I'm having some problems getting the data through my PHP loop.
<?php
$url = 'https://www.fibalivestats.com/data/1653309/data.json';
$content = file_get_contents($url);
$json = json_decode($content, true);
?>
<?php
foreach($json['totallds']['sPoints'] as $item); {
echo $item;
}
?>
The error I'm getting is an array to string conversion error. What I'm trying to get is the data from the sPoints array that will give me a Top 5 points scorers for a basketball game.
I'll build a table for this in HTML later but for now, it's not displaying the data at all and I'm getting errors. I feel like I may have confused arrays and strings too. Any thoughts about what I'm doing wrong? JSON file can be found in the $url variable.
Also if it helps, here's the link to where I have gotten the data from and what context the Top 5 is from https://www.fibalivestats.com/u/NSS/1653309/lds.html
Thanks!
Your $item is an array, so you can't just echo it like that. You can, however, echo its columns, for example:
foreach($json['totallds']['sPoints'] as $item) {
echo $item['firstName'] . ' ' . $item['familyName'];
}
Notice the removed semicolon between the foreach () and {.
Well, array to string conversion error means you're trying to echo an array.
If you see the return of the url you are looking at, you can verify that the "sPoints" key returns an array with several objects.
Try to change echo to print_r or var_dump to view entire data or complete your business logic.
Try changing:
echo $item;
to:
var_dump($item);
Related
For some strange reason I can't change the following JSON to a PHP array:
{"sides0":{"name_nl":"Voorkant100","name":"Frontside100","template_overlay":""},"sides1":{"name_nl":"Achterkant100","name":"Backside100","template_overlay":"1"}}
I've validated the json and it's valid.
First I post $product['sides'] to my page, containing:
"{\"sides0\":{\"name_nl\":\"Voorkant100\",\"name\":\"Frontside100\",\"template_overlay\":\"\"},\"sides1\":{\"name_nl\":\"Achterkant100\",\"name\":\"Backside100\",\"template_overlay\":\"1\"}}"
Then I use json_decode on it like this:
$sidearr = json_decode($product['sides'], true);
If I then do:
echo '<pre>';
print_r($sidearr);
echo '</pre>';
It prints the first part of my question.
Now I want to loop over it, but even this test shows nothing:
foreach($sidearr as $side){
echo 'test';
}
I tried testing if it even is an array with:
echo is_array($sidearr) ? 'Array' : 'not an Array';
echo "\n";
And it shows me that it is not an array. Why is that? I always thought using json_decode on a json string and add true inside the function turns it into a PHP array.
It prints the first part of my question.
Because $sidearr is a string now, decode it again, you'll get an array.
$sidearr = json_decode($sidearr, true);
I have the url http://pubapi.cryptsy.com/api.php?method=singleorderdata&marketid=132 which leads to an array.
I want to get the value of the first 'sellorders' which in this case is: 0.00000048 and store it in the variable $sellorderprice.
Can anyone help?
Thanks.
Just access the url contents thru file_get_contents. Your page actually return a JSON string, to get those values into meaningful data, decode it thru json_decode, after that access the data needed accordingly:
$url = 'http://pubapi.cryptsy.com/api.php?method=singleorderdata&marketid=132';
$data = json_decode(file_get_contents($url), true);
$sellorderprice = $data['return']['DOGE']['sellorders'][0]['price'];
echo $sellorderprice;
That code actually points directly to index zero 0 which gets the first price. If you need to get all items an just simply echo them all you need to iterate all items thru foreach:
foreach($data['return']['DOGE']['sellorders'] as $sellorders) {
echo $sellorders['price'], '<br/>';
}
Its simple, you just have to decode json like this:
$json = file_get_contents("http://pubapi.cryptsy.com/api.php?method=singleorderdata&marketid=132");
$arr = json_decode($json, true);
$sellorderprice = $arr['return']['DOGE']['sellorders'][0]['price'];
below is my 'script.json' file with json array and i want the values of webUserid and webPassword
{
"totalSize":2,
"webUserId":"abc",
"webPassword":"def",
"operation":"send",
"testMode":true,
"records":[
{
"phoneNumber":"1908908399",
"message":"Happy Birthday",
"Id":"a0YL0000008QYunMAG",
"deviceId":"ABCDEFXABCDEF"
}
]
}
I tried below one but not getting the result
<?php
$jsonString=file_get_contents("script.json");
$decoded=json_decode($jsonString,true);
foreach($decoded->data as $name){
echo $name->totalSize;
}
?>
Zarif, try the below code, its working 100%......... :)
<?php
$jsonString=file_get_contents("script.json");
$decoded=array(json_decode($jsonString,true));
foreach($decoded as $name){
echo $name['totalSize'];
}
?>
There's no need for a foreach loop in your current example, as you only have one level.
Your main problem is you're trying to use the result of your json_decode as an object when you've previously stated you want the result as an associative array.
