Add rows together - php

I have one table with some rows and lot of columns (about 50)
- I don't want to list all the column names, co I use a while loop to go through the table and a foreach command to find the column names and values.
Now I would like to add these two rows into one row (where id is 1) and sum the values together...
id | col 1 | col 2 | ...
1 30 21
1 11 16
2 75 0
It should look like this
id | col1 | col2 | ...
1 41 37
2 75 0
This is what I have...
$query = mysql_query("SELECT * FROM `table` WHERE `id`='1'");
while ($row = mysql_fetch_assoc($query)) {
foreach($row as $key => $val) {
if($key != 'id') {
//the sum code...?
}
}
}
Could you please help me? Thank you a lot...

Based on your code which indicates you're using mysql I'm going to give you a mysql solution (which can easily be ported to most RDBMS). What you're looking for can easily be accomplished with aggregate functions. Follow the link to read about all the aggregate functions mysql has.
SELECT id, SUM(col1), SUM(col2) FROM table GROUP BY id;

just sum the results in mysql.. databases are made to handle things like this so it'll be a faster solution than doing it just in php.
SELECT
id,
SUM(col1),
SUM(col2)
FROM table
GROUP BY id;

Try this: See the Explanation as comments:
<?php
$query = mysql_query("SELECT * FROM `table` WHERE `id`='1'");
//Initially Set all the columns as zero.
$col1 = 0; $col2 = 0;
//Etc.
while ($row = mysql_fetch_assoc($query)) {
foreach($row as $key => $val) {
if($key != 'id') {
$$key += $val;
//Like: $col1 += 30;
}
}
}
//Now All the variables are ready added:
//Like: $col1 = 41;
//Like: $col2 = 37;
//Use them However you like:
//To update:
//1. First Delete both rows:
$query = mysql_query("DELETE FROM `table` WHERE `id`='1'");
//2. Insert
$query = mysql_query("INSERT INTO `table` (`id`,`col1`,`col2`) VALUES ('1','{$col1}','{$col2}') ");
//And so on
?>

Related

Select value from foreach result

Hi is there a way to get the value from each foreach result.
For Example I have a table named tblsamp.
id | data |
1 | d1 |
2 | d2 |
3 | d3 |
then put some query:
$query = $this->db->query("SELECT * FROM tblsamp");
foreach ($query->result() as $row){
echo $row->data .'<br>';
}
Result is:
d1
d2
d3
Now what I want is I want to get the value of the first result and compare the value from another table, and so on...
For Example:
if('d1' == '(value from another table)'{
\\do something here
} else if ('d2' == '(value from another table)'{
\\and so on.....
}
how can I do this guys? TIA!.
It looks like you are using codeigniter based off the $this->db->query syntax. With codeigniter you can change a table into an array using $query->result_array().
If you are sure both tables have the same amount of rows, you can use something like the following.
$query = $this->db->query("SELECT * FROM tbl1");
$table1 = $query->result_array();
$query = $this->db->query("SELECT * FROM tbl2");
$table2 = $query->result_array();
for ($x = 0; $x <= count($table1); $x++) {
if ($table1[$x] === $table2[$x]) {
//DO SOMETHING HERE
}
}
If $table1 might have more rows than table2, I would change it to
$query = $this->db->query("SELECT * FROM tbl1");
$table1 = $query->result_array();
$query = $this->db->query("SELECT * FROM tbl2");
$table2 = $query->result_array();
for ($x = 0; $x <= count($table1); $x++) {
if (isset($table1[$x]) && isset($table2[$x])) {
if ($table1[$x] === $table2[$x]) {
//DO SOMETHING HERE
}
} else {
break;
}
}
You can find you have matches in 2 tables however you may want to do more research about How SQL query can return data from multiple tables
How can an SQL query return data from multiple tables
This may work for your basic example
$query = $this->db->query("SELECT * FROM tblsamp,tblother");
$rst = mysql_query($query);
if(mysql_affected_rows() > 0) {
while($row = mysql_fetch_array($rst)) :
if($row['data'] == '$row['otherdata']') {
echo 'you got a match' . $row['data'] . ' In table sample to ' . $row['otherdata'] . ' In other table<br>';
}
else {
echo ' no match found in results;
}
}
endwhile;
You could add a query within your query, but this is not recommended -- things can get REALLY slow. It might be something like this:
// your original query
$query = $this->db->query("SELECT * FROM tblsamp");
foreach ($query->result() as $row){
// for each record in your original query, we run a new query derived from the result
// OBVIOUSLY you need to change this line of code to be specific to
// your database table's structure because some_col is probably not
// the name of a column in your database
$subquery = $this->db->query("SELECT * FROM other_table WHERE foo=" . $row->some_col);
$subrows = $subquery->result();
// output $subrows here?
// note that $subrows might be an array with any number any number of records
}
the exact code will depend on the db classes you are using. It's codeigniter, if I'm not mistaken? EDIT: it is codeigniter.
The correct solution here is going to depend on your database table definitions. I would strongly suggest creating a JOIN using CodeIgniter, but can't offer much more advice without some idea of what your db structures are going to look like and how many records in the second table exist for each record in the first table.

