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Alright so I have made a site, just for a project I was doing. On this site I have this database that has a couple of articles on it, I use this code for make queries:
<?php
if (!empty($_REQUEST['term'])) {
$term = mysql_real_escape_string($_REQUEST['term']);
$sql = "SELECT * FROM articles WHERE title LIKE '%".$term."%'";
$r_query = mysql_query($sql);
while ($row = mysql_fetch_array($r_query)){
echo $row['title'];
echo $row['summary'];
echo $row['content'];
echo $row['publicationDate'];
}
}
?>
The problem is that the search is a bit too "loose." The database which the site connects to has many articles. What I don't like is that say I searched the letter 'A' in the search box, it comes up with any instance the letter 'A' appears in any article title. So instead of coming with the article for the letter 'A', Australia, Austria, Afghanistan and even Ecuador come up. Its kind of frustrating. Can you help me?
You can try to force it to be a start of a string or start of a word:
$sql = "SELECT * FROM articles WHERE title LIKE '% ".$term."%' OR title LIKE '".$term."%'";
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The image above is my sql database. what I want to do is load the names and echo in json but the thing is though, I want to show one of each name. Like see how there are 4 assassinshadow entries? I want php to echo only one of em. not making much sense am I? haha
You can use DISTINCT in your mysql query:
$mysqli = mysqli_connect("example.com", "user", "password", "database");
$query = "SELECT DISTINCT name from yourtable";
$res = mysqli_query($mysqli, $query);
$row = mysqli_fetch_assoc($res);
Two ways to do that:
SELECT distinct name FROM my_table
or
SELECT name FROM my_table group by name
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how i can make example: post.php and when somebody goes to post.php to show all posts and when somebody click on one post to show in URL post.php?id=1(id=1 by id in database? and when it types post.php?id=2 to go to id 2 in database and show all datas from row of table by id 2)
Use the $_GET method to pass the url. At the top of the php file you can access the information posted in the url using the global $_GET['id']. You can check if it is set, and depending on whether or not it is, show information regarding that id from the database.
It might look something like this:
if (isset($_GET["id"])) {
$id = $_GET["id"];
$query = "SELECT * table WHERE id = {$id} LIMIT 1;";
$result = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($result)){
echo $row["id"];
echo $row["name"];
echo $row["someOtherAttribute"];
}
}
Make sure you have your connection and your database set up and whatnot, but thats how you would accomplish this.
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I have some code here for a song request program. And it works just fine other than the user has to use surrounding quotes for an exact match. I am wondering how I would go about having the php add the quotes so the user can type a band or song title as normal without having to read the small help notice saying to use quotes?
You can concate quotes in after if you like.
$termToSearch = '"' . $termFromUser . '"';
$query = 'SELECT * FROM table WHERE song = :song'
$statement = $this->db->prepare($query);
$statement->bindValue(':song', $termToSearch);
$statement->execute();
$statement->closeCursor();
Just use "=" instead of "LIKE"
SELECT * FROM table WHERE column = '$searchterm'
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so I have records in my database that I would like to print to a HTML table IF they belong to the user.
$sql="SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
The table would read :
Date, Room, Period , Cancel
With cancel being a red cross designed to delete that specific entry from the database :
Booking ID, Date, Period,Type,RoomID, Username are the fields in the database.
How would I go about doing this? I was thinking echoing a table using a for loop but I wouldn't know where to begin?
Try:
$query_rsSearch = "SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
$rsSearch = mysql_query($query_rsSearch) or die(mysql_error());
$row_rsSearch = mysql_fetch_assoc($rsSearch);
$totalRows_rsSearch = mysql_num_rows($rsSearch);
do {
echo $row_rsSearch['Date']." | ".$row_rsSearch['Room']." | ".$row_rsSearch['Period'];
} while($row_rsSearch = mysql_fetch_assoc($rsSearch));
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I am very new and trying to get from the url ie
device.php?id=2
and use the id number multiple times.
can anyone tell me how to display this?
Thanks in advance
1) Get the ID.
$id = $_GET["id"];
2) Search for $id in your database, using MySQL functions like mysqli_fetch_array() etc.
3) Echo the values you fetched, using simple HTML and PHP.
$id = $_GET['id'];
$sql= mysql_query("select * from tableName where id = $id ");
while($row = mysql_fetch_array($sql))
{
echo $row['columnName'];
}
The variable should be in $_GET["id"].
<?php
echo $_GET['id'];
?>