I was doing this code for my project and it seems that I can't get the values of the query into $currentRow. All that saved into the variable $currentrow is 22 which is the number rows in the database. I want to have access to all the query results. Please help. Here's the code.
public function getBSIConfig(){
$conn = oci_connect("472proj","system","//localhost/XE");
$sql = oci_parse($conn,"SELECT conf_id, conf_key, conf_value FROM bsi_configure");
oci_execute($sql);
echo "0";
while($currentRow = oci_fetch_all($sql,$res)){
echo "1.5";
echo $currentRow;
if($currentRow["conf_key"]){
echo "1";
if($currentRow["conf_value"]){
$this->config[trim($currentRow["conf_key"])] = trim($currentRow["conf_value"]);
echo "2";
}else{
$this->config[trim($currentRow["conf_key"])] = false;
echo "3";
}
}
}
}
And the output is only:
0
1.5
22
The results from this function are stored in the 2nd argument, rather than returned directly. See if this works for you:
$results = array();
$numResults = oci_fetch_all($sql, $results);
foreach ($results as $result) {
if ($result["conf_key"]) {
// etc ...
}
}
Read this http://php.net/manual/en/function.oci-fetch-all.php , you might get an idea what's wrong.
Related
Im writing a page in HTML/PHP that connects to a Marina Database(boats,owners etc...) that takes a boat name chosen from a drop down list and then displays all the service that boat has had done on it.
here is my relevant code...
if(isset($_POST['form1'])){//if there was input data submitted
$form1 = $_POST['form1'];
$sql1 = 'select Status from ServiceRequest,MarinaSlip where MarinaSlip.SlipID = ServiceRequest.SlipID and BoatName = "'.$form1.'"';
$form1 = null;
$result1 = $conn->query($sql1);
$test = 0;
while ($row = mysqli_fetch_array($result1, MYSQLI_ASSOC)) {
$values1[] = array(
'Status' => $row['Status']
);
$test = 1;
}
echo '<p>Service Done:</p><ol>';
if($test = 1){
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
echo '</ol>';
}else{
echo 'No service Done';
}
the issue im having is that some of the descriptions of sevice are simply Open which i do not want displayed as service done, or there is no service completed at all, which throws undefined variable: values1
how would I stop my script from adding Open to the values1 array and display a message that no work has been completed if values1 is empty?
Try this
$arr = array();
if (empty($arr))
{
echo'empty array';
}
We often use empty($array_name) to check whether it is empty or not
<?php
if(!empty($array_name))
{
//not empty
}
else
{
//empty
}
there is also another way we can double sure about is using count() function
if(count($array_name) > 0)
{
//not empty
}
else
{
//empty
}
?>
To make sure an array is empty you can use count() and empty() both. but count() is slightly slower than empty().count() returns the number of element present in an array.
$arr=array();
if(count($arr)==0){
//your code here
}
try this
if(isset($array_name) && !empty($array_name))
{
//not empty
}
You can try this-
if (empty($somelist)) {
// list is empty.
}
I often use empty（$arr) to do it.
Try this instead:
if (!$values1) {
echo "No work has been completed";
} else {
//Do staffs here
}
I think what you need is to check if $values1 exists so try using isset() to do that and there is no need to use the $test var:
if(isset($values1))
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
Or try to define $values1 before the while:
$values1 = array();
then check if it's not empty:
if($values1 != '')
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
All you have to do is get the boolean value of
empty($array). It will return false if the array is empty.
You could use empty($varName) for multiple uses.
For more reference : http://php.net/manual/en/function.empty.php
I have a loop which displays the wanted rows but I also want each row to be stored in its own variable in php. I have a table that has an ID and an info column.
This displays the wanted ID and info:
if ($info = $stmnt2->fetch()) {
do {
echo "$info[id] . $info[info] </br> ";
} while ($info = $stmnt2->fetch());
} else {
echo "<p>No Info</p>";
}
I want each row to have its own variable so I can manipulate the data later down the line. Like the first row will be stored in a php variable called $one and the second row in $second.
How can I do this?