Get data from mysql database inside for loop with php pdo

I have this php code - for loop and on every step , every increment search for data in mysql table aktivnosti
PHP:
for ($i=1; $i<=30; $i++;){
$temp = array();
$temp['ID'] = $i;
// ATTEMP TO GET DATA FROM aktivnosti WHERE id_activity = $i
$rs1 = $db->prepare('SELECT naziv FROM aktivnosti WHERE id_activity=:idd');
$rs1->bindParam(':idd', $i);
$rs1->execute();
$naz = $rs1->fetchColumn();
$temp['activity'] = '<button>'.$naz.'</button>';
$output['data'][] = $temp;
}
$jsonTable = json_encode($output);
So as you can see from code above I try to get data on every $i increment and search if id_activity on table aktivnosti = $i
I get just one result so I get just first 'naziv', I need to get all naziv data from table aktivnosti where id_activity = $i and create:
<button>$naz[0]<button>
<button>$naz[1]<button>
<button>$naz[2]<button>
<button>$naz[how many times id_activity = $i]<button>
How I can do that? Some ideas?
sorry for my engish. Thanks
As pointed out in comments above, you are taking a bad approach here. You should be able to get all this data in a single query. You probably also need to take a look at your schema if you want to have the concept of a fixed number of 30 days with each days related to n number of records. I would suggest two tables
day_list
day_id day_name (or any other day-related data fields)
1 ...
2 ...
... ...
30 ...
days_records
record_id day_id other_data
1 1 ...
2 1 ...
3 3 ...
4 5 ...
...
You would then query this like:
SELECT
d.day_id AS day_id
dr.record_id AS record_id
dr.other_date AS other_data
FROM day_list AS d
LEFT JOIN day_records AS dr
ON d.day_id = dr.day_id
Sorry for the change in table names, as don't know what your database schema represents in real-world terms.
You then make a single query like:
$query = <<<EOT
SELECT
d.day_id AS day_id
dr.record_id AS record_id
dr.other_date AS other_data
FROM day_list AS d
LEFT JOIN day_records AS dr
ON d.day_id = dr.day_id
EOT;
$rs1 = $db->execute($query);
if (false === $rs1) {
// something went wrong. perhaps log an error
} else {
while($row = $rs1->fetch(PDO::FETCH_ASSOC)) {
$temp = $row;
// check to see if this date has a record
if (empty($temp['record_id'])) {
// this is a day with no associated record.
// do something
}
// not shown - continue to manipulate your $temp as desired
// then add to output array
$output['data'][] = $temp
}
}
If you need both ID and activity:
$sql = <<<EOD
SELECT
id_activity AS ID,
CONCAT('<button>', naziv, '</button>') AS activity
FROM aktivnosti
WHERE id_activity BETWEEN 1 AND 30
ORDER BY id_activity
EOD;
$data = $db->query($sql)->fetchAll(PDO::FETCH_ASSOC);
$jsonTable = json_encode(compact('data'));
If you only use activity:
$sql = <<<EOD
SELECT CONCAT('<button>', naziv, '</button>')
FROM aktivnosti
WHERE id_activity BETWEEN 1 AND 30
ORDER BY id_activity
EOD;
$data = $db->query($sql)->fetchAll(PDO::FETCH_COLUMN, 0);
$jsonTable = json_encode(compact('data'));
try this...
while($naz=$rs1->fetch(PDO::FETCH_OBJ))
{
echo $naz->column1;
echo $naz->column2;
}
instead of
$naz = $rs1->fetchColumn();

