I have a table with one field which has 16 record. I wanna show them in a 4*4 table but i don't know how do it. My code shows them in one row.
<table class="table">
<thead>
<tr class="mybg">
<?php
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "SELECT * FROM tutors_students where tutor_id = ? and ok=1 ORDER BY date DESC ";
$q = $pdo->prepare($sql);
$q->execute(array($userid));
$data = $q->setFetchMode(PDO::FETCH_ASSOC);
foreach($q->fetchAll() as $k=>$v) { ?>
<th><?php echo $v['date'];?> </th>
<?php }
Database::disconnect();
?>
</tr>
</thead>
<tbody class="mybg1">
Add a counter, increase that in every loop;
Once you have 4 colums print a new row and reset the counter:
$cnt=0;
foreach($q->fetchAll() as $k=>$v) {
$cnt++;
echo '<th>'. $v['date'].'</th>';
if($cnt===4) {
echo "</tr><tr>";
$cnt=0;
}
}
Related
This is a tricky question to search, hence my post here. I have a a header that displays the sum of all the values in a column of a table that is printed below it. However the table is generated from a MYSQL table and the sum of the column values is calculated as it is generated. So somehow I have to have a variable printed but only after the table is generated and I am not sure how to pass the variables back up to the print statement so it doesn't always print out a 0
I feel like the solution is that the sum should call a script (Javascipt) that generates and prints the table returning the sum of columns to then be printed. But I am not sure how I would do this
echo "
<h3>EPL</h3>
<h5>Total Score: $total</h5>
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>"?>
<?php
require('db_config.php');
$tablename = $_SESSION['username'] . "_epl";
$_SESSION['tablename'] = $tablename;
$sql = "SELECT * FROM $tablename ORDER BY position_order";
$users = $mysqli->query($sql);
while($user = $users->fetch_assoc()){
$con = mysqli_connect('localhost', 'root', 'root', 'predictions');
$sql1 = "SELECT * FROM `predictions`.`".$tablename."` WHERE (CONVERT(`title` USING utf8) LIKE '%".$user['title']."%')";
$sql2 = "SELECT * FROM `predictions`.`epl` WHERE (CONVERT(`title` USING utf8) LIKE '%".$user['title']."%')";
$result = mysqli_query($con, $sql1);
$row = $result->fetch_assoc();
$position1 = $row['position_order'];
$result->close();
$result = mysqli_query($con, $sql2);
$row = $result->fetch_assoc();
$position2 = $row['position_order'];
$total += abs($position1-$position2);
?>
<tr id="<?php echo $user['id'] ?>">
<td><?php echo $user['position_order'] ?></td>
<td><?php echo $user['title'] ?></td>
<td><?php echo abs($position1-$position2); ?></td>
</tr>
<?php } ?>
</tbody>
</table>
To explain the table further, each user has their own table with the same format username_league, so I use some php code to grab the table. Additionally I have a base case table in this case 'epl' in which I compare the tables and calculate the scores based on the absolute difference in the column 'position_order'.
You should always aim for separation of your code and presentation. And beyond that, your database code is extremely inefficient. You're re-creating an entire database object for every instance of your original query.
Just put your PHP code before the HTML, or better yet in a separate file.
<?php
$total = 0;
require('db_config.php');
$tablename = $_SESSION['username'] . "_epl";
$_SESSION['tablename'] = $tablename;
$sql = "SELECT id, position_order, title FROM `$tablename` ORDER BY position_order";
$users_result = $mysqli->query($sql);
while($user = $users_result->fetch_assoc()) {
$users[] = $user;
}
foreach ($users as $user) {
$sql1 = "
SELECT position_order FROM `$tablename` WHERE CONVERT(`title` USING utf8) LIKE '%$user[title]%' LIMIT 1
UNION
SELECT position_order FROM `epl` WHERE CONVERT(`title` USING utf8) LIKE '%$user[title]%' LIMIT 1
";
$result = $mysqli->query($sql1);
$row = $result->fetch_assoc();
$position1 = $row['position_order'];
$user["position1"] = $position1;
$row = $result->fetch_assoc();
$position2 = $row['position_order'];
$user["position2"] = $position2;
$total += abs($position1 - $position2);
}
?>
There you are; using a single database object, one third fewer queries, all your values in an array. They're ready to use later in the file, or in your separate HTML view:
<h3>EPL</h3>
<h5>Total Score: <?=$total?></h5>
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>
<?php foreach($users as $user):?>
<tr id="<?=$user['id'] ?>">
<td><?=$user['position_order'] ?></td>
<td><?=$user['title'] ?></td>
<td><?=abs($user["position1"]-$user["position2"]); ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
I don't know enough about the structure here, but I'd be very surprised if you couldn't make this a single database query.