I wouldn't use a variable to solve this! Take an array instead:
$rows = [];
if ($info = $stmnt2->fetch()) {
do {
$rows[] = $info;
echo $info['id'].$info['info']."</br>";
} while ($info = $stmnt2->fetch());
} else {
echo "<p>No Info</p>";
}
if (!empty($rows)) {
//you can change the values of the rows like the following.
$rows[0]['id'] = 1; // The ID of the first row!
$rows[0]['info'] = 'Some Info'; // The info of the first row!
$rows[1]['id'] = 2; // The ID of the second row!
$rows[1]['info'] = 'Some Info'; // The info of the second row!
//...
}
With the above example each item on rows is one row ($rows[number_of_row - 1]).
Hint: $info[id] and $info[info] isn't valid. You have to replace these with $info['id'] and $info['info']!
Just add $info to an Array:
if ($info = $stmnt->fetch()) {
$array = [];
do {
echo "$info[id] . $info[info] </br> ";
$array[] = $info;
} while ($info = $stmnt2->fetch());
} else {
echo "<p>No Info</p>";
}
// Do stuff with all rows
if ($info = $stmnt2->fetch()) {
$array=[];
do {
$array[$info['id']][]=$info; //the array index will be the same as id from the db
echo "$info[id] . $info[info] </br> ";
} while ($info = $stmnt2->fetch());
} else {
echo "<p>No Info</p>";
}
The array index will be same as the id in the DB.
To Retrieve the content use
$array[1]['info'] //will retrieve content id id = 1
$mysqli = new mysqli('localhost','root','','yourdb');
if($resultobj=$mysqli->query("select * from yourtable limit 4")){
list($one,$two,$three,$four)=$resultobj->fetch_all();
}
print_r($one);
I'm trying to return a value to an android application in JSON format using a web service. For some reason, my code is only returning "Invalid login, please try again". I'm positive that the username is being entered, and I'm positive the tasks are returning properly. Using test code, which I've included as commented lines, I verify that the service will return one set of data to the application. It appears that the problem is with my foreach loop, but I don't see how. It's pretty simple stuff. Obviously it isn't iterating, or my count would be increasing and I wouldn't receive the Invalid Login error. The only thing I can figure is that I would need to use a nest foreach loop, but I haven't had much success with that, either.
Thanks in advance for the help, guys!
Here is the foreach loop...
//for reach task returned, add to array for later output
foreach ($row2['Description'] as $t)
{
$taskDisplay = array('task' => $t);
$taskCount++;
}
and the count...
if ($taskCount > 0)
{
echo json_encode($taskDisplay);
}
else
{
echo "Invalid login, please try again";
}
here is the code in full
$taskDisplay = array();
$taskCount = 0;
//do this portion if app gives key value "PART_ONE"
if ($result['part'] == "PART_ONE")
{
//if username was entered, check user credentials
if(array_key_exists('user', $result)) {
$usercheck = $con->prepare("Select * from Employee
Where usr = ?
and pass = ?");
$usercheck -> execute(array($result['user'], $result['password']));
$row = $usercheck -> fetch();
//if username was verified, select tasks from database
if($row['usr'])
{
$task = $con->prepare("Select * from Tasks
where Assigned_Employee = ?");
$task -> execute(array($result['user']));
$row2 = $task -> fetch();
$statusCode = "Success";
//$taskDisplay = $row2['Description'];
//for reach task returned, add to array for later output
foreach ($row2['Description'] as $t)
{
$taskDisplay = array('task' => $t);
$taskCount++;
}
}
else
{
$statusCode = "Fail";
//bail if invalid username entered
exit;
}
//$arr = array('task' => $taskDisplay, 'status_code' => $statusCode);
//echo json_encode($arr);
if ($taskCount > 0)
{
echo json_encode($taskDisplay);
}
else
{
echo "Invalid login, please try again";
}
}
}
To foreach over all rows you'll want fetchAll(). Then you want to access the Description column in each row:
$row2 = $task->fetchAll();
// etc...
foreach ($row2 as $t)
{
$taskDisplay[] = array('task' => $t['Description']);
$taskCount++;
}
I am trying to GET different rows from different columns in php/mysql, and pack them into an array. I am able to successfully GET a jason encoded array back IF all values in the GET string match. However, if there is no match, the code echos 'no match', and without the array. I know this is because of the way my code is formatted. What I would like help figuring out, is how to format my code so that it just displays "null" in the array for the match it couldn't find.