The 2nd param of json_decode specifies what format the return value is in, so as you've done
$decoded = json_decode($jsonString, true);
you'll receive an array, which you could access like
echo $decoded['totalSize'];
if you wanted to treat it as on object as you've done in your question, either state false or omit a 2nd param in json_decode (it's false by default anyway), and that'll let you do what you're trying to do:
$decoded = json_decode($jsonString);
$decoded->totalSize;
lets say that
$myJSON = yourPostedJSON.
$myJSON = json_decode($myJSON, true);
echo $myJSON['webUserId'];
echo $myJSON['webPassword'];
{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}
I am trying to fetch description from the weather from the json above but getting errors in php. I have tried the below php code:
$jsonDecode = json_decode($contents, true);
$result=array();
foreach($jsonDecode as $data)
{
foreach($data{'weather'} as $data2)
{
echo $data2{'description'};
}
}
Any help is appreciated. I am new in using json.
You have to use square brackets ([]) for accessing array elements, not curly ones ({}).
Thus, your code should be changed to reflect these changes:
foreach($data['weather'] as $data2)
{
echo $data2['description'];
}
Also, your outer foreach loop will cause your code to do something completely different than you intend, you should just do this:
foreach($jsonDecode['weather'] as $data2)
{
echo $data2['description'];
}
Your $jsonDecode seems to be an array, so this should work-
foreach($jsonDecode['weather'] as $data)
{
echo $data['description'];
}
You can access data directly with scopes
$json = '{"coord":{"lon":73.69,"lat":17.8},"sys":{"message":0.109,"country":"IN","sunrise":1393032482,"sunset":1393074559},"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}],"base":"cmc stations","main":{"temp":293.999,"temp_min":293.999,"temp_max":293.999,"pressure":962.38,"sea_level":1025.86,"grnd_level":962.38,"humidity":78},"wind":{"speed":1.15,"deg":275.503},"clouds":{"all":0},"dt":1393077388,"id":1264491,"name":"Mahabaleshwar","cod":200}';
$jsonDecode = json_decode($json, true);
echo $jsonDecode['weather'][0]['description'];
//output Sky is Clear
As you can see wheater` is surrounded with scopes so that means it is another array. You can loop throw that array if you have more than one result
foreach($jsonDecode['weather'] as $weather)
{
echo $weather['description'];
}
Live demo
If the result of decode is an array, use:
$data['weather']
If the result is an object, use:
$data->weather
you have to access "weather" with "[]" operator
like this,
$data["weather"]
There is several things worth answering in your question:
Q: What's the difference between json_decode($data) and json_decode($data, true)?
A: The former converts JSON object to a PHP object, the latter creates an associative array: http://uk1.php.net/json_decode
In either case, there is no point on iterating over the result. You probably want to access just the 'weather' field:
$o = json_decode($data) => use $weather = $o->weather
$a = json_decode($data, true) => use $weather = $a['weather']
Once you have the 'weather' field, look carefully what it is:
"weather":[{"id":800,"main":"Clear","description":"Sky is Clear","icon":"01n"}]
It's an array, containing a single object. That means you will either need to iterate over it, or use $clearSky = $weather[0]. In this case, it does not matter which approach of json_decode did you choose => JSON array is always decoded to a PHP (numeric indexed) array.
But, once you get $clearSky, you are accessing the object and it again matters, which approach you chose - use arrow or brackets, similarly to the first step.
So, the correct way to get for exaple the weather description would be either of these:
json_decode($data)->weather[0]->description
json_decode($data, true)['weather'][0]['description']
Note: In the latter case, dereferencing result of the function call is supported only in PHP 5.4 or newer. In PHP 5.3 or older, you have to create a variable.
Note: I also encourage you to always check if the expected fields are actually set in the result, using isset. Otherwise you will try to access undefined field, which raises an error.
I'm trying to get the "screenshotUrls" string from this piece of json:
$request_url = 'http://itunes.apple.com/search?term=ibooks&country=us&entity=software&limit=1';
$json = file_get_contents($request_url);
$decode = json_decode($json, true);
echo $decode['results'][0]['screenshotUrls'];
But I get only text "Array"
What have I done wrong?
Try
var_dump($decode['results'][0]['screenshotUrls']);
IF you get 'Array' output by PHP that means that you're trying to echo an actual array (or the string 'Array'...). That means you need to get a specific index value.
Since $decode['results']['0']['screenshotUrls'] is an array, if you want just a string (say, delimited by commas), you could use
echo implode(",", $decode['results']['0']['screenshotUrls']);
This will iterate over the array, and return a comma-separated string of all the URLs.
Do a var_dump($decode['results']['0']['screenshotUrls']). You'll find that the ['screenshotUrls'] is actually an Array, containing one or more URLs (hence the plural 'urls' in its name).
There's nothing wrong with your code so far, but $decode['results'][0]['screenshotUrls'] is an array of all the URLs to screenshots. To go through each one individualy, you need to do:
forearch ($decode['results'][0]['screenshotUrls'] as $url) {
// Do stuff here
}