FIFO calculation in php (mysql) - php

I have two data tables stock_incomes, stock_outcomes and stock_outcomes_fifo (the one I insert pre-calculated data):
stock_incomes (stores leftovers data)
id| Levtv
-----------
7 | 100
8 | 250
9 | 350
stock_outcomes (here is the point)
id| Quantity
--------------
1 | 150*
I have no problem when stock_outcomes.Quantity is less than 100 (min(Id) from stock_incomes, please see my code below) but I have no idea what code to write I could get calculations if outcome is >100. In my example I used 150 and I would like to get data in next table as:
stock_outcomes_fifo (the one I wish to insert pre-calculated data from the previous two tables)
id| IncomeId| OutcomeId| OutcomePart| Leftv
---------------------------------------------
1 | 7 | 1 | 100 | 0
2 | 8 | 1 | 50 | 200
Here is my code with question inside (see last part of the code):
<?php
include_once("config.inc.php");
include_once("db.class.php");
// stock_outcomes
$db = new db($host, $database, $user, $passwd);
$sql = "SELECT * FROM stock_outcomes WHERE Id = '1'";
$mas = $db->get_array($sql);
if($mas) {
foreach ($mas as $k => $v) {
$OutcomeId = $mas[$k]['Id'];
$OutcomeQuantity = $mas[$k]['Quantity'];
}
}
// stock_incomes
$sql = "select * from stock_incomes where Id = (select min(Id) from stock_incomes where Leftv > 0)";
$mas = $db->get_array($sql);
if($mas) {
foreach ($mas as $k => $v) {
$IncomeId = $mas[$k]['Id'];
$IncomeLeftv = $mas[$k]['Leftv'];
}
}
// insert into stock_outcomes_fifo
if ($OutcomeQuantity <= $IncomeLeftv) {
$OutcomePart = $OutcomeQuantity;
$FifoLeftv = $IncomeLeftv - $OutcomeQuantity;
mysql_query("INSERT INTO `stock_outcomes_fifo` (IncomeId,OutcomeId,OutcomePart,Leftv) VALUES ($IncomeId, $OutcomeId, $OutcomePart, $FifoLeftv)");
}
if ($OutcomeQuantity > $IncomeLeftv) {
// I have no idea what php function to use in this case... please give me direction, thank you...
}
?>

The question has been solved, here is the final working code in case someone might need it:
<?php
include_once("config.inc.php");
include_once("db.class.php");
// stock_outcomes
$db = new db($host, $database, $user, $passwd);
$sql = "SELECT * FROM stock_outcomes WHERE Id = '1'";
$mas = $db->get_array($sql);
if($mas){
foreach ($mas as $k=>$v) {
$OutcomeId=$mas[$k]['Id'];
$OutcomeBarCode=$mas[$k]['BarCode'];
$OutcomeQuantity=$mas[$k]['Quantity'];
}
}
/* - Start code */
if ($OutcomeQuantity > 0) {
$sql = "select * from stock_incomes where Leftv > 0 order by id asc";
$mas = $db->get_array($sql);
if ($mas) {
//filing stock_outcomes_fifo
foreach ($mas as $k=>$v) {
$IncomeId = $mas[$k]['Id'];
$IncomeQuantity = $mas[$k]['Quantity'];
$IncomeUnitPrice = $mas[$k]['UnitPrice'];
$IncomeLeftv = $mas[$k]['Leftv'];
$OutcomePart = min($OutcomeQuantity, $IncomeLeftv);
$FifoLeftv = $IncomeLeftv - $OutcomePart;
$FifoCost = $IncomeUnitPrice * $OutcomePart;
mysql_query("INSERT INTO `stock_outcomes_fifo` (BarCode,IncomeId,OutcomeId,OutcomePart,UnitPrice,Leftv,Cost) VALUES ($OutcomeBarCode, $IncomeId, $OutcomeId, $OutcomePart, $IncomeUnitPrice, $FifoLeftv, $FifoCost)");
mysql_query("UPDATE `stock_incomes` SET Leftv = ".$FifoLeftv." WHERE Id = ".$IncomeId);
$OutcomeQuantity -= $OutcomePart;
if ($OutcomeQuantity <= 0) break;
}
$OutcomeCostQuery = "select sum(Cost) as summ from stock_outcomes_fifo where OutcomeId = ".$OutcomeId."";
$OutcomeCost = mysql_query($OutcomeCostQuery);
$OutcomeCostResult = mysql_fetch_array($OutcomeCost);
mysql_query("UPDATE `stock_outcomes` SET Cost = ".$OutcomeCostResult["summ"]." WHERE Id = ".$OutcomeId."");
}
} /* - Finish code */
?>