Output buffering is your friend! Simply call ob_start before outputting the table i.e.
ob_start();
echo "
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>"?>
...
then once you have done generating the table, you can collect the output of the table's content using ob_get_clean, output the header and then the table content:
...
$table = ob_get_clean();
echo "<h3>EPL</h3>
<h5>Total Score: $total</h5>";
echo $table;
Hello I am trying to make a little game, where I need to add some point given for how a drink looks and taste.
There will be 7 people giving points, so in php i need to create a table for each date and only show 1 name for each of the players, but I need the points to be added for every row with the same name:
Here is what I have so far.
<?php
$pdo = Logbase::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = 'SELECT DISTINCT start FROM grade';
$q = $pdo->query($sql);
$q->setFetchMode(PDO::FETCH_ASSOC);?>
<?php while ($r = $q->fetch()): ?>
<table class="blueTable" align="center">
<thead>
<tr>
<th> <?php echo $r['start'] ?></th>
<th></th>
</tr>
</thead>
<?php endwhile; ?>
<tbody>
<?php
$pdo = Logbase::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = 'SELECT * FROM grade group by start, name';
$q = $pdo->query($sql);
$q->setFetchMode(PDO::FETCH_ASSOC);
?>
<?php while ($r = $q->fetch()): ?>
<tr>
<td> <?php echo $r['name'] ?></td>
<td> <?php echo $r['drinks_fla'] + $r['drinks_view'] + $r['food'] +
$r['sam'] ?></td>
</tr>
<?php endwhile; ?>
</tbody>
</table>
In my result I can see 1 name for each player, but only 1 rows has been added (the first), so I quess I need a loop or something in my mysql?
Dennis --------10 point
Michael--------6 point
I want to see
Dennis 24 point
Michale 12 points
id---start--- name-----drinks_fla---drinks_view
1---31.07-2017---dennis---5---5
1---31.07-2017---dennis---4---3
1---31.07-2017---dennis---5---2
2---31.07-2017---Michale---5---1
2---31.07-2017---Michael---2---4
$sql = 'SELECT * FROM grade group by start, name';
You have grouped your Results from MySQL, so only one Row will be called for the Properties of the Group.
Try "sum()" to get sum of the selected Columns you want:
$sql = 'SELECT name as name,sum(sum(drinks_fla),sum(drinks_view)) as sum FROM grade group by start, name';
MySQL will call all Rows, ordered by the first Property. All Rows with the same first Property are sorted with the second one.
Example:
id---start--- name-----drinks_fla---drinks_view
1---31.07-2017---dennis---5---5
1---31.07-2017---dennis---4---3
1---31.07-2017---dennis---5---2
2---31.07-2017---Michale---5---1
2---31.07-2017---Michael---2---4
Result:
name----sum
dennis----24
Michale----6
Michael----6
Hello I am doing a query for search using like clause it work and I want to add a link on the result and when I click the link it will display each file. I am using session for the link but when 3 records that display on search which I'm using like example:
I search grace and it display 3 records that start with Grace
1 - Grace Napoles
2 - Grace Urgel
3 - Grace Smith
And I want to add link when i click the click it will redirect another page that display there individual record A am using the code below which have the problem display only the last record
3 - Grace Smith will display even i click the 1 or 2 i need your help if i click the 1 or 2 or 3 it display each records thanks
<?php
session_start();
include'database.php';
$ssmain = $_SESSION['sessionsmain'];
$conn = mysqli_connect($server, $dbusername, $dbpassword, $database);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM employee where E_ID = '$ssmain' || LastName like '%$ssmain' || FirstName like '%$ssmain'";
$no=0;
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) { ?>
<table class="table table-hover">
<thead>
<tr>
<th>ID</th>
<th>Last Name</th>
<th>First Name</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result)) {
$no++;
?>
<tr>
<td><?php $_SESSION['ttid'] = $row['E_ID']; echo"{$row['E_ID']}"; ?></td>
<td><?php echo"{$row['FirstName']}"; ?></td>
<td><?php echo"{$row['LastName']}"; ?></td>
</tr>
<?php
}
}
else
{
header('location: error404.php');
}
?>
</tbody>
</table>
You're only ever going to get the last result (ie: 3 - Grace Smith) because you're overwriting the $_SESSION['ttid'] value in each iteration.
