I have two tables here.
log (stands for logbook)
act (stands for actions)
log
contains columns: logid, userid, actid
act
contains columns: actid, amount
Amount stands for an amount of points (e.g. 50 of 700 or 5) the user (userid) receives when the corresponding actid is inserted in the logbook (log).
What I'm trying to achieve is that when you search for userid 1, that all rows from log where userid = 1 are selected. Then, from these selected log-rows, the actids should be looked up in the table act, and the amounts should be summed.
In short:
select log-rows where userid = 1
take all the actids from these rows
find the matching amount in the act table
sum all these amounts
I started with this query:
SELECT log.logid, log.userid, log.actid, act.actid, act.amount
FROM log
JOIN act
ON act.actid = log.actid
WHERE log.userid = '1'
This got me a table with (among other things)
userid | amount
---1----|--20---
---1----|--40---
---1----|---5---
---1----|--10---
Now I would like to sum all these amounts and echo the total, but unfortunately I can't find a working query for this.
EDIT:
I used the query that Naruto provided me to sum these amounts. This works like a charm now! The query:
SELECT log.userid, sum(act.amount) FROM log JOIN act ON act.actid = log.actid WHERE log.userid = '1'
The next thing that I'm trying is to get not only the summed amount from the user with userid = 1, but also from the other users in the user-table. After that, I'd like to use these summed amounts in the following query:
$result = $mysqli->query("SELECT * FROM `db`.`user` ORDER BY `summed_amount` DESC");
In which summed_amount is the summed amount generated by Naruto's query.
MySQL has an Aggregate function called sum() which can sum all the records.
So your query will be
SELECT log.userid, sum(act.amount) FROM log JOIN act ON act.actid = log.actid WHERE log.userid = '1'
http://dev.mysql.com/doc/refman/5.7/en/group-by-functions.html#function_sum
To get sum of all users by a single query use group by clause.Here it will calculate sum of amaount for each user and return the result.
SELECT log.userid, sum(act.amount) FROM log JOIN act ON act.actid = log.actid group by log.userid
Edit:- To get order by desc
SELECT log.userid, sum(act.amount) FROM log JOIN act ON act.actid = log.actid group by log.userid order by sum(act.amount) desc
Related
I have two tables, one for registered users and one to store votes.
We are logging in with registrants.id and registrants.zipcode. Once they vote their votes are inserted into the votes table, along with their Registration ID.
Im trying to right a select statement that returns a record that will select all the records for Matched ID and Zipcode, but the ID is not in the Votes.voter column. i have tried all kinds of variations of all the joins i can think of. is it something simple i am missing.
SELECT * FROM registrants
LEFT JOIN votes on registrants.id = votes.voter
WHERE registrants.id = 1 AND registrants.zipcode = 46706 and votes.voter <> 1
Perhaps a not exists query:
select * from registrants
where registrants.zipcode = '46706'
and not exists (select 1 from votes where registrants.id = votes.voter)
I am trying to only show unique userIds (userIds are (0,1,2,3,4,5,6,7,8,9 etc...) for the query I am running. I tried using DISTINCT in my query, but it only shows me unique values of the rows that have 2 or more of the same userId.
Is there a way I can use php to only show the unique values. My weak points are arrays and it makes it more complicated because its using data from a MySQLi query.
Example right now I have with the query now (lets say its GROUP BY rentPaid DESC and the rent total is 800.00 for all users):
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
3--------400.00------April
1--------200.00------April
1--------100.00------April
Example desired output:
userID rentPaid rentMonth
2--------800.00------April
1--------500.00------April
3--------400.00------April
Can I do this with MYSQL because I tried DISTINCT and it wouldn't work, how about PHP?
Query:
SELECT
properties.*,
leases.*,
users.userId, users.primaryPhone,
CONCAT(users.userFirstName,' ',users.userLastName) AS user,
admins.adminName, payments.*
FROM
properties
LEFT JOIN leases ON properties.propertyId = leases.propertyId
LEFT JOIN assigned ON properties.propertyId = assigned.propertyId
LEFT JOIN admins ON assigned.adminId = admins.adminId
LEFT JOIN users ON properties.propertyId = users.propertyId
LEFT JOIN payments ON properties.propertyId = payments.propertyId
WHERE
payments.rentMonth = '$currentMonth' AND
payments.rentYear = '$currentYear'
Edit: Please excuse my formatting, this is my first post.
Edit: Added query....its long, but works lol. I only want unique userIds (no double or triple userIds etc...)
