I have a text box where I search database for a specific information.
The PHP code when I just type and click on search is the following:
try
{
$date_emp = $_POST['date_emp'];
$val = $_POST['data1'];
$gender = $_POST['gen'];
if($date_emp == "choose" && $gender == "specify")
{
$search = "SELECT * FROM employee
WHERE emp_name = :val OR position = :val
OR salary = :val OR date_employed = :val
OR gender = :val";
$searchStmt = $conn->prepare($search);
$searchStmt->bindValue(":val", $val);
$searchStmt->execute();
$res = $searchStmt->fetchAll();
echo json_encode($res);
}
catch(PDOException $ex)
{
echo $ex->getMessage();
}
And here the AJAX script for it:
$("#search").click(function()
{
var txt = $("#txtSearch").val();
var drop = $("#date_employed").val();
var gender = $("#sex").val();
//console.log(txt);
if(txt == '' && drop == "choose" && gender == "specify")
{
$("#txtSearch").css('border-color', 'red');
}
else
{
if(drop == "choose" && gender == "specify")
{
$.ajax
({
url: 'search.php',
type: 'POST',
data: {data1: txt, date_emp: drop, gen: gender},
dataType: 'JSON',
success:function(res)
{
$("#myTable tr").remove();
$("#myTable").append("<tr><th>Name</th><th>Position</th><th>Salary</th><th>Date</th><th>Gender</th></tr>");
$.each( res, function(key, row){
$("#myTable").append("<tr><td>"+row['emp_name']+"</td><td>"+row['position']+"</td><td>"+row['salary']+"</td><td>"+row['date_employed']+"</td><td>"+row['gender']+"</td></tr>");
});
},
error:function(res)
{
alert("Something Wrong");
}
});
}
$("#date_employed, #sex").change(function()
{
var txt = $("#txtSearch").val();
var drop = $("#date_employed").val();
var gender = $("#sex").val();
$.ajax({
url: 'search.php',
type: 'post',
data: {data1: txt, date_emp: drop, gen: gender},
datatype: 'json',
success:function(res)
{
$("#myTable tr").remove();
$("#myTable").append("<tr><th>Name</th><th>Position</th><th>Salary</th><th>Date</th><th>Gender</th></tr>");
$.each( res, function(key, row){
$("#myTable").append("<tr><td>"+row['emp_name']+"</td><td>"+row['position']+"</td><td>"+row['salary']+"</td><td>"+row['date_employed']+"</td><td>"+row['gender']+"</td></tr>");
});
},
error:function(res)
{
alert("Couldn't find any data!");
}
});
});
}
});
WHERE gender and drop are 2 drop lists that forming a search filters
When I change one of the drop lists, per example, when I choose the date equal to: this week I should see in table 2 rows.
But I can only see them in the network (in devTool), and at console tab I see the following error:
Uncaught TypeError: Cannot use 'in' operator to search for 'length' in
[{"id":"48","0":"48","emp_name":"Alexa","1":"Alexa","position":"Secretary","2":"Secretary","salary":"8000","3":"8000","date_employed":"2016-02-23","4":"2016-02-23","gender":"female","5":"female"}]
The PHP code when I change drop lists is:
if($date_emp == "week" && $gender == "specify")
{
$search = "SELECT * FROM employee WHERE (emp_name = :val OR position = :val
OR salary = :val OR date_employed = :val
OR gender = :val) AND date_employed > DATE_SUB(NOW(), INTERVAL 1 WEEK)";
$searchStmt = $conn->prepare($search);
$searchStmt->bindValue(":val", $val);
$searchStmt->execute();
$res = $searchStmt->fetchAll();
echo json_encode($res);
}
When you make an ajax call and expect the response to be a json you need to send a json header from the PHP
header('Content-Type: application/json');
echo json_encode($data);
Sending the json header from the PHP will turn the "res" param in your ajax to a json object and not a json string.
If you don't send the the header you need to parse the json string into a json object
var json = JSON.parse(res);
Related
I want to send two values to my PHP script that is being called from an AJAX request. Somehow my data is not being passed to the PHP script.
