Put a list of arrays in a php variable - php

Question

I have a big piece of php code that builds a dropdown menu and I want to minimize it by loading the select options from a text file. How to do this in the right way with php?
An example of original code:
$field['options'] = array(
array('value' => 'Anenii Noi', 'text' => 'Anenii Noi', 'depth' => 0),
array('value' => 'Bălţi', 'text' => 'Bălţi', 'depth' => 0),
array('value' => 'Basarabeasca', 'text' => 'Basarabeasca', 'depth' => 0),
....
array('value' => 'Ungheni', 'text' => 'Ungheni', 'depth' => 0)
);
And this is what I try to do, but without success:
// read a text file with select options
// where each option is a seperate line
$file_array = str_replace("\n","", file($file_path));
// build the list of arrays with select options
foreach ($file_array as $location)
$options .= "array('value' => '" . $location . "', 'text' => '" . $location . "', 'depth' => 0),";
foreach($form['field'] as $k => $field) {
// replace the big list of arrays with $options variable
$field['options'] = array($options);
$form['field'][$k] = $field;
break;
}

Answer 1

Looks like you had it almost. But you tried to mimic the pure php code, that might have worked if you use eval() later on, but you need to mimic its functionality.
// read a text file with select options
// where each option is a seperate line
$file_array = str_replace("\n","", file($file_path));
// build the list of arrays with select options
$options = array();
foreach ($file_array as $location) {
$options[] = array('value' => $location, 'text' => $location, 'depth' => 0);
}
foreach($form['field'] as $k => $field) {
$field['options'] = $options;
$form['field'][$k] = $field;
break;
}