Retrieving data belonging to a session and user id - php

I am trying to obtain data from the current session and the field "bidder_id" from tbl_bidder where the field "accept" has the value Accepted, but I get data of all the users in that table which is not I want. This is my code
<?php } else if (($_SESSION['Usertype']) == 'recruiter') { ?>
<table class="table table-hover">
<?php
$u_id = $_SESSION['UserID'];
$notifyR = " SELECT bidid, recbid_id, bidder_id, selected, accept FROM tbl_bides WHERE recbid_id = '" . $u_id . "'";
$ResultR = mysql_query($notifyR, $con);
while ($rowR = mysql_fetch_array($ResultR)) {
if ($rowR['accept'] == "Accepted") {
echo "<h3 style='color:#001F7A;'><b>You Have Updates </b><i class='fa fa-bell-o'></i></h3>";
echo $rowR['bidder_id'];
}
$recR = "SELECT users_id, first_name, last_name FROM tbl_users WHERE users_id = '" . $rowR['bidder_id'] . "'";
$recResultB = mysql_query($recR, $con)or die(mysql_error());
while ($rowre = mysql_fetch_array($recResultB)) {
echo " <tr><td>" . $rowre['first_name'] . " " . $rowre['last_name'] . "</td></tr>";
}
}
?>
Please help!!!

Change From
$notifyR = " SELECT bidid, recbid_id, bidder_id, selected, accept FROM tbl_bides WHERE recbid_id = '" . $u_id . "'";
To
$notifyR = " SELECT bidid, recbid_id, bidder_id, selected, accept FROM tbl_bides WHERE recbid_id = '" . $u_id . "' and accept = 'Accepted' ";
add this on your query and accept = 'Accepted' in $notifyR

I hope you might need to use the following query if you stored the user id in $_SESSION['UserID']. May be logical error: And also use mysqli_query instead of mysql_query which is deprecated in latest php versions. And instead of binding the variable directly in query, use bind param of prepared statement.
$recR = "SELECT users_id, first_name, last_name FROM tbl_users WHERE users_id = '" . $_SESSION['UserID'] . "' LIMIT 1";

If you only want to execute the second query (selecting the user associated with the given bid) when the bid has been "accepted" then you need to move that code into your conditional:
if ($rowR['accept'] == "Accepted") {
echo "<h3 style='color:#001F7A;'><b>You Have Updates </b><i class='fa fa-bell-o'></i></h3>";
echo $rowR['bidder_id'];
$recR = "SELECT users_id, first_name, last_name
FROM tbl_users
WHERE users_id = '" . $rowR['bidder_id'] . "'";
$recResultB = mysql_query($recR, $con)or die(mysql_error());
while ($rowre = mysql_fetch_array($recResultB)) {
echo " <tr><td>" . $rowre['first_name'] . " " . $rowre['last_name'] . "</td></tr>";
// echo $rowre['users_id'];
}
}
You may want to consider using a newer interface to MySQL, such as PDO, and protecting your code from SQL injection attacks by using techniques such as prepared statements or at least input cleansing.

