I don't have anything in my database? - php

Question

$query = "INSERT INTO `users` (`id`, `name`, `lname`, `uname`, `email`, `pass`) VALUES (NULL, '$name', '$lname', '$uname', '$email1', '$pass1')" or die(mysqli_error($con));
mysqli_query($con, $query);
I wrote this code... I don't have anything in my base after inputing

Answer 1

$query = "INSERT INTO `users` (`id`, `name`, `lname`, `uname`, `email`, `pass`) VALUES (NULL, '$name', '$lname', '$uname', '$email1', '$pass1')" or die(mysqli_error($con));
mysqli_query($con, $query);
Replace with:
$query = "INSERT INTO `users` (name, lname, uname, email, pass) VALUES ('$name', '$lname', '$uname', '$email1', '$pass1')" or die(mysqli_error($con));
mysqli_query($con, $query);
No need to put your column names in quotes.
Also, if your ID is auto_increment, you don't need to add it in your insert query.

Answer 2

An or die(mysqli_error($con)); makes no sense as part of setting a string literal. So try recoding like this so that you are looking for errors from the right place.
$query = "INSERT INTO `users`
(`id`, `name`, `lname`, `uname`, `email`, `pass`)
VALUES (NULL, '$name', '$lname', '$uname', '$email1', '$pass1')" ;
$result = mysqli_query($con, $query);
if ( $result === FALSE ) {
echo mysqli_error($con);
exit;
}