How to enter POST data into database? - php

Sample code:
echo $mylinks;
Outputted echo:
http://www.google1.com|http://www.google2.com
I want to insert each of these into a database table.
Here's what I was trying to use:
INSERT INTO `backlinks` (`id`, `link`, `apikey`, `date`) VALUES (NULL, '".$mylinks."', '11bebe13ae7fe257d9ddba22a9d1eea3', CURRENT_TIMESTAMP);
The problem is, it's inserting into the database like this basically:
INSERT INTO `backlinks` (`id`, `link`, `apikey`, `date`) VALUES (NULL, 'http://www.google1.com|http://www.google2.com', '11bebe13ae7fe257d9ddba22a9d1eea3', CURRENT_TIMESTAMP);
Whereas I want each URL to be entered into its own row like this:
INSERT INTO `backlinks` (`id`, `link`, `apikey`, `date`) VALUES (NULL, 'http://www.google1.com', '11bebe13ae7fe257d9ddba22a9d1eea3', CURRENT_TIMESTAMP);
INSERT INTO `backlinks` (`id`, `link`, `apikey`, `date`) VALUES (NULL, 'http://www.google2.com', '11bebe13ae7fe257d9ddba22a9d1eea3', CURRENT_TIMESTAMP);
URLs are separated by a pipe (|) - there's normally more than one URL that's submitted, but sometimes there's only a single URL - in case that makes a difference.
So how do I submit the URLs into my database so each is on a separate row?

mysql will not split that for you, you need to split it yourself.
$stmt = $pdo->prepare("INSERT INTO `backlinks` (`id`, `link`, `apikey`, `date`) VALUES (NULL,:link, '11bebe13ae7fe257d9ddba22a9d1eea3', CURRENT_TIMESTAMP)");
foreach (explode("|", $mylinks) as $link) {
$stmt->execute(array(":link" => $link))
}

You can convert this string to an array with php explode function and after that insert data like this:
$array = explode('|', $mylinks);
foreach($array as $key => $value)
//Insert $value into table

Related

How do you pass multiple sql statements using php [duplicate]

This question already has answers here:
php/mysql with multiple queries
(3 answers)
Closed 7 years ago.
This is what i want to do but with lots of records. When i try this i get this kind of error:the error message i get
this is my currant php and when i submit it no record is added.
$sql = "INSERT INTO `people` (`id`, `firstname`, `lastname`, `email`, `reg_date`) VALUES (NULL, 'firstnameA', 'surnameA', 'example1#email.com', CURRENT_TIMESTAMP);
INSERT INTO `people` (`id`, `firstname`, `lastname`, `email`, `reg_date`) VALUES (NULL, 'firstnameB', 'surnameB', 'example#email.com', CURRENT_TIMESTAMP);
" ;
However this code works but i am only adding one record
$sql = "INSERT INTO `people` (`id`, `firstname`, `lastname`, `email`, `reg_date`) VALUES (NULL, 'tom', 'walker', 'tom#walker.com', CURRENT_TIMESTAMP);
"
You just need to duplicate the values portion, like this:
$sql = "INSERT INTO `people` (`id`, `firstname`, `lastname`, `email`, `reg_date`)
VALUES (NULL, 'tom', 'walker', 'tom#walker.com', CURRENT_TIMESTAMP),
(NULL, 'bob', 'jones', 'bob#jones', CURRENT_TIMESTAMP)";
Use mysqli_multi_query check out:
http://php.net/manual/en/mysqli.multi-query.php