Maybe I am doing something wrong somewhere. Can I have some insight?
$(function() {
$(".delbutton").click(function() {
var viewed_comments = $("#viewed_comments").val();
var del_id = $(this).attr("id");
var info = 'id=' + del_id;
var comments = 'comm=' + viewed_comments;
var tr = $(this).closest('tr');
if (confirm("Are you sure to mark this as viewed?")) {
$.ajax({
type : "POST",
url : "update_entry.php",
dataType: "json",
data: {info:info, comments:comments },
success : function(response) {
if(response=="updation success"){
console.log('inside');
}
}
});
}
return false;
});
});
And my PHP where the AJAX request is going,
$id = $_POST['id'];
$viewed_comments = $_POST['comm'];
$level_code = $_SESSION['level_code'];
$action = 'view';
$viewed_date = date("Y-m-d");
$viewed_by = $_SESSION['session_admin_id'] ;
if($action == 'view')
{
$viewed_date = date('Y-m-d h:i:s');
$nots = $db->idToField("tbl_table","notes",$id);
if ($nots == "")
{
$date_string = "last viewed on|".$viewed_date."|" ;
}
else {
$date_string = $nots."last viewed on|".$viewed_date."|" ;
}
$fnc->update_is_viewed_for("tbl_table",$id, "$viewed_date", $viewed_by);
$notes_data = array("notes"=>$date_string,"viewed_comments"=>$viewed_comments);
$db->query_update("tbl_table", $notes_data, "id=$id");
}
if($db->query_update("tbl_table", $notes_data, "id=$id")){
http_response_code();
echo json_encode('updation success');
}else{
http_response_code(204);
}
Isn't it a name thing? You send two POST variables:
data: {
info: info,
comments: comments
},
but you retrieve them with different names:
$id = $_POST['id'];
$viewed_comments = $_POST['comm'];
What do you get if you var_dump($_POST);?
Use seriliaze form values it will solve your data missing problem, change #frm to your form id
$(document).ready(function(){
$('#frm').submit(function(event){
event.preventDefault();
var formValues = $(this).serialize();
$.ajax({
url:"update_entry.php",
method:"POST",
data:formValues,
dataType:"JSON",
success:function(data){
if (data == 'updation success') {
console.log('success');
}
}
});
});
});
I php code that will insert into database but it always returns false even if it is inserting values into the database.
Here is my code: PHP
<?php
require_once 'connection.php';
if (isset($_POST['borrowBook']))
{
newBorrowRequest();
}
function newBorrowRequest()
{
$b_id = $GLOBALS['db']->real_escape_string($_POST['b_id']);
$userID = $GLOBALS['db']->real_escape_string($_POST['userID']);
$dateBorrowed = $GLOBALS['db']->real_escape_string($_POST['dateBorrowed']);
$remarks = $GLOBALS['db']->real_escape_string($_POST['remarks']);
$sql = "INSERT INTO `tbl_requestbook`(`b_id`, `userID`, `dateBorrowed`, `remarks`) VALUES ('$b_id','$userID','$dateBorrowed','$remarks')";
if($GLOBALS['db']->query($sql))
{
$GLOBALS['db']->close();
header("location:../../admin/Book-Items.php?r=success", true);
}
else
{
header("location:../../admin/Book-Items.php?r=failed", true);
}
}
>?
And here is my Ajax Code:
<script>
$("#borrowBook").click(function(event) {
var bookID = $("#bookBorrow").val();
var userID = $("#borrowBook").val();
var d = new Date();
var month = d.getMonth()+1;
var day = d.getDate();
var output = d.getFullYear() + '/' +
(month<10 ? '0' : '') + month + '/' +
(day<10 ? '0' : '') + day;
$.ajax({
url: '../assets/php/functions-book.php',
type: 'POST',
data: {borrowBook: 'true', b_id: bookID, userID: userID, dateBorrowed: output, remarks: $("#remarks").val() },
success: function(result) {
window.location.reload();
},
error: function(result) {
//window.location.reload();
console.log(result);
}
});
});
</script
There is something wrong with the php query, it will not iterate with the condition thus, it will call the ajax error function.