I suspect this is what you want:
SELECT userID, MAX(rentPaid) AS maxRentPaid, rentMonth
FROM yourTable
WHERE rentMonth = "April"
GROUP BY userID
ORDER BY maxRentPaid
I have a table ipaddresses that contains IP ranges. Columns are: ipStart, ipEnd
Example of
ipStart: 3579374832
ipEnd: 3579374839
Now I want to select 300ish IP addresses from another table: visit_count. And based on those 300 addresses I want to check if the ip address is in the range of any of IPs in the table ipaddresses
My current code:
$results = $database->query("SELECT user_id,
DATE_FORMAT(last_visit, '%Y-%m-%d') as datumet,
cookieId, ipaddress
FROM `visit_count`
WHERE last_visit BETWEEN
'$firstDayOfMonth' AND '$lastDayOfMonth'
AND user_id = '$userId'
GROUP BY cookieId
ORDER BY last_visit ASC");
$rows = $database->loadObjectList($results);
foreach ( $rows as $row ) {
$ipaddressLong = ip2long($row->ipaddress);
// This is where its very very slow
$selO = $database->query("SELECT ipStart, ipEnd FROM `ipaddresses`
WHERE '$ipaddressLong' BETWEEN `ipStart` AND `ipEnd`");
$rowO = $database->getrow($selO);
}
The result is a really slow query that consumes a lot of cpu.
ipaddresses has indexes for both ipStart and ipEnd and contains around 50k rows.
How can I make this go faster?
A quick and dirty change to a single query using a JOIN:-
SELECT a.ipStart, a.ipEnd
FROM `ipaddresses` a
INNER JOIN
(
SELECT user_id, DATE_FORMAT(last_visit, '%Y-%m-%d') as datumet, cookieId, inet_aton(ipaddress ) AS ipaddressLong
FROM `visit_count`
WHERE last_visit BETWEEN '$firstDayOfMonth' AND '$lastDayOfMonth'
AND user_id = '$userId'
GROUP BY cookieId
) b
ON b.ipaddressLong BETWEEN a.ipStart AND a.ipEnd
Note that this could probably be simplified. However it depends on your use of GROUP BY cookieId . At the moment this is going to get one row per cookie id, but which row is undefined (ie, could be any user_id, ip address and last visit date that goes with that cookie id).
You can simplify the first select. You don't need to select any fields beyond ipaddress. You also don't need to order or group the result. If you want unique ipaddresses, just use distinct
select distinct ipaddress
from visit_count
where last_visit between '$firstDayOfMonth' and '$lastDayOfMonth'
and user_id = '$userId'
300 selects don't seem to be much, even with the second table having 50k rows. On my machine, even without indexes, it takes only a fraction of a second.
If you want to simplify it anyway, you can join the two tables with
select ipstart, ipend
from ipaddresses i
join visit_count v on inet_aton(v.ipaddress) between i.ipstart and i.ipend
where v.last_visit between '$firstDayOfMonth' and '$lastDayOfMonth'
and v.userid = '$userId'
1) Use better query like other suggested to you
2) Have you defined indexes for the field you need ?
3) Dont know if you use mysql or mysqli...anyway use fetch_assoc that is faster then fetch_array
with this 3 trick you should be ok
i have two tables in my db .. one is Messages and the other is Contacts... both tables contain the mobile_number field.. in Contacts table there is no duplicate numbers ... but in Messages tables there are several duplicate numbers in mobileNo field...what i am doing is write now i am selecting the distinct mobile numbers from the Messages tables and then i am comparring the distinct numbers from the contacts table ... so if the messages_mobileNo is found on the contacts table then give me the contact name against the number otherwise messages_mobileNo ... so the problem is distinct not working .. i am not able to get the distinct numbers from the Messages table ... it is showing me the duplicate numbers
here is my query
SELECT DISTINCT Message.mobileNo,
Contact.mobileNo,
Contact.workNo,
Contact.homeNo,
Contact.other,
Contact.name,
Message.body,
Message.idTextMessage
FROM cakephp_db.textmessage AS Message
LEFT JOIN cakephp_db.contacts AS Contact ON (Message.user_id = Contact.user_id
AND ((Message.mobileNo = Contact.mobileNo)
OR (Message.mobileNo = Contact.workNo)
OR (Message.mobileNo = Contact.homeNo)
OR (Message.mobileNo = Contact.other)))
WHERE Message.User_id = 23
ORDER BY Message.idTextMessage DESC LIMIT 6
So your trying to get the last 6 messages of a person if I'm right?