Please help me let me explain with this.....
purchase table
id purchase_id product_id qty net_unit_cost created_at
-------------------------------------------------------------------------
1 1 1 10 10 2022-10-10
--------------------------------------------------------------------------
2 2 1 20 12 2022-10-10
Sale table
sale_id product_id qty net_unit_price created_at
1 1 11 15 2022-10-10
in this, if i sold '11' units then how can i subtract from the rows to get remaining units? i've to subtract '10' units from first row and '1' unit from second row...

Related

PHP Compare column values and edit database accordingly

I am a newbie to PHP and I am stuck at a certain point. I tried looking up a solution for it however, I didn't find exactly what I need.
My goal is to create a leaderboard, in which the values are displayed in descending order plus the rank and score are displayed. Furthermore, it should also display whether or not a tie is present.
The database should look like this:
+---------+------+----------------+-------+------+
| user_id | name | email | score | tied |
+---------+------+----------------+-------+------+
| 1 | SB | sb#gmail.com | 1 | 0 |
+---------+------+----------------+-------+------+
| 2 | AS | as#web.de | 2 | 0 |
+---------+------+----------------+-------+------+
| 3 | BR | br#yahoo.com | 5 | 1 |
+---------+------+----------------+-------+------+
| 4 | PJ | pj#gmail.com | 5 | 1 |
+---------+------+----------------+-------+------+
And the outputted table should look something like this:
+------+-------------+-------+------+
| rank | participant | score | tied |
+------+-------------+-------+------+
| 1 | BR | 5 | Yes |
+------+-------------+-------+------+
| 2 | PJ | 5 | Yes |
+------+-------------+-------+------+
| 3 | AS | 2 | No |
+------+-------------+-------+------+
| 4 | SB | 1 | No |
+------+-------------+-------+------+
I managed to display the rank, participant and the score in the right order. However, I can't bring the tied column to work in the way I want it to. It should change the value, whenever two rows (don't) have the same value.
The table is constructed by creating the <table> and the <thead> in usual html but the <tbody> is created by requiring a php file that creates the table content dynamically.
As one can see in the createTable code I tried to solve this problem by comparing the current row to the previous one. However, this approach only ended in me getting a syntax error. My thought on that would be that I cannot use a php variable in a SQL Query, moreover my knowledge doesn't exceed far enough to fix the problem myself. I didn't find a solution for that by researching as well.
My other concern with that approach would be that it doesn't check all values against all values. It only checks one to the previous one, so it doesn't compare the first one with the third one for example.
My question would be how I could accomplish the task with my approach or, if my approach was completely wrong, how I could come to a solution on another route.
index.php
<table class="table table-hover" id="test">
<thead>
<tr>
<th>Rank</th>
<th>Participant</th>
<th>Score</th>
<th>Tied</th>
</tr>
</thead>
<tbody>
<?php
require("./php/createTable.php");
?>
</tbody>
</table>
createTable.php
<?php
// Connection
$conn = new mysqli('localhost', 'root', '', 'ax');
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// SQL Query
$sql = "SELECT * FROM names ORDER BY score DESC";
$result = $conn->query("$sql");
// Initalizing of variables
$count = 1;
$previous = '';
while($row = mysqli_fetch_array($result)) {
$current = $row['score'];
$index = $result['user_id']
if ($current == $previous) {
$update = "UPDATE names SET tied=0 WHERE user_id=$index";
$conn->query($update);
}
$previous = $current;
?>
<tr>
<td>
<?php
echo $count;
$count++;
?>
</td>
<td><?php echo $row['name'];?></td>
<td><?php echo $row['score'];?></td>
<td>
<?php
if ($row['tied'] == 0) {
echo 'No';
} else{
echo 'Yes';
}
?>
</td>
</tr>
<?php
}
?>
I think the problem is here
$index = $result['user_id'];
it should be
$index = $row['user_id'];
after updating tied you should retrieve it again from database
So I solved my question by myself, by coming up with a different approach.
First of all I deleted this part:
$current = $row['score'];
$index = $result['user_id']
if ($current == $previous) {
$update = "UPDATE names SET tied=0 WHERE user_id=$index";
$conn->query($update);
}
$previous = $current;
and the previous variable.
My new approach saves the whole table in a new array, gets the duplicate values with the array_count_values() method, proceeds to get the keys with the array_keys() method and updates the database via a SQL Query.
This is the code for the changed part:
// SQL Query
$sql = "SELECT * FROM names ORDER BY score DESC";
$result = $conn->query("$sql");
$query = "SELECT * FROM names ORDER BY score DESC";
$sol = $conn->query("$query");
// initalizing of variables
$count = 1;
$data = array();
// inputs table into an array
while($rows = mysqli_fetch_array($sol)) {
$data[$rows['user_id']] = $rows['score'];
}
// -- Tied Column Sort --
// counts duplicates
$cnt_array = array_count_values($data);
// sets true (1) or false (0) in helper-array ($dup)
$dup = array();
foreach($cnt_array as $key=>$val){
if($val == 1){
$dup[$key] = 0;
}
else{
$dup[$key] = 1;
}
}
// gets keys of duplicates (array_keys()) and updates database accordingly ($update query)
foreach($dup as $key => $val){
if ($val == 1) {
$temp = array_keys($data, $key);
foreach($temp as $k => $v){
$update = "UPDATE names SET tied=1 WHERE user_id=$v";
$conn->query($update);
}
} else{
$temp = array_keys($data, $k);
foreach($temp as $k => $v){
$update = "UPDATE names SET tied=0 WHERE user_id=$v";
$conn->query($update);
}
}
}
Thank you all for answering and helping me get to the solution.
instead of the update code you've got use something simular
$query = "select score, count(*) as c from names group by score having c > 1";
then you will have the scores which have a tie, update the records with these scores and your done. Make sure to set tie to 0 at first for all rows and then run this solution
UPDATE for an even faster solution sql based:
First reset the database:
$update = "UPDATE names SET tied=0";
$conn->query($update);
All records have a tied = 0 value now. Next update all the records which have a tie
$update = "update docs set tied = 1 where score IN (
select score from docs
group by score having count(*) > 1)";
$conn->query($update);
All records with a tie now have tied = 1 as we select all scores which have two or more records and update all the records with those scores.

