I've been looking all over for the solution to this problem, but everything I try always returns the same error.
Fatal error: Cannot use object of type stdClass as array
This is the JSON resource I'm trying to access with PHP cURL:
https://www.easports.com/iframe/fifa16proclubs/api/platforms/PS4/clubs/36881/members
The issue I'm having is accessing the raw array. I've had success using the following code with objects, but I always have trouble when there is an array involved.
$phpObj = json_decode($json);
if (!is_null($phpObj->raw))
{
$object = $phpObj->raw;
foreach ($object as $obj)
{
echo "<tr id='clubs-search-result'><td class='club-search-name'>" . $obj->name . "</td><td class='blaze-id hidden'>" . $obj->blazeId . "</td><td><button type='button' class='form-button players-search-button red-bg'>Select</button></td></tr>";
}
}
I know that this is not the correct way to access an array, which is what I need help with. I want to be able to access the raw array and then iterate through all the objects inside the array. I've looked at many code examples but nothing seems to be working for my scenario.
The above code works with this resource:
http://www.easports.com/iframe/fifa16proclubs/api/platforms/PS4/clubsComplete/United
Only because I'm accessing nested objects and there are no arrays [] involved.
Any help would be appreciated. Thanks!
It appears the foreach loop needs to run on the first (and only) array in $phpObj->raw.
You need to change the foreach to:
foreach ($object[0] as $obj)
Related
I'm having some problems getting the data through my PHP loop.
<?php
$url = 'https://www.fibalivestats.com/data/1653309/data.json';
$content = file_get_contents($url);
$json = json_decode($content, true);
?>
<?php
foreach($json['totallds']['sPoints'] as $item); {
echo $item;
}
?>
The error I'm getting is an array to string conversion error. What I'm trying to get is the data from the sPoints array that will give me a Top 5 points scorers for a basketball game.
I'll build a table for this in HTML later but for now, it's not displaying the data at all and I'm getting errors. I feel like I may have confused arrays and strings too. Any thoughts about what I'm doing wrong? JSON file can be found in the $url variable.
Also if it helps, here's the link to where I have gotten the data from and what context the Top 5 is from https://www.fibalivestats.com/u/NSS/1653309/lds.html
Thanks!
Your $item is an array, so you can't just echo it like that. You can, however, echo its columns, for example:
foreach($json['totallds']['sPoints'] as $item) {
echo $item['firstName'] . ' ' . $item['familyName'];
}
Notice the removed semicolon between the foreach () and {.
Well, array to string conversion error means you're trying to echo an array.
If you see the return of the url you are looking at, you can verify that the "sPoints" key returns an array with several objects.
Try to change echo to print_r or var_dump to view entire data or complete your business logic.
Try changing:
echo $item;
to:
var_dump($item);
I know others have already asked about this, but I don't find a solution for my problem. In my PHP page I call an external service and I can't modify the response obtained.
I'm moving my first steps both with JSON and PHP.
The response is a JSON like this, I print this using the var_dump method:
object(stdClass)#1 (3)
{
["search_string"]=>string(15) "ABCDEFG HI LMNO"
["resut"]=>string(5) "apixi"
["0"]=>array(1){
[0]=>object(stdClass)#2(2){
["resp_code"]=>string(7) "12.34.0"
["resp_description"]=>string(15) "ABCDEFG HI LMNO"
}
}
}
In my PHP page I can read the value ”ABCDEFG HI LMNO” for the key "search_string" with this code, in the $output variable I store the result of the cUrl call
.......
$output = curl_exec($ch);
$jsonDecode =json_decode(str_replace('""','"',$output));
var_dump($jsonDecode);
echo $jsonDecode -> search_string;
I need the str_replace method because the JSON is dirty but not always, how can I access at the fields "resp_code" and "resp_description" and then store them in a variable? I tried many solutions but none works for me.
Instead of converting JSON array to stdClass object you can also convert it to regular PHP array by adding second parameter to the json_decode function:
$jsonDecode =json_decode(str_replace('""','"',$output), true);
In your case in the output, you'll get a multidimensional array.
Then, to access resp_code and resp_description, you can do something like this:
$respCode = $jsonDecode[0]["resp_code"];
$respDescription = $jsonDecode[0]["resp_description"];
In the decoded JSON you have, the resp_code and resp_description keys are difficult to get to, because the top-level object has a numerical ("0") attribute. Trying to reach that attribute like this:
$jsonDecode -> 0
will give this parsing error:
syntax error, unexpected '0' (T_LNUMBER), expecting identifier (T_STRING) or variable (T_VARIABLE) or '{' or '$'
Trying the same with a string notation (-> "0") also fails.
However, the suggestion in the error message is useful: encapsulate the zero with braces. Then you can proceed easily by adding the array index selector ([0]) to get to the object and keys of your interest, like this:
echo $jsonDecode->{0}[0]->resp_code;
echo $jsonDecode->{0}[0]->resp_description;
If you expect more elements in that array $jsonDecode->{0}, then loop over them like this:
foreach ($jsonDecode->{0} as $element) {
echo $element->resp_code;
echo $element->resp_description;
}
Alternative
If, however, you prefer to work with associative arrays instead of objects, you can use the second argument of json_encode as stated in the docs:
assoc
When TRUE, returned objects will be converted into associative arrays.
