I have a form, which includes a date field.
The date will be received in the format dd-mm-yyyy (e.g. 08-11-2015).
I want to convert this to a unix timestamp before inserting into the database.
If possible, I would like to use Codeigniter functions rather than native PHP functions.
Codeigniter has the function:
human_to_unix($input)
The function does not accept a format string and I cannot find the correct format to use ( how will it now that 08-11-2015 is 8th March 2015 rather than 11th August 2015??).
Thanks
The default date_helper in CodeIgniter won't accept dates in the format dd-mm-yyyy. You can use standard PHP (although you specified you would prefer CodeIgniter functions):
$date = DateTime::createFromFormat('d-m-Y', '08-11-2015');
echo $date->format('U');
Alternatively, you can extend the helpers that CodeIgniter provides.
Create a new file application/helpers/MY_date_helper.php:
<?php
function human_to_unix_alternative($datestr) { // change this to a suitable function name
$date = DateTime::createFromFormat('d-m-Y', $datestr);
return $date->format('U');
}
You can then use it in your code, just as you'd use human_to_unix($input), e.g. human_to_unix_alternative($input).
U have to use date format like this to get
human_to_unix -> YY-MM-DD HH:MM <space> meridian
ex:
$this->load->helper('date_helper');
human_to_unix("2015-12-03 03:28 PM");
outputs:
1449136680
$this->load->helper('date');
$input = strtotime('08-11-2015');
$human = unix_to_human($input);
$unix = human_to_unix($human);
Output will be:
2015-11-08 12:00 AM
Related
I am using DateTime function of php. I get a date from a calendar in format d-m-Y and pass it via ajax to my function. I am getting the date right till this step.
When I try to store the date in unix format using:
$ai_ff_date=DateTime::CreateFromFormat('d-m-Y', $data['date']);
$final_date=$ai_ff_date->format('U');
The date stored is wrong. Suppose the date I passed via ajax is 26-12-2016 then in database 27-12-2016 is stored. Why its counting one more day then the input.
use this code :
$date = date('Y-m-d H:i:s', strtotime('-1 day', $stop_date));
$ai_ff_date=DateTime::CreateFromFormat('d-m-Y',$date);
$final_date=$ai_ff_date->format('U');
and please check the variable (code not tested)
You might want to convert the Date-Format to "Y-m-d" First and then call-in the DateTime() Constructor. However, since what you are trying to do is just get the TimeStamp you might also do that directly without using DateTime. The Snippet below shows what is meant here:
<?php
$data = ['date'=>"13-12-2016"]; //<== JUST AN EXAMPLE FOR TESTING!!!
// SIMPLY CONVERT THE DATE TO Y-m-d FIRST.
$dateYMD = date("Y-m-d", strtotime($data['date']));
// THEN USE DateTime CONSTRUCTOR TO CREATE A NEW DateTime INSTANCE
// AND THEN RUN THE FORMAT YOU WISH::
$final_date = (new DateTime($dateYMD))->format('U');
var_dump($final_date); //<== YIELDS: string '1481583600' (length=10)
var_dump(date("Y-m-d", $final_date)); //<== YIELDS: string '2016-12-13' (length=10)
I want to store a specific date in a variable. If stored like $x="01/01/2016" it is acting as a string from which I cannot extract a part, like from getdate() year, month, day of the month, etc.
Use the DateTime object:
$dateTime = new DateTime('2016/01/01');
To get only parts of the date you can use the format method:
echo $dateTime->format('Y'); // it will display 2016
If you need to create it from the format you wrote in the question, then you can use the factory method createFromFormat:
$dateTime = DateTime::createFromFormat('d/m/Y', '01/01/2016');
echo $dateTime->format('Y/m/d');
This is work for me
$date = '20/May/2015:14:00:01';
$dateInfo = date_parse_from_format('d/M/Y:H:i:s', $date);
$unixTimestamp = mktime(
$dateInfo['hour'], $dateInfo['minute'], $dateInfo['second'],
$dateInfo['month'], $dateInfo['day'], $dateInfo['year'],
$dateInfo['is_dst']
);
this is what you are looking for http://php.net/manual/en/class.datetime.php
You can use $myDate = new DateTime('01/01/2016'); to declare date. To get year, month and date from the specified date, use echo $myDate->format('d m Y');
Change the format based on your need. To know more about date format refer
How to get current date in codeigniter in YY-mm-dd format. I wants to get current date in YY-mm-dd frmat and put this value into input text box
You can use the PHP date function.
date('Y-m-d');
Up to my knowledge, there is no separate date function in codeigniter.
EDIT :
But if you want date in this format 13-04-05 [ yy-mm-dd ], Try this
date('y-m-d');
For more date formats, check this link PHP Date Formats
Try to use this is a generic format of DateTime
echo date('Y-m-d H:i:s');
use php date function
echo date("Y-m-d");
will give you the result
What about:
$date = new \Datetime('now');
var_dump($date);
if you want the full date:
echo date('Y-m-d');
depends your date structure.
echo date('d-m-Y');
if you want year only, then echo date('Y'); is enough
Use php date() function, like this
echo Date('Y/m/d');
it give you the desired result!
I am trying to format a datetime variable with the following code:
$passed_time = $stu_quiz->c_date_time;
$passed_time_string = date_format($passed_time, 'M-d-Y');
For some reason, if I print $passed_time_string, the output is blank, but if I print out $passed_time, I get the date (in the format 2011-06-15 21:43:09).
Why is the date_format method not working?
The date_format function expects a "DateTime" object that is created using date_create.
Example:
$passed_time = date_create($stu_quiz->c_date_time);
$passed_time_string = date_format($passed_time, 'M-d-Y');
You are looking for just date()
http://php.net/manual/en/function.date.php
If you don't have PHP 5.3 and cannot use the DateTime class, try this:
$passed_time_string = date("M-d-Y", strtotime($passed_time));
First it converts your original MySQL time to a unix timestamp, then formats it as M-d-Y
I have a date in this format:
24-12-2010 // DAY - MONTH - YEAR
I need to get it in this format:
1995-12-31T23:59:59.999Z // The Z is for the TimeZone I think.
Check this link out:
http://lucene.apache.org/solr/api/org/apache/solr/schema/DateField.html
The above link is the way I need the date.
I am using PHP now, so this needs to be with PHP.
How can I convert these dates the easiest way?
Thanks
That is an ISO8601 format date; the following is what you want.
gmdate('Y-m-d\TH:i:s\Z', strtotime($date_value));
You can do something like that:
$dateTime = new DateTime($myDate);
$formatted = $dateTime->format("Y-m-d\TH:i:s.z\Z");
The mentioned solution with:
$dateTime->format(DateTime::W3C);
$dateTime->format(DateTime::ISO8601);
does return strings like:
2012-11-28T17:21:11+0100
which cannot be parsed, at least with newer Solr versions.
I wouldn't use gmdate if you need to support timezones. The DateTime implementation is well done, and is also available for functional programming.
http://php.net/manual/en/class.datetime.php
http://php.net/manual/en/ref.datetime.php
You can use the DateTime class
$dateTime = new DateTime();
$dateTime.setDate(24, 12, 2010);
$output = $dateTime.format(DateTime::W3C);
// Output now is your date in W3C format.
use the date ( string $format [, int $timestamp ] ) function of php!
In second paramter use http://php.net/manual/en/function.strtotime.php to get the timestamp from strings
$date = strtotime('24-12-2010');
$new_date = gmDate("Y-m-d\TH:i:s.z\Z",$date);