Related

how to insert into multiple fields in same db

I am looking to insert a single selection into a field for multiple users. I have the following code, when the selection is made and submit is entered. I do not get an error, I get the next page with the message posted 5 times, which is how many users are not it the weekpicks table. But nothing is inserted into the DB.
<?
// This code is to use to place info into the MySQL
$sTeam1 = $_POST['sTeam1'];
// (WHERE username FROM authorize WHERE username not in ( SELECT username FROM weekpicks WHERE whatweek='$totalnoOfWeek' )" .
//$nMemberID = (integer) Query
$sql_events = mysql_query("SELECT username FROM authorize WHERE username not in ( SELECT username FROM weekpicks WHERE whatweek='$totalnoOfWeek' )") or die(mysql_error());
while ($row = mysql_fetch_array($sql_events)) {
$username = $row["username"];
("INSERT INTO weekpicks SET " . "username = '" . ($username) . "'," . "date_create = NOW(), " . "whatweek = '" . ($totalnoOfWeek) . "'," . "team = '" . addslashes($sTeam1) . "'" . 'INSERT');
echo "<HTML>
<BODY>
<h2>Your pick of " . ($sTeam1) . ", for week " . ($totalnoOfWeek) . ", has been added.</h2>
<P align=left>Return to main page</p>
</BODY>
</HTML>";
}
?>
You are creating the string for insert but you are not running it.
Fixing your code it'd be:
while ($row = mysql_fetch_array($sql_events)) {
$username = $row["username"];
mysql_query("INSERT INTO weekpicks SET " . "username = '" . ($username) . "'," . "date_create = NOW(), " . "whatweek = '" . ($totalnoOfWeek) . "'," . "team = '" . addslashes($sTeam1) . "'");
//echo ...
}
Fixing the string syntax you could do this, which looks nicer. Also using mysql_real_escape_string() instead of addslashes(), since addslashes is not as safe as mysql's native function for php.
$sTeam1 = mysql_real_escape_string($sTeam1);
mysql_query("INSERT INTO weekpicks SET username = '$username', date_create = NOW(), whatweek = '$totalnoOfWeek', team = '$sTeam1');
Another thing I must tell you:
Stop using mysql_*, use mysqli_* instead.
mysql_ was removed from PHP7 and deprecated after PHP 5.5
It's not as safe as mysqli_, so consider improving your code to the new model.
Follow this guide in order to change your code properly.

if statement to check if mysql row exists, then selecting next query

I'm attempting to select a query to use based on the number of rows returned by a test result.
$id = mysql_real_escape_string(htmlspecialchars($_POST['id']));
$result = "SELECT FROM Notifications WHERE UserID=$id";
$r = e_mysql_query($result);
$row = mysql_fetch_array($r);
$num_results = mysql_num_rows($result);
$result = '';
if ($num_results != 0) {
$result =
"SELECT U.UserID,U.FirstName,U.LastName, " .
" DATE_FORMAT(U.BirthDate,'%m-%d-%Y') AS BirthDate, " .
" N.Email, N.Phone,N.ProviderName, N.SubNotifications " .
" FROM Users U, Notifications N " .
" WHERE U.LocationID=0 " .
" AND N.UserID='$id'";
} else {
$result =
"SELECT UserID, FirstName, LastName," .
" DATE_FORMAT(BirthDate, '%m-%d-%Y') AS BirthDate " .
" FROM Users " .
" WHERE LocationID = 0 " .
" AND UserID ='$id'";
}
echo $result;
e_mysql_result($result); //Bastardized/homegrown PDO
if ($row = mysql_fetch_assoc($result)) {
$retValue['userInfo'] = $row;
...
I'm checking the Notifications table to see if the UserID exists there, if it doesn't it loads what does exist from the Users table, if it does, then it loads everything from the Notifications table.
I'm echoing out the $result and the proper statement is loaded, but it doesn't execute. When I run the concatenated query I get from the PHP preview, it returns just fine.
Before I had to if/else this, I was running the first query, loading everything from the Notifications table, and it was loading just fine. What am I missing?
You can do the whole thing with one query with a LEFT JOIN.
$query= "SELECT U.UserID, U.FirstName,U.LastName, " .
" DATE_FORMAT(U.BirthDate,'%m-%d-%Y') AS BirthDate, " .
" N.Email, N.Phone,N.ProviderName, N.SubNotifications " .
" FROM Users U " .
" LEFT JOIN Notifications N " .
" ON U.UserID = N.UserID " .
" WHERE U.UserID = '$id'";
You are missing execute a query with mysql_query() on all $result
Also change (query variable should be quoted) so change your all variables $id quoted
$result = "SELECT FROM Notifications WHERE UserID=$id";
to
$result = "SELECT FROM Notifications WHERE UserID='$id'";
$r = mysql_query($result);
Note :- mysql_* has been deprecated use mysqli_* or PDO