SELECT Message.mobileNo,
Contact.mobileNo,
Contact.workNo,
Contact.homeNo,
Contact.other,
Contact.name,
Message.body,
Message.idTextMessage
FROM cakephp_db.textmessage AS Message
LEFT JOIN cakephp_db.contacts AS Contact ON Message.user_id = Contact.user_id
AND Message.mobileNo IN (Contact.mobileNo, Contact.workNo, Contact.homeNo, Contact.other)
WHERE Message.User_id = 23
GROUP BY Message.mobileNo
ORDER BY Message.idTextMessage DESC LIMIT 6
add a GROUP BY Message.mobileNo before your ORDER BY
If you are using MySQL SELECT DISTINCT with an ORDER BY added to it, you will have to create a temporary table where it can store its results. Here is a link offering more help:
MySQL DISTINCT Optimization
Select 3 rows from table1
Get a specific column data out of each row.
Then use that each column data obtained , to make a query again to get data from table2.
Store the data obtained in step 4 into a variable for each row.
Then put them in json array (table 1 , 3 rows + table 2's data(each of them).
I am building a rank table, it displays top 3 users with their rank name.
For example:
User1 has 2000 points , user 2 has 4000points , user 3 has 10k points , so the top 3 user is :
user 3 > user 2 > user 1
So , i want the php to go to 'users' table and get the top 3 members using this:
$query = mysql_query("SELECT * FROM users ORDER BY pts DESC LIMIT 3");
$rows = array();
while($r = mysql_fetch_assoc($query)) {
$rows[] = $r;
}
Table structure for 'user':
1.username(varchar)
2.pts(int)
After the rows are put into an array , how can i get 'points' for each of the row in that array.
Then go to 'rank' table to get their ranknames.
Table structure for 'rank':
1.rank(varchar)
2.pts(int)
Inside rank table there is 'pts' to let php choose compare which rank the user is at based on the points from each row of the array.
Normally i would use this if its only for 1 user , but for multiple users , im not sure:
$result = mysql_query("SELECT * FROM rank WHERE pts <= '$upts' ORDER BY pts DESC LIMIT 1")
or die(mysql_error());
Then after getting the rank for the top 3 users , php will now add the ranks to each of the user(row) in that array(of course , add it to the rank owner, not just simply place it in).
Then JSON encode it out.
How can i do this?
I am not sure if this is what you want. That is combine the two query into one query. Please take a look at http://sqlfiddle.com/#!2/ad419/8
SELECT user.username,user.pts,rank.rank
FROM user LEFT JOIN rank
ON user.pts <=rank.pts group by user.id
UPDATED:
For extracting top 3, could do as below;
SELECT user.username,user.pts,rank.rank
FROM user LEFT JOIN rank
ON user.pts <=rank.pts
GROUP BY user.id
ORDER BY pts DESC LIMIT 3
If i understand correctly, you need to get values from Rank and Users tables. In order to do that in just one query You need to add FK (Foreign Key) to the Rank table that points to a specific user in the Users table.
So you need to add userId to the Rank table and then you can run:
SELECT r.rank, u.points from users u,rank r where u.userId = r.userId
This is roughly what you need.
Not quite the answer to your exact question, but this might be of use to you: How to get rank using mysql query. And may even mean that you don't require a rank table. If this doesn't help, I'll check back later.
Use this query
$query = "SELECT
u.pts,
r.rank
FROM users as u
left join ranks as r
on r.pts = u .pts
ORDER BY pts DESC
LIMIT 3";
This will bring what you required without putting into an array
$rec = mysql_query($query);
$results = arrau();
while($row = mysql_fetch_row($rec)){
$results[] = $row;
}
echo json_encode($results);
It looks like what you're trying to do is retrieve the rank with the highest point requirement that the user actual meets, which isn't quite what everyone else is giving here. Fortunately it is easily possible to do this in a single query with a nice little trick:
SELECT
user.username,
SUBSTRING_INDEX(GROUP_CONCAT(rank.rank ORDER BY pts DESC),",",1) AS `rank`
FROM user
LEFT JOIN rank ON user.pts >= rank.pts
GROUP BY user.id
ORDER BY pts DESC
LIMIT 3
Basically what the second bit is doing is generating a list of all the ranks the user has achieved, ordering them by descending order of points and then selecting the first one.
If any of your rank names have commas in then there's another little tweak we need to add on, but I wouldn't have thought they would so I've left it out to keep things simple.