PHP Pagination-related MySQL query issue

I'm trying to do 2 things.
1) Get the amount of rows in this query
SELECT
COUNT(*)
FROM
`my_table`
WHERE
`column_1` = 152
AND
`column_2` = 42
ORDER BY
`column_3`
As you can see that is no problem ^^
2) Determine the number within the range of rows that is returned by id
Ex: ID 765 is Item 4 of 7 where column_1 = 152 and column_3 = 42
Does anyone have any basic solutions to this problem with almost pure MySQL? I'd like to avoid iterating through all the rows and setup a counter to increment until it matches current id like this:
$sql = '
SELECT
*
FROM
`my_table`
WHERE
`column_1` = 152
AND
`column_2` = 42
ORDER BY
`column_3`
';
$query = mysqli_query($sql);
$current_id = 2523;
$i = 1;
while ($row = mysqli_fetch_assoc($query)) {
if ($row['id'] == $current_id) {
$current_position = $i;
}
$i++;
}
print 'Current position in range is: '. $current_position;
Also please don't worry about the actual syntax, I won't be using this exact script, but you get the logic that I'd like to avoid using. If anyone has a better solution, please let me know. Thanks in advance!!

MySQL/PHP query to reverse relationship

I have a mysql table with the following columns:
ID Units
1 1234,6543,9876
2 1234,6543
3 6543
4 9876
5 0987
I would like to reverse the relationship to get an output like this:
Unit IDs
1234 1,2
6543 1,2,3
9876 1,4
0987 5
I was wondering if this could be done in a query or some php, without chunking through with explodes etc?
Using comma-separated lists in SQL is awkward. This is a denormalized design, and SQL is not well suited to work with data in this format.
I would fetch all the data back into PHP and manipulate it there.
$id_per_unit = array();
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$unit_array = explode(",", $row["Units"]);
foreach ($unit_array as $unit) {
$id_per_unit[$unit][] = $row["Id"];
}
}
Something like this:
$query = "SELECT `Unit`, `IDs` FROM `table` ORDER BY `Unit`";
$data = mysqli_query($con, $query);
$prev_unit = '';
while ($row = mysqli_fetch_array($data)) {
if ($prev_unit != $row['Unit']) {
// echo a new row with the new unit and then ID
} else {
// echo just the ID in the same row, this unit is the same as the last one.
}
$prev_unit = $row['Unit'];
}
With only SQL, you can do something like this :
SELECT unit , GROUP_CONCAT(id)
FROM (
SELECT id,substring_index(Units,',',1) AS unit
FROM Table1
UNION
SELECT id,REPLACE(
REPLACE(SUBSTRING_INDEX(Units,',',2),SUBSTRING_INDEX(Units,',',1),'')
,',','') AS unit
FROM Table1
UNION
SELECT id,REPLACE(
REPLACE(SUBSTRING_INDEX(Units,',',3),SUBSTRING_INDEX(Units,',',2),'')
,',','') AS unit
FROM Table1) AS UNITS
WHERE unit != ''
GROUP BY unit
See SQLFIDDLE

PHP SUM function

I have a table like following:
id q_id value
------------------------
1 2 5
2 2 NULL
3 2 5
4 2 NULL
5 4 2
6 4 NULL
7 4 2
8 4 NULL
What I want is to get the sum of (for example) all value where q_id = 2
$sq = mysql_query("SELECT SUM(value) AS sum FROM table WHERE q_id = 2)or die(mysql_error());
while($row = mysql_fetch_array($sq)){
$sum = $row['sum'];
}
echo $sum."<br>";
But I'm getting
5
5
But what I want is the sum of the value and expecting 10 instead.
Thank you for helping.
If you're going to loop over the result set anyway, why not just use
SELECT value FROM table WHERE q_id=2
then sum up those values using the while loop? Something like:
while($row = mysql_fetch_array($sq)) {
    $sum += $row['value'];
}
echo $sum."<br>";
Edit: also, as Jason McCreary said above, you should look into an alternate method of querying the database. I would suggest searching php.net for "PDO", which is very easy to use.
We can directly sum in the query like
SELECT 5+6 AS addition
Give it a try... You are displaying value, there was missing quote in your code.
$sq = mysql_query("SELECT SUM(value) AS sum FROM `table` WHERE `q_id` = '2'")or die(mysql_error());
while($row = mysql_fetch_assoc($sq))
{
$sum = $row["sum"];
}
echo $sum . "<br>";
$sq="SELECT value FROM table WHERE q_id='".$am."'";
$result=mysqli_query($link,$sq);
while($row=mysqli_fetch_assoc($result)) {
$sum += $row['value'];
}
echo "<p>Sum: ".$sum."</p><br>";
//$am ='2';
//$link -- connection to the data base
Please put $am ='2'; before the select statement and also make sure you have connected to the data base using $link
You will get the total sum according to the value of q_id
I have tested the code and works fine.
You need to add a GROUP BY to your query. Add the following to the end
GROUP BY q_id

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