_encode($json);

Use true to convert it into array;
$data = json_decode($json,true);
echo '<pre>';
print_r($data);

for displaying json in format use json_encode() and for proper format use JSON_PRETTY_PRINT
header('Content-type: application/json');
echo json_encode($json,JSON_PRETTY_PRINT);

you need to get rid of the bracket and semicolon on the JSON file first before you can use the json_decode();
<?php
$json = file_get_contents('myurl');
//remove the brackets
$json = str_replace("(", "", $json);
$json = str_replace(")", "", $json);
//remove the semicolon
$json = str_replace(";", "", $json);
$data = json_decode($json);
print_r($data);
?>
this is a bit ugly, but hope you get the idea, you need to remove that character first

I just want to add to what Manish has explained above. This is what PHP Docs say about the second parameter:
When TRUE, returned objects will be converted into associative arrays.
else you will simply get a stdclass object

The problem is the URL does not return a valid Json
you could simply try
var_dump($data);
this will return null because it's not a valid json see json_decode
this will work
$json = file_get_contents('myurl');
$json = preg_replace('/[ ]{2,}|[\t\n\r\(\)\;]/', '', trim($json));
$data = json_decode($json);
print_r($data);

PHP json_decode displaying blank

<?php
$url = "http://api.giphy.com/v1/gifs/search?q=hello&api_key=dc6zaTOxFJmzC";
$content = file_get_contents($url);
$json = json_decode($content);
echo $json->images[0]->fixedheight->url[0];
?>
I've tried everything- even reading it as an array and it doesn't work.
Any help?
So sorry to bother! Thanks again.

You should access it this way
echo $json->data[0]->images->fixed_height->url;
That is beacause the $data is an array , and it has an object as its first parameter.

use this
<?php
$url = "http://api.giphy.com/v1/gifs/search?q=hello&api_key=dc6zaTOxFJmzC";
$content = file_get_contents($url);
$json = json_decode($content);
echo "<pre>";
print_r($json->data[0]->images->fixed_height->url);
exit;
?>

get data from JSON file (with cURL)

I would like to trnsform some JSON data to a php array, this is my code:
<?php
$obj1=json_decode('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json', true);
$championname = $obj1[data][aatrox][name];
echo $championname;
?>
The problem is that i don't know how to get the data from http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json
How can i make this code work?

Try with file_get_contents() like this:
$json = file_get_contents('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json');
$obj1 = json_decode($json , true);
$championname = $obj1['data']['aatrox']['name'];
echo $championname;

Use file_get_contents to download a file.
$json = file_get_contents('http://ddragon.leagueoflegends.com/cdn/3.15.5/data/en_US/champion/Aatrox.json');
$obj1 = json_decode($json, true);

PHP json_decode brings back null

I am trying to get this to work but can't see where I'm going wrong. Can anyone assist?
<?php
$jsonurl = 'http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json_output = var_dump(json_decode($json,true));
echo $json_output
?>

Hint :
The initial JSON (stored in $json variable) does NOT validate.
Code : (FIXED)
<?php
$jsonurl='http://www.foxsports.com.au/internal-syndication/json/livescoreboard';
$json = file_get_contents($jsonurl,0,null,null);
$json = strip_tags(str_replace("jQuery.fs['scoreboard'].data =","",$json));
$json_output = var_dump(json_decode($json,true));
echo $json_output;
?>
This will work. :-)

Your JSON source is not valid. You can try this validator http://jsonlint.com/

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