Mysql count column issue

I can't figure-it out how to count all these dancers columns and echo with total of all dancers
id | dancer1 | dancer2 | dancer3 | dancer4, and so on..
---------------------------------------
1 alex michael dalm name
2 clare rose test
I have this for the start but is not working:
$counter = mysql_query("SELECT COUNT(*) AS id FROM table");
$num = mysql_fetch_array($counter);
$dancers = $num["id"];
echo "Total dancers: $dancers";
Any help is appreciated. Thanks!
Try this:
$counter = mysql_query("SELECT * FROM table");
$dancers = 0;
while($rows = mysql_fetch_array($counter)){
for($i = 1; $i <= 24; $i++){
$dan_id = 'dancer'.$i;
if($rows[$dan_id] != "" || $rows[$dan_id] != null )
$dancers++;
}
}
echo "Total dancers:". $dancers;
Note: Never design your database table like this.
I would actually save your dancers in a different (easier) way... For examle:
ID NAME SURNAME PHONE ....
1 Anna Brickstone 0975 ...
2 Jef Damen 0754 ...
That way you could use the following code to count tables:
$dancersCount="0";
$sql = "SELECT * FROM dancers";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$dancersCount++;
}
} else {
echo "No dancers..";
}
echo"$dancersCount";
The counter will count +1 each time it finds a row (dancer)
If you really want to do it that way...
Then I don't really think there's an easy way to fix this... You will probably need to check how many columns you have in your database but that's not something i can help you with...
You need to change your table structure:
id | dancerNumber | name
1 1 alex
2 1 clare
3 2 michael
4 2 rose
5 3 dalm
6 3 test
7 4 name
8 4 dana
SELECT COUNT(*) AS id FROM table will return 8 dancers. If this is what you were looking for?
if you want to keep your structure then you need to do the following sql query
SELECT dancer1,
dancer2,
dancer3,
(CASE WHEN (dancer1 <> "" AND dancer1 IS NOT NULL) THEN 1 ELSE 0 END +
CASE WHEN (dancer2 <> "" AND dancer2 IS NOT NULL) THEN 1 ELSE 0 END +
CASE WHEN (dancer3 <> "" AND dancer3 IS NOT NULL) THEN 1 ELSE 0 END) AS COUNTER
FROM table
This will count all the non empty and non null columns and add a counter at the end of the table. this counter will then contain the number of dancers with your structure.
Full answer with your php code
$query = 'SELECT (CASE WHEN (dancer1 <> "" AND dancer1 IS NOT NULL) THEN 1 ELSE 0 END +
CASE WHEN (dancer2 <> "" AND dancer2 IS NOT NULL) THEN 1 ELSE 0 END +
CASE WHEN (dancer3 <> "" AND dancer3 IS NOT NULL) THEN 1 ELSE 0 END) AS COUNTER
FROM table'
$counter = mysql_query($query);
$num = mysql_fetch_array($counter);
$dancers = $num["COUNTER"];
echo "Total dancers: $dancers";

