fetch multiple value from same table using id value - php

Question

I want to fetch value Rows from single table.I want to fetch sub_id for specific id.
I achieved my require ment in 2 query.I want to do it in single query.I want to display result as Event,order history,Eent Ticket,calander
$sql="select * from table1 where roles like %admin% and sub_id='0'"
$sql1=mysql_query($sql);
while($fet=mysql_fetch_assoc($sql1))
{
$id=$fet['id'];
$query="select page_name from table1 where sub_id= '$id'";
.. ..
}

Answer 1

Use a JOIN
SELECT t1.id, t1.sub_id, t1.page_name, t2.page_name AS parent_page
FROM table1 AS t1
JOIN table1 AS t2 ON t1.sub_id = t2.id
WHERE t2.roles like '%admin%' AND t2.sub_id = '0';
DEMO

Answer 2

use this
$sql="select sub_id from table1 where id='".$id."' ";
After this, use results of this as below
$sql= "select * from table1 where roles like %admin% and sub_id in($ids)";

Answer 3

You dont need another query to get the value of page_name just use $fet['page_name']; you already get the data of page_name in your first query.
$sub_id = $fet['sub_id'];//
echo $sub_id;//
$page_name = $fet['page_name'];//You can get and use the value of page_name here
UPDATED
if you want Event,Order History,Event Ticket and Calander
then change your where to sub_id = '2' ordered by id ascending.
$sql="select * from table1 where roles like %admin% and sub_id='2' order by id asc"
$sql1=mysql_query($sql);
while($fet=mysql_fetch_assoc($sql1))
{
echo $fet['page_name'].'<br/>';//display the page_name
}

Answer 4

You can also use the single query for getting page_name:
SELECT page_name FROM table1
WHERE roles LIKE %admin%
AND sub_id = 2
you can get Event,Order History,Event Ticket,Calendar as:
$sql="SELECT page_name FROM table1
WHERE roles LIKE %admin%
AND sub_id = 2";
$sql1=mysql_query($sql);
$records = array();
while($fet=mysql_fetch_assoc($sql1))
{
$records[] = $fet['page_name'];
}
echo implode(",",$records); // Event,Order History,Event Ticket,Calendar
UPDATE 1:
use sub_id = 2 for getting all page_name related to Event MAnagement
Side note:
I suggest you to use mysqli_* or PDO, instead of mysql_* because mysql_* is deprecated in not available in PHP 7.

Answer 5

$sql="select sub_id from table1 where id='".$id."' ";
if thats what you want.