Couldn't insert into Database: Column count doesn't match value count at row 1

I have a table in hte same database similar to this that has no difference in syntax or format. Yet I get the above mentioned error? I have done everything I know to fix it, but not sure what I have done wrong. I have an image of the structure as well.
$sql = "INSERT INTO `FormInfo` (`first_name`,
`last_name`,
`company`,
`address`,
`province`,
`postal`,
`telephone`,
`fax`,
`email`,
`comment`)
VALUES ('$good_data[first_name]',
'$good_data[last_name]',
'$good_data[company]',
'$good_data[address]',
'$good_data[province]',
'$good_data[postal]',
'$good_data[telephone]',
'$good_data[email]',
'$good_data[comment]')";
mysqli_query($cxn, $sql) or die ("Couldn't insert into Database: " . mysqli_error($cxn));
What am I missing here?
You are missing your $good_data[fax] argument
EDIT: Also, please consider the way you are calling your objects in your array is bad practice. See this for more information
try to change,
$sql = "INSERT INTO `FormInfo` (`first_name`, `last_name`, `company`, `address`, `province`, `postal`, `telephone`, `fax`, `email` ,`comment`) VALUES ('$good_data[first_name]', '$good_data[last_name]', '$good_data[company]', '$good_data[address]', '$good_data[province]', '$good_data[postal]', '$good_data[telephone]', '$good_data[email]', '$good_data[comment]')";
to
$sql = "INSERT INTO `FormInfo` (`first_name`, `last_name`, `company`, `address`, `province`, `postal`, `telephone`, `fax`, `email` ,`comment`) VALUES ('$good_data[first_name]', '$good_data[last_name]', '$good_data[company]', '$good_data[address]', '$good_data[province]', '$good_data[postal]', '$good_data[telephone]', '$good_data[email]', '$good_data[comment]', '$good_data[fax]')";
You are missing insert value for fax column:
$SQL = "INSERT INTO `FormInfo`
(`first_name`,
`last_name`,
`company`,
`address`,
`province`,
`postal`,
`telephone`,
`fax`,
`email`,
`comment`
)
VALUES (
'$good_data[first_name]',
'$good_data[last_name]',
'$good_data[company]',
'$good_data[address]',
'$good_data[province]',
'$good_data[postal]',
'$good_data[telephone]',
'$good_data[fax]',
'$good_data[email]',
'$good_data[comment]'
)";

Conversion from MySQL to mysqli not working

I am in a process of converting my Existing MySQL to mysqli
But I can't get this piece of code correct
mysql_query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");
$new_id = mysql_insert_id();
mysql_query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");
What I tried is given below but didn't work
$mysqli->query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");
$new_id = mysqli_insert_id();
$mysqli->query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");
The Problem is with the $new_id = mysqli_insert_id(); statement bcoz the first query is executing
For mysqli Object oriented style to get the last inserted id use this
$mysqli->insert_id ;
http://www.php.net/manual/en/mysqli.insert-id.php
So your queries will be as
$mysqli->query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");
$new_id = $mysqli->insert_id;
$mysqli->query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");

how can I add same value in two different tables

i m trying to add custom list of tags using excel file and I have done most of the work. but i am confused that how can I add same value in 2 different tables columns.
i had inserted the values in
INSERT INTO `steve`.`wp_terms` (`term_id`, `name`, `slug`, `term_group`) VALUES (NULL, 'tag99', 'tag99', '0');
and
INSERT INTO `steve`.`wp_term_taxonomy` (`term_taxonomy_id`, `term_id`, `taxonomy`, `description`, `parent`, `count`) VALUES (NULL, '21', 'post_tag', '', '0', '0');
now i want to add term_id in both table .. could somebody tell me how can i do that?
AND term_id is database generated value.
INSERT INTO `steve`.`wp_term_taxonomy` (`term_taxonomy_id`, `term_id`, `taxonomy`, `description`, `parent`, `count`) VALUES (NULL, LAST_INSERT_ID, 'post_tag', '', '0', '0');
If I follow correctly your first query inserts into a table and creates a new id for that record, then you want to use that ID in the next query to insert into a different table right? If that's the case the above query should work for your second one using LAST_INSERT_ID for the term_id value.
To update the question with your new code it should, I emphasize should, work with this:
$sql2 = "INSERT INTO " . $table2 . " (`term_taxonomy_id`, `term_id`, `taxonomy`, `description`, `parent`, `count`) VALUES (NULL, LAST_INSERT_ID, 'post_tag', '', '0', '0')";
$wpdb->query($sql);
$wpdb->query($sql2);
The way you have it above you are overwriting your first query before you execute it.
Also I don't understand how you're inserting nulls into an auto-increment field, that alone should be throwing an error. Honestly both your queries should be leaving their base ids (the auto increment ones) out of the query entirely like this:
$sql2 = "INSERT INTO " . $table2 . " (term_id, taxonomy, description, parent, count) VALUES (LAST_INSERT_ID, 'post_tag', '', '0', '0')";
Use mysql_insert_id()
mysql_query("INSERT INTO `steve`.`wp_terms` (`term_id`, `name`, `slug`, `term_group`) VALUES (NULL, 'tag99', 'tag99', '0')");
$lastInsertId = mysql_insert_id();
mysql_query("INSERT INTO `steve`.`wp_term_taxonomy` (`term_taxonomy_id`, `term_id`, `taxonomy`, `description`, `parent`, `count`) VALUES (NULL, '" . $lastInsertId . "', 'post_tag', '', '0', '0')");
NOTE: To use mysql_insert_id(), term_id in wp_terms must be set to auto increment.
you need to use ALTER table and add that column's definition/constraints into the other table, here's the manual