Here is my code:
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode($fbaddra);
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['addr'];
} else {
$fbaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['addr'];
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
UPDATE: The GET Request
I would like the GET request below to return the full array, with whatever value that didn't match as 'null' inside the array.
domain.com/api/core/engine.php?a=fbaddra&facebook=username&facebookp=pagename
The GET above currently returns null.
Requests that work:
domain.com/api/core/engine.php?a=fbaddra&facebook=username or domain.com/api/core/engine.php?a=fbaddra&facebookp=pagename
These requests return the full array with the values that match, or null for the values that don't.
TL;DR
I need assistance figuring out how to format code to give back the full array with a value of 'null' for no match found in a row.
rather than assigning as 'null' assign null. Your full code as follows :
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode('no match');
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
You can even leave else part altogether.
Check your code in this fragment you not use same names for variables:
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = 'null';
}
$fbaddr not is same as $fpaddr, this assign wrong result to if statement.
It was the mysql query that was the problem.
For those who come across this, and need something similar, you'll need to format your query like this:
** MYSQL QUERY **
if ($_GET['PUTVALUEHERE']) {
$g = $_GET['PUTVALUEHERE'];
$gq = $mysqli->real_escape_string($g);
$q1 = "SELECT * FROM `addrbook` WHERE `facebookp` = '".$gq."' OR `facebook` = '".$gq."'";
}
** PHP CODE **
if($_GET['PUTVALUEHERE']{
echo json_encode($row['addr']);
}
So I have a query that I am returning all of the items into a mysql_fetch_array. Now, I know I could write another query and just select the items I need into a seperate query but, is there a way to just filter from the larger query what I want dependent on $_GET?
So, in english the user comes from a hyperlink that has ?id=1 and I peform a while that gets the all the values but, only display the $_GET['id'] items in a list
<?php //give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result) {
$id = $rowvideo["id"];
$title = $rowvideo["title"];
$length = $rowvideo["length"];
}
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
?>
Hope this makes sense. Thank you all.
If you do not want a second query to get just what you need, a simple-if-statement in your loop should work:
<?php
$getId = isset($_GET['id']) ? $_GET['id'] : false;
//give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result)) {
$id = $row["id"];
$title = $row["title"];
$length = $row["length"];
if ($id == $getId) {
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
}
}
?>
Note that I declared $getId outside of the loop to prevent having to use isset() during every iteration. If you don't verify if it's set and attempt to use it it will throw an undefined index warning - assuming you have error_reporting turned on (with that level enabled).
Alternatively, you could use PHP's array_filter() on the data after you've parsed it all:
$results = array();
while ($row = mysql_fetch_array($result)) $results[] = $row;
if (isset($_GET['id'])) {
$filtered = array_filter($results, function($element) use ($_GET['id']) { return ($element['id'] == $_GET['id']); });
$results = $filtered;
}
foreach ($results as $result) {
echo("<li><a href='#'>". $result['title']." " .$result['length']. "</a></li>");
}
My personal opinion would be to be more efficient and write the second query though, assuming of course you don't actually need all of the results when an id is specified. It would be as simple as:
if (isset($_GET['id']) && is_numeric($_GET['id'])) {
$query = 'SELECT id, title, length FROM table WHERE id=' . (int)$_GET['id'];
} else {
$query = 'SELECT id, title, length FROM table';
}
// your existing code as-is
A little more clarity here:
This will allow the filter by id in the url by specifying id=xxx, IF xxx is an integer that is positive. So id of 'bob' or -1 will not filter the results still giving all results
$filter=false;
if(isset($_GET['id']))
{
$filter_id=intval($_GET['id']);
if($id>0) $filter=true;
}
while($row = mysql_fetch_array($result))
{
if( (!$filter) || ( ($filter) && ($filter_id==$row['id']) ) )
{
$id = $row["id"];
$title = $row["title"];
$length = $row["length"];
// do other stuff here
}
}
I also changed $rowvideo to $row as this is the array you used to fetch the results.
<?php //give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result)) {
$id = $rowvideo["id"];
$title = $rowvideo["title"];
$length = $rowvideo["length"];
if ($id == $_GET['id']) { // or even ===
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
}
}
?>