So then you would pass true as second argument:
$jsonDecode = json_decode(str_replace('""', '"', $output), true);
The above code would then be rewritten like this to access the variable as an associative array:
foreach ($jsonDecode[0] as $element) {
echo $element["resp_code"];
echo $element["resp_description"];
}
$str = file_get_contents('http://uapi.alidays.it/service/2.0.0/rs/alidays/applications/fluidtravel/public/baskets/5660609ee4b0ab55863d6c42/contents/selected');
$json =json_decode($str,true);
echo '<pre>' . print_r($json,true) . '</pre>';
foreach($json['data'] as $item['value']['baskettile']) {
echo $item['value']['baskettile']['type'];
echo '<br>';
}
i tried to access the data like this but it says Warning: Invalid argument supplied for foreach()
The value of baskettile is an object with properties like type and status.
It is not an array. It doesn't make sense to iterate over it with foreach(... in ...).
Just access the values directly.
$json['data']['0']['value']['baskettile']['type']
You need to debug your code. Chances are $item is not what you think it is.
The quickest way is to do a var_dump($item) in your foreach. From there you will see that the variable either is not an array or the key does not exist.
{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}
I am trying to fetch description from the weather from the json above but getting errors in php. I have tried the below php code:
$jsonDecode = json_decode($contents, true);
$result=array();
foreach($jsonDecode as $data)
{
foreach($data{'weather'} as $data2)
{
echo $data2{'description'};
}
}
Any help is appreciated. I am new in using json.
You have to use square brackets ([]) for accessing array elements, not curly ones ({}).
Thus, your code should be changed to reflect these changes:
foreach($data['weather'] as $data2)
{
echo $data2['description'];
}
Also, your outer foreach loop will cause your code to do something completely different than you intend, you should just do this:
foreach($jsonDecode['weather'] as $data2)
{
echo $data2['description'];
}
Your $jsonDecode seems to be an array, so this should work-
foreach($jsonDecode['weather'] as $data)
{
echo $data['description'];
}
You can access data directly with scopes
$json = '{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}';
$jsonDecode = json_decode($json, true);
echo $jsonDecode['weather'][0]['description'];
//output Sky is Clear
As you can see wheater` is surrounded with scopes so that means it is another array. You can loop throw that array if you have more than one result
foreach($jsonDecode['weather'] as $weather)
{
echo $weather['description'];
}
Live demo
If the result of decode is an array, use:
$data['weather']
If the result is an object, use:
$data->weather
you have to access "weather" with "[]" operator
like this,
$data["weather"]
There is several things worth answering in your question:
Q: What's the difference between json_decode($data) and json_decode($data, true)?
A: The former converts JSON object to a PHP object, the latter creates an associative array: http://uk1.php.net/json_decode
In either case, there is no point on iterating over the result. You probably want to access just the 'weather' field:
$o = json_decode($data) => use $weather = $o->weather
$a = json_decode($data, true) => use $weather = $a['weather']
Once you have the 'weather' field, look carefully what it is:
"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}]
It's an array, containing a single object. That means you will either need to iterate over it, or use $clearSky = $weather[0]. In this case, it does not matter which approach of json_decode did you choose => JSON array is always decoded to a PHP (numeric indexed) array.
But, once you get $clearSky, you are accessing the object and it again matters, which approach you chose - use arrow or brackets, similarly to the first step.
So, the correct way to get for exaple the weather description would be either of these:
json_decode($data)->weather[0]->description
json_decode($data, true)['weather'][0]['description']
Note: In the latter case, dereferencing result of the function call is supported only in PHP 5.4 or newer. In PHP 5.3 or older, you have to create a variable.
Note: I also encourage you to always check if the expected fields are actually set in the result, using isset. Otherwise you will try to access undefined field, which raises an error.
I'm trying to decode the following JSON using php json_decode function.
[{"total_count":17}]
I think the square brackets in output is preventing it. How do I get around that? I can't control the output because it is coming from Facebook FQL query:
https://api.facebook.com/method/fql.query?format=json&query=SELECT%20total_count%20FROM%20link_stat%20WHERE%20url=%22http://www.apple.com%22
PHP's json_decode returns an instance of stdClass by default.
For you, it's probably easier to deal with array. You can force PHP to return arrays, as a second parameter to json_decode:
$var = json_decode('[{"total_count":17}]', true);
After that, you can access the variable as $result[0]['total_count']
See this JS fiddle for an example of how to read it:
http://jsfiddle.net/8V4qP/1
It's basically the same code for PHP, except you need to pass true as your second argument to json_decode to tell php you want to use it as associative arrays instead of actual objects:
<?php
$result = json_decode('[{"total_count":17}]', true);
print $result[0]['total_count'];
?>
if you don't pass true, you would have to access it like this: $result[0]->total_count because it is an array containing an object, not an array containing an array.
$json = "[{\"total_count\":17}]";
$arr = Jason_decode($json);
foreach ($arr as $obj) {
echo $obj->total_count . "<br>";
}
Or use json_decode($json, true) if you want associative arrays instead of objects.