Remove same values rows over different column mysql

I 'm stuck on a very basic problem, I want to skip the row which has duplicate values over three columns.
Table feeds
id,type,user_id,friend_id,date
1, 'friend', 4 , 5 , 5/5/2010
2, 'friend', 5 , 4 , 5/5/2010
Now this is how the data is saved (I can't change the saving module)
since both have same thing, so I want to pick them only as a 1 row not 2.
I don't want to validate and remove it at PHP end, b/c if I'll do at PHP the pagination would be disturb
Edit:
Table Structure
create table `feed` (
`id` double ,
`type` blob ,
`user_id` double ,
`type_id` double ,
`date` datetime
);
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('78','friends','1314','1313','2012-09-03 19:48:14');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('79','friends','1313','1314','2012-09-03 19:48:14');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('80','friends','1314','1312','2012-09-03 19:49:07');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('82','friends','1313','1312','2012-09-03 19:49:09');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('84','friends','1315','1312','2012-09-03 19:49:24');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('86','friends','1315','1313','2012-09-03 19:49:33');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('87','friends','1313','1315','2012-09-03 19:49:33');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('97','friends','1317','1312','2012-09-03 19:55:06');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('99','friends','1313','1317','2012-09-03 19:56:01');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('100','friends','1317','1313','2012-09-03 19:56:01');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('101','friends','1315','1317','2012-09-03 19:56:58');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('102','friends','1317','1315','2012-09-03 19:56:58');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('104','following','1313','1193','2012-09-03 19:59:39');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('105','following','1313','1308','2012-09-03 19:59:51');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('106','following','1313','1098','2012-09-03 19:59:58');
And here is the ultimate solution! If the same friendship pair (reversed) exists it only takes the one where user_id>friend_id.
SELECT DISTINCT type, user_id, friend_id, date
FROM table t1
WHERE t1.user_id > t1.friend_id
OR NOT EXISTS (
SELECT * FROM table t2
WHERE t1.type=t2.type AND t1.date=t2.date
AND t2.user_id = t1.friend_id AND t2.friend_id = t1.user_id
)
The function you are looking for is DISTINCT(). That allows you to group the table by that column and remove duplicates.
Just make sure in your select statement that you also select the other field columns as well:
SELECT id, DISTINCT(type), user_id, friend_id, date FROM TABLENAME
You could perform a JOIN on the table itself, which should do what you are looking for.
Something like this might do the trick:
SELECT * FROM tableName a
JOIN tableName b ON a.user_id = b.friend_id
You should get rid of those duplicate records by running:
DELETE FROM table t1 WHERE
EXISTS (
SELECT * FROM table t2
WHERE t1.type=t2.type AND t1.date=t2.date
AND t2.user_id = t1.friend_id AND t2.friend_id = t1.user_id
AND t1.user_id > t2.user_id
)
Then you can get distinct friendship records with:
SELECT DISTINCT type, user_id, friend_id, date FROM table
Also, you can write a DB trigger that fires on INSERT, that checks if a duplicate (with reversed user_id and friend_id) already exists. If exists it does ROLLBACK, else allow INSERT.

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