[EDITED]
I solved this by changing 'header("location:../../admin/Book-Item.php?r=success");' to 'header("location:../../admin/Book-Items.php?r=success");'. It was a wrong call.
My problem now is, after success the header remains. It can't be replace by the new header that I want to change. I already changed the php code to the latest.
I am trying to run a SELECT query in PHP and then multiple rows are selected, but I need to fetch them into an array and then use: echo json_encode($array). After That I need to get this array into AJAX.
Here is the PHP code:
$val = $_POST['data1'];
$search = "SELECT * FROM employee WHERE emp_name = :val OR salary = :val OR date_employed = :val";
$insertStmt = $conn->prepare($search);
$insertStmt->bindValue(":val", $val);
$insertStmt->execute();
$insertStmt->fetchAll();
//echo "success";
//$lastid = $conn->lastInsertId();
$i = 0;
foreach($insertStmt as $row)
{
$arr[$i] = $row;
$i++;
}
echo json_encode($arr);
The problem is that I can't get all the lines of this array into AJAX so I can append them into some table. Here is the script:
var txt = $("#txtSearch").val();
$.ajax({
url: 'search.php', // Sending variable emp, pos, and sal, into this url
type: 'POST', // I will get variable and use them inside my PHP code using $_POST['emp']
data: {
data1: txt
}, //Now we can use $_POST[data1];
dataType: "json", // text or html or json or script
success: function(arr) {
for() {
// Here I don't know how to get the rows and display them in a table
}
},
error:function(arr) {
alert("data not added");
}
});
You need to loop over your "arr" data in the success callback. Something along the lines of:
var txt = $("#txtSearch").val();
$.ajax
({
url: 'search.php', //Sending variable emp, pos, and sal, into this url
type: 'POST', //I will get variable and use them inside my PHP code using $_POST['emp']
data: {data1: txt},//Now we can use $_POST[data1];
dataType: "json", //text or html or json or script
success:function(arr)
{
var my_table = "";
$.each( arr, function( key, row ) {
my_table += "<tr>";
my_table += "<td>"+row['employee_first_name']+"</td>";
my_table += "<td>"+row['employee_last_name']+"</td>";
my_table += "</tr>";
});
my_table = "<table>" + my_table + "</table>";
$(document).append(my_table);
},
error:function(arr)
{
alert("data not added");
}
});
You could just return
json_encode($insertStmt->fetchAll());
Also, be sure to retrieve only characters in UTF-8 or JSON_encode will "crash".
Your success function should be like this :
success:function(arr)
{
$.each(arr,function (i,item) {
alert(item.YOUR_KEY);
});
}
I'm new Jquery and AJAX and I've really been struggling with the syntax I've been trying to use other tutorials as reference but nothing seems to work. I feel I have the right idea but syntax is wrong somewhere please help.
Here is the Ajax side
var var_numdatacheck = <?php echo $datacheck; ?>;
var var_numcheck = parseInt(var_numdatacheck);
function activitycheck(){
$.ajax({
type: 'POST',
url: 'feedupdate.php',
data: {function: '3test', datacheck: var_numcheck},
dataType: "json",
success: function(data) {
var json = eval('(' + data + ')');
$('#datacheck').html(json['0']);
var var_numcheck = parseInt(msg);
//setTimeout('activitycheck()',1000)},
error:function(msg) {
console.log(msg);
}
});
}
$(document).ready(function() {
activitycheck();
});
Here is the php the AJAX calls
<?php
require "dbc.php";
$function = $_POST['function'];
$datacheck = $_POST['datacheck'];
$search="SELECT * FROM Feedtest ORDER BY id DESC";
$request = mysql_query($search);
$update= mysql_fetch_array($request);
$updateid = $update['id'];
$updatecheck = mysql_num_rows($request);
$data = array();
if ($function == $datacheck){
echo $updatecheck;
echo $datacheck;
}
if ($function == "3test" && $updatecheck > $datacheck ) {
$updatesearch="SELECT * FROM Feedtest WHERE id = '$updateid' ORDER BY id DESC";
$updatequery = mysql_query($updatesearch);
$data['id'] = $updateid;
while ($row = mysql_fetch_array($updatequery))
{
?>
<?php $data[]= $row['First Name']; ?>
<?php
}
echo json_encode($data);
}
?>
</div>
</ul>
first of all ,always use JSON.parse(data) instead of eval.It is considereda a good practice.
