Running Multiple MySQL Queries in PHP - php

Question

In PHP I'm attempting to build a form that needs to check for an ID in one table and if it exists it should create a record in another table. So far, that works but the issue I'm having is when I attempt to handle the case if the ID I checked for didn't exist. If it doesn't exist I'd like to create another one. But every time I try it, I get 500 errors from the server when I fetch the results.
Essentially I made the following function
function trySQL($con, $query, $params) {
$stmt = $con->prepare($query);
$result = $stmt->execute($params);
$id = $stmt->insert_id;
return array($stmt,$result,$id);
}
I call this function multiple times through out my php code but when I call it more then once and attempt to fetch the results it breaks.
$custINSquery = "
INSERT INTO custs (
FirstName,
LastName,
EmailAddress,
PhoneNumber
) VALUES (
:FirstName,
:LastName,
:EmailAddress,
:PhoneNumber
)
";
$createJob = "
INSERT INTO jobs (
custs_id,
StAddress,
State,
ZipCode,
MoistureLocation,
status_id
) VALUES (
:custs_id,
:StAddress,
:State,
:ZipCode,
:IssueDesc,
:status_id
)
";
$custSELquery = "SELECT id, FirstName, LastName, EmailAddress FROM custs WHERE FirstName = :FirstName AND LastName = :LastName AND EmailAddress = :EmailAddress";
$custSELquery_params = array(
':FirstName' => $_POST['FirstName'],
':LastName' => $_POST['LastName'],
':EmailAddress' => $_POST['EmailAddress']
);
$checkcust = trySQL($db, $custSELquery, $custSELquery_params);
$row = $checkcust[0]->fetch();
if(!$row){
$custINSquery_params = array(
':FirstName' => $_POST['FirstName'],
':LastName' => $_POST['LastName'],
':EmailAddress' => $_POST['EmailAddress'],
':PhoneNumber' => $_POST['PhoneNumber']
);
$custins = trySQL($db, $custINSquery, $custINSquery_params);
$custsel = trySQL($db, $custSELquery, $custSELquery_params);
$custs_id = $custsel[0]->fetch();
if ($custs_id != null) {
$createJobParam = array(
':custs_id' => $custs_id,
':StAddress' => $_POST['StAddress'],
':State' => $_POST['State'],
':ZipCode' => $_POST['ZipCode'],
':IssueDesc' => $_POST['MoistureLocation'],
':status_id' => $_POST['status_id']
);
$jobins = trySQL($db, $createJob, $createJobParam);
$jobres = $jobins[0]->fetch();
die("um...");
if ($jobres) {
# code...
die("looks like I made it");
}
}
} else {
$createJobParam = array(
':custs_id' => $row['id'],
':StAddress' => $_POST['StAddress'],
':State' => $_POST['State'],
':ZipCode' => $_POST['ZipCode'],
':IssueDesc' => $_POST['MoistureLocation'],
':status_id' => $_POST['status_id']
);
$data['success'] = true;
$data['message'] = 'Success!';
}
Additional Notes: When I look through the php doc's they are saying that I could use the inserted_id thing in order to get the ID that I inserted previously but when I try that it just gives me nulls with this set up.
Any help would be appreciated.
Thanks!