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I am very new and trying to get from the url ie
device.php?id=2
and use the id number multiple times.
can anyone tell me how to display this?
Thanks in advance
1) Get the ID.
$id = $_GET["id"];
2) Search for $id in your database, using MySQL functions like mysqli_fetch_array() etc.
3) Echo the values you fetched, using simple HTML and PHP.
$id = $_GET['id'];
$sql= mysql_query("select * from tableName where id = $id ");
while($row = mysql_fetch_array($sql))
{
echo $row['columnName'];
}
The variable should be in $_GET["id"].
<?php
echo $_GET['id'];
?>
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$sql4 = "SELECT userid, userName FROM $user_table WHERE userName= '$userNames'";
$result = $conn->query($sql4);
$_SESSION['myUser'] = $result['userid'] ;
I have most code I can find but nothing works
Assuming these lines of code come immediately after executing an insert of a new user record and you are using PDO. You could try:
$last_id = $conn->lastInsertId();
$_SESSION['myUser'] = $last_id;
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The image above is my sql database. what I want to do is load the names and echo in json but the thing is though, I want to show one of each name. Like see how there are 4 assassinshadow entries? I want php to echo only one of em. not making much sense am I? haha
You can use DISTINCT in your mysql query:
$mysqli = mysqli_connect("example.com", "user", "password", "database");
$query = "SELECT DISTINCT name from yourtable";
$res = mysqli_query($mysqli, $query);
$row = mysqli_fetch_assoc($res);
Two ways to do that:
SELECT distinct name FROM my_table
or
SELECT name FROM my_table group by name
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how i can make example: post.php and when somebody goes to post.php to show all posts and when somebody click on one post to show in URL post.php?id=1(id=1 by id in database? and when it types post.php?id=2 to go to id 2 in database and show all datas from row of table by id 2)
Use the $_GET method to pass the url. At the top of the php file you can access the information posted in the url using the global $_GET['id']. You can check if it is set, and depending on whether or not it is, show information regarding that id from the database.
It might look something like this:
if (isset($_GET["id"])) {
$id = $_GET["id"];
$query = "SELECT * table WHERE id = {$id} LIMIT 1;";
$result = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($result)){
echo $row["id"];
echo $row["name"];
echo $row["someOtherAttribute"];
}
}
Make sure you have your connection and your database set up and whatnot, but thats how you would accomplish this.
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I'm trying to get array of fields from database:
$query=("SELECT firstname FROM users");
$res = $connect->query($query);
Target is to display first name of every users:
echo $firstname
Output:
Firstname1,Firstname2,Firstname3
I know should be easy, if I just knew more.
For getting all records or a set of records you have to fetch each records inside a while loop.
$query=mysqli_query($connect,"SELECT firstname FROM users"); // execute the query
$string="";
while ($row = mysqli_fetch_array($query)) // fetch each records
{
$string.=$row['firstname']).','; // append the firstname to a variable
}
echo $string; // output the constructed variable with all firstnames
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so I have records in my database that I would like to print to a HTML table IF they belong to the user.
$sql="SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
The table would read :
Date, Room, Period , Cancel
With cancel being a red cross designed to delete that specific entry from the database :
Booking ID, Date, Period,Type,RoomID, Username are the fields in the database.
How would I go about doing this? I was thinking echoing a table using a for loop but I wouldn't know where to begin?
Try:
$query_rsSearch = "SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
$rsSearch = mysql_query($query_rsSearch) or die(mysql_error());
$row_rsSearch = mysql_fetch_assoc($rsSearch);
$totalRows_rsSearch = mysql_num_rows($rsSearch);
do {
echo $row_rsSearch['Date']." | ".$row_rsSearch['Room']." | ".$row_rsSearch['Period'];
} while($row_rsSearch = mysql_fetch_assoc($rsSearch));