second thing is always try to debug your code by checking it in console or alerting.In your context,this is what is happening-:
$.ajax({
type: 'POST',
url: 'feedupdate.php',
data: {function: '3test', datacheck: var_numcheck},
dataType: "json",
success: function(data) {
var data = eval('(' + data + ')');
console.log("myData"+data)//debugging.check the pattern so that you can acces it the way you want!!!
for(var i=0;i< data.length;i++)
{
alldata += "<li>"+data[i][0]+"<li><hr>";
}
$('#datacheck').html(alldata);
});
}
For JSON.parse:
success: function(data) {
var data = JSON.parse(data);
console.log("myData"+data)//debugging.check the pattern so that you can acces it the way you want!!!
for(var i in data)
{
alldata += "<li>"+data[i].First Name+"<li><hr>";
}
$('#datacheck').html(alldata);
});
I'm making a simple voter that takes either a "like" vote or "dislike" vote. Then, I count the total number of likes and dislikes and output the total numbers. I figured out how to put in the votes using Jquery Ajax, but the number of votes do not update after I put in a vote. I would like to update the $numlike and $numdislike variables using Jquery Ajax.
Here is the PHP script pertaining to the output:
$like = mysql_query("SELECT * FROM voter WHERE likes = 1 ");
$numlike = 0;
while($row = mysql_fetch_assoc($like)){
$numlike++;
}
$dislike = mysql_query("SELECT * FROM voter WHERE likes = 0 ");
$numdislike = 0;
while($row = mysql_fetch_assoc($dislike)){
$numdislike++;
}
echo "$numlike like";
echo "<br>";
echo "$numdislike dislike";
UPDATE:
Jquery Ajax for uploading vote
<script>
$(document).ready(function(){
$("#voter").submit(function() {
var like = $('#like').attr('value');
var dislike = $('#dislike').attr('value');
$.ajax({
type: "POST",
url: "vote.php",
data: "like=" + like +"& dislike="+ dislike,
success: submitFinished
});
function submitFinished( response ) {
response = $.trim( response );
if ( response == "success" ) {
jAlert("Thanks for voting!", "Thank you!");
}
return false;
});
});
</script>
<form id="voter" method="post">
<input type='image' name='like' id='like' value='like' src='like.png'/>
<input type='image' name='dislike' id='dislike' value='dislike' src='dislike.png'/>
</form>
vote.php:
if ($_POST['like'])
{
$likeqry = "INSERT INTO test VALUES('','1')";
mysql_query($likeqry) or die(mysql_error());
echo "success";
}
if ($_POST['dislike'])
{
$dislikeqry = "INSERT INTO test VALUES('','0')";
mysql_query($dislikeqry) or die(mysql_error());
echo "success";
}
If you want to change current like or dislike number after clicking it you must return result instead of printing it ! return json result and echo this and change div innerHTML to see new result !
............
............
............
$dislike = mysql_query("SELECT * FROM voter WHERE likes = 0 ");
$numdislike = 0;
while($row = mysql_fetch_assoc($dislike)){
$numdislike++;
}
echo json_encode( array( $numlike, $numdislike ) ) ;
exit();
Now in your html code :
$.ajax({
type: "POST",
url: "vote.php",
context:$(this)
data: "like=" + like +"& dislike="+ dislike,
success: submitFinished(data)
});
function submitFinished( response ) {
response = $.parseJSON( response );
//Now change number of like and dilike but i don't know where are shown in your html
$('#like').attr('value',response[0]);
$('#dislike').attr('value',response[1]);
return false;
});
You can send a $_GET or $_POST variable to the file that you are calling with AJAX.
.load("google.com", "foo=bar", function(){
});