Buy/Sell profit tracking via FIFO stack in PHP

I need to implement an algorythm that can keep track of profits for a list of individual item transactions and update the 'profit' table. The idea is to fetch items bought and cross-reference them with items sold, purely by order (i.e no individual instancing of individual items exists, there are only IDs for item types). So, say we have a table with this data:
items:
item id item type
1 red box
2 blue box
3 white box
transactions:
item id -- quantity -- transaction_type -- price_unit($) -- time
1 3 buy 20 2015-10-10
3 1 buy 10 2015-10-11
1 1 sell 25 2015-10-12
1 1 sell 20 2015-11-14
3 1 sell 15 2015-11-13
For this example my profit table should look like:
item_id -- quantity -- profit -- timestamp_bought ---timestamp_sold
1 1 (25-20)=5 2015-10-10 2015-10-12
1 1 (20-20)=0 2015-10-10 2015-11-14
3 1 (15-10)=5 2015-10-11 2015-11-13
This is what I have so far. It works until several different buy/sell quantities come into play...
$buy_list = mysqli_query($con, "SELECT * FROM transaction WHERE
transaction_type = 'Buy' ORDER BY time DESC");
$sell_list = mysqli_query($con, "SELECT * FROM transaction WHERE
transaction_type = 'Sell' ORDER BY time DESC");
while($row = mysqli_fetch_array($buy_list))
{
array_push($buy_stack, array(
$row['idtrans'],
$row['iditem'],
$row['quantity'],
$row['time'],
$row['price_unit']));
}
while($row = mysqli_fetch_array($sell_list))
{
array_push($sell_stack, array(
$row['idtrans'],
$row['iditem'],
$row['quantity'],
$row['time'],
$row['price_unit']));
}
$size_buy = sizeof($buy_stack);
$size_sell = sizeof($sell_stack);
for($i=0; $i<=$size_buy-1; $i++) //iterate BUY orders
{
$idtrans_b = $buy_stack[$i][0];
$itemid_b = $buy_stack[$i][1];
$quantity_b = $buy_stack[$i][2];
$time_b = $buy_stack[$i][3];
$price_unit_b = $buy_stack[$i][4];
$quantity_b_calc = $buy_stack[$i][2];
for($k=0; $k<=$size_sell-1; $k++)
{
$idtrans_s = $sell_stack[$k][0];
$itemid_s = $sell_stack[$k][1];
$quantity_s = $sell_stack[$k][2];
$time_s = $sell_stack[$k][3];
$price_unit_s = $sell_stack[$k][4];
if($itemid_s == $itemid_b &&
$time_s > $time_b &&
$quantity_b > 0
&& $quantity_s >= $quantity_b) //match
{
$sell_stack[$k][1] = "done_sell";
$buy_stack[$i][1] = "done_buy";
$profit_unit = $price_unit_s - $price_unit_b;
$profit_ quantity = min($quantity_s, $quantity_b);
$quantity_b = $quantity_b - $profit_quantity;
$time_bought = $buy_stack[$i][3];
$time_sold = $sell_stack[$k][3];
$add_profit = mysqli_query
($con, "INSERT INTO profit (id, transaction_buy, transaction_sell, profit_unit, quantity, timestamp_buy, timestamp_sell)
VALUES ( 'null', '$idtrans_b', '$idtrans_s', '$profit_unit', '$profit_quantity', $time_bought, $time_sold));
}
}
}
I'm stuck to get this working properly. Should I scrap this and do it with stacks instead?