COUNT always returning 1

I have issue where obj->num_rows constantly returns 1 Heres my code:
$open_tickets = $con->query("SELECT COUNT(*) FROM support_tickets WHERE Username='" . $_SESSION['user'] . "'");
echo '<table><tr><th>Open Tickets</th><td>' . $open_tickets->num_rows . '</td></tr></table>';
$open_tickets->close();
$_SESSION['user'] is currently dextermb
As you can see in my SQL table, there are 2 tickets with the name dextermb, so why does the code always return 1?
You are getting the number of rows returned - of course, this is only ever going to be 1. You probably want to get the value that is returned rather than the number of rows.
Try this
$open_tickets = $con->query("SELECT * FROM support_tickets WHERE Username='" . $_SESSION['user'] . "'");
echo '<table><tr><th>Open Tickets</th><td>' . count($open_tickets) . '</td></tr> </table>';
$open_tickets->close();
The query will return the count, just use the value.
Try:
$open_tickets = $con->query("SELECT COUNT(*) FROM support_tickets WHERE Username='" . $_SESSION['user'] . "'");
echo '<table><tr><th>Open Tickets</th><td>' . $open_tickets . '</td></tr></table>';
$open_tickets->close();
Try this:
$stm = $con->prepare("SELECT COUNT(*) as total FROM support_tickets WHERE Username = :username");
$stm->bindParam(':username', $_SESSION['user']);
$stm->execute();
$row = $res->fetch();
echo '<table><tr><th>Open Tickets</th><td>' . $row->total . '</td></tr></table>';
Note prepare and bindParam methods. This way you avoid SQL Injection.

Update a sql table field one time with php

Below is my small code for inserting some info into AthleteID. It doesn't actually insert the information to the table though, any help is appreciated. (sorry for asking twice, but I think my first question isn't addressing whatever issue is holding me up here!)
<?php
require_once('resources/connection.php');
echo 'hello noob' . '<br />';
$query = mysql_query('SELECT LName, MyWebSiteUserID FROM tuser WHERE MyWebSiteUserID = MyWebSiteUserID');
$athleteId = strtoupper(substr($row["LName"], 0, 2)) . $row["MyWebSiteUserID"];
$update = "UPDATE `tuser` SET `AthleteID`='$athleteId' WHERE `MyWebSiteUserID` = `MyWebSiteUserID`;";
while($row = mysql_fetch_array($query)){
mysql_query( $update);
}
Where to begin..
1) Your using mysql and not mysqli. mysql is now deprecated but you could be on a PHP 4 system so keep that in mind.
2) You are building the $athleteID before you have found out what LName and SkillshowUserID is.
3) Your using a where of 1 = 1. You dont need this as it will return true for every row.
4) So...
// Execute a query
$results = mysql_query('SELECT LName, MyWebsiteID FROM tuser WHERE SkillshowUserID = SkillshowUserID');
// Loop through the result set
while($row = mysql_fetch_array($query))
{
// Generate the athleteId
$athleteId = strtoupper(substr($row["LName"], 0, 2)) . $row["MyWebsiteID"];
// Generate an sql update statement
$update = "UPDATE `tuser` SET `AthleteID`='" . $athleteId . "' " .
" WHERE LName = '" . $row['LName'] . "' " .
" AND MyWebsiteID = '" . $row['MyWebsiteID'] . "';";
// Fire off that bad boy
mysql_query($update);
}

How to put a PHP Variable into output of a SQL Query

Ok, I am querying my DB for a file. And I want to use a PHP global variable and stick it somewhere in that output using say a '$dir' in my table. Any possible way to do so?
Just use it in a string for the query like you would in any other string. eg:
$sql = "UPDATE TABLE x SET dir=" . $dir . " WHERE id=" . $id;
Though if you do this and your variables use user input it's VERY IMPORTANT to sanitize them against SQL injection and such. The function mysql_real_escape_string() is provided for just such instances.
$sql = "UPDATE TABLE x SET dir=" . mysql_real_escape_string($dir) . " WHERE id=" . mysql_real_escape_string($id);
$query = "SELECT '" . $dir . "' as myVariable, userName, userpassword from users where userName = ...."
The first reply was missing some quotes:
$sql = "UPDATE TABLE x SET dir=" . $dir . " WHERE id=" . $i
->
$sql = "UPDATE TABLE x SET dir='" . mysql_real_escape_string($dir) . "' WHERE id=" . $i
and
$sql = "UPDATE TABLE x SET dir=" . mysql_real_escape_string($dir) . " WHERE id=" . mysql_real_escape_string($id);
->
$sql = "UPDATE TABLE x SET dir='" . mysql_real_escape_string($dir) . "' WHERE id=" . mysql_real_escape_string($id);

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