Add rows together

I have one table with some rows and lot of columns (about 50)
- I don't want to list all the column names, co I use a while loop to go through the table and a foreach command to find the column names and values.
Now I would like to add these two rows into one row (where id is 1) and sum the values together...
id | col 1 | col 2 | ...
1 30 21
1 11 16
2 75 0
It should look like this
id | col1 | col2 | ...
1 41 37
2 75 0
This is what I have...
$query = mysql_query("SELECT * FROM `table` WHERE `id`='1'");
while ($row = mysql_fetch_assoc($query)) {
foreach($row as $key => $val) {
if($key != 'id') {
//the sum code...?
}
}
}
Could you please help me? Thank you a lot...
Based on your code which indicates you're using mysql I'm going to give you a mysql solution (which can easily be ported to most RDBMS). What you're looking for can easily be accomplished with aggregate functions. Follow the link to read about all the aggregate functions mysql has.
SELECT id, SUM(col1), SUM(col2) FROM table GROUP BY id;
just sum the results in mysql.. databases are made to handle things like this so it'll be a faster solution than doing it just in php.
SELECT
id,
SUM(col1),
SUM(col2)
FROM table
GROUP BY id;
Try this: See the Explanation as comments:
<?php
$query = mysql_query("SELECT * FROM `table` WHERE `id`='1'");
//Initially Set all the columns as zero.
$col1 = 0; $col2 = 0;
//Etc.
while ($row = mysql_fetch_assoc($query)) {
foreach($row as $key => $val) {
if($key != 'id') {
$$key += $val;
//Like: $col1 += 30;
}
}
}
//Now All the variables are ready added:
//Like: $col1 = 41;
//Like: $col2 = 37;
//Use them However you like:
//To update:
//1. First Delete both rows:
$query = mysql_query("DELETE FROM `table` WHERE `id`='1'");
//2. Insert
$query = mysql_query("INSERT INTO `table` (`id`,`col1`,`col2`) VALUES ('1','{$col1}','{$col2}') ");
//And so on
?>

Update numbers in table with variable and update variable

As you can see from the table below the user with the id of 1 has 10 points altogether
What I'm trying to do is have one number submitted from a form $edit_points to loop through and subtract from user 1
This number could be anything eg:
$edit_points = 6
would subtract 4 from the first record
then move to the next and only subtract the remainder 2
then break out of loop
UserID | TotalPoints
-------------------
1 | 4
1 | 4
1 | 2
4 | 3
3 | 3
5 | 4
This is what I've got so far
$pointLeft = $edit_points;//sent from form
while($point = mysqli_fetch_array($output)){
if($pointLeft > $point["TotalPoints"]){//if pointsLeft more than this record
$remainder = $pointLeft-$point["TotalPoints"];//get remainder
$query2 = "UPDATE pointstable SET TotalPoints=0 WHERE UserID=".$UserID;
$output2 = $mysqli->query($query2);
}elseif($pointLeft < $point["TotalPoints"]){
$remainder = $point["TotalPoints"] - $pointLeft;
$query2 = "UPDATE pointstable SET TotalPoints=".$remainder." WHERE UserID=".$UserID;
$output2 = $mysqli->query($query2);
}
$pointLeft = $remainder;
}
It works to a point and seems to populate all the records with the same last value that remainder holds
I've tried break and putting an if ($pointLeft<=0) above the first if
but none works.
any help? or a better way of doing it preferably using php
Thanks to Marty
Revised code below
There's a unique id PointID that I now use
$poinstLeft = $edit_points; //sent from form
while($point = mysqli_fetch_array($output)){
//if pointsLeft more than this record
if($poinstLeft >= $point["TotalPoints"]){
//get remainder
echo $poinstLeft." ";
$remainder = $poinstLeft-$point["TotalPoints"];
$query2 = "UPDATE pointstable SET TotalPoints=0 WHERE UserID=".$UserID." AND PointID=".$point["PointID"];
$output2 = $mysqli->query($query2);
// Calculate new pointsleft
$poinstLeft = $remainder;
} elseif ($poinstLeft < $point["TotalPoints"]){
$remainder = $point["TotalPoints"] - $poinstLeft;
echo $poinstLeft." ";
$query2 = "UPDATE pointstable SET TotalPoints=".$remainder." WHERE UserID=".$UserID." AND PointID=".$point["PointID"] ;
$output2 = $mysqli->query($query2);
// Here, your remainder is different from the upper half of your if-function!
// So, you don't have to recalculate pointsleft... It's just:
$poinstLeft = 0;
// Break the while loop:
break 2;
}
}

Categories