You should append a GET query string to your link and adjust your code. For example;
<td><a href="employeerecord.php?id=<?php echo $row['E_ID']; ?>">
<?php echo $row['E_ID']; ?> - <?php echo implode(" ", array($row['FirstName'], $row['LastName'])); ?>
</a>
</td>
Now in your query, look for the query string.
if( isset($_GET['id']) AND ctype_digit($_GET['id']) ) {
//Query for the specific E_ID
$sql = "SELECT `FirstName`,`LastName` FROM employee where E_ID = ?";
$objGet = mysqli_prepare($conn, $sql);
mysqli_stmt_bind_param($objGet, 'i', $_GET['id']);
mysqli_stmt_execute($objGet);
mysqli_stmt_bind_result($objGet, $strFirstName, $strLastName);
echo 'Viewing: '. $strFirstName .' '. $strLastName;
} else {
//Query all records to show to the user
}
I have this php/html code that echos a column from a mysql table called "tickets".
These are the 3 columns in the table (member_id, ticket_id, ticket_result).
I want to be able to grab the info from the other columns in a specific row and echo that with the foreach loop. I just don't know how I would be able to do that because you can only have 1 array in a foreach loop so if I was to make add this line to the PHP Code I don't see how I could echo it in the foreach loop.
$me3 = array();
$me2[] = $row->ticket_result;
PHP Code:
public function tickets() {
$this->db_connection = new mysqli('', '', '', '');
$sql = "SELECT ticket_result
FROM tickets
WHERE member_id = '1'";
$query = $this->db_connection->query($sql);
$me2 = array();
while ($row = $query->fetch_object()) {
$me2[] = $row->ticket_result;
}
return $me2;
}
}
HTML Code:
<?php $me2 = $classLogin->tickets(); ?>
<?php foreach($me2 as $value) { ?>
<table>
<thead>
<th>Result</th>
<th>ID</th>
</thead>
<tr>
<td><?php echo $value; ?> </td>
<td> </td>
<?php } ?>
</tr>
</table>
You're only selecting one column of your table:
$sql = "SELECT ticket_result FROM tickets WHERE member_id = '1'";
Your statement should look like this:
$sql = "SELECT member_id, ticket_id, ticket_result FROM tickets WHERE member_id = '1'";
Or:
$sql = "SELECT * FROM tickets WHERE member_id = '1'";
Then you can retrieve your data with this:
while ($row = $query->fetch_object()) {
$me2[$row->ticket_id]['ticket_result'] = $row->ticket_result;
$me2[$row->ticket_id]['member_id'] = $row->member_id;
}
So you'll have an array ($me2) that contains keys according to your ticked_ids and each key is an array with the keys ticket_result and member_id which contain that data from your db.
Then you can implement your foreach like this:
foreach($me2 as $key => $value) {
echo $key;
echo $value['ticket_result'];
echo $value['member_id'];
}
Also, if the HTML you have to print is not that much, I suggest you better use echo and concatenate a string withing a single php clause rather than opening and closing multiple php tags for every little php code you have to execute, your code would look like this:
<?php
$me2 = $classLogin->tickets();
echo
'<table>
<thead>
<th>Result</th>
<th>ID</th>
</thead>';
foreach($me2 as $key => $value) {
echo
'<tr>
<td>'.$value['ticket_result'].'</td>
<td>'.$value['member_id'].'</td>
</tr>';
}
echo '</table>';
?>
TEST SITE Look here to see code in action
I have two arrays which when echo'd show exactly what i want it to (look at the test site). I'm trying to get them both into a html table but it is only showing the last entry. I have shoved the entire array code into the table and it works fine (although there all in the same row and not separated) but as it is being used in a html email i'm not sure if this will be safe? I'm sorry if this is a really simple fix i'm new to php/mysql so the simple things seem impossible at the moment. I also know i could no doubt combine the two arrays but im on a KISS mantra at the moment and this is the easiest for me to understand. Any help would be appreciated. Thanks.
<?php
//Get Order Codes
foreach ($ids as $id) {
$sqlcode = "SELECT od_code FROM tbl_order_code WHERE pd_id = $id LIMIT 1";
$result = mysql_query($sqlcode);
while($row = mysql_fetch_assoc($result)) {
$codes['codes'] = $row['od_code'];
}
echo "".$codes['codes']."<br />";
}
//Get Product Name
foreach ($ids as $id) {
$sqlname = "SELECT pd_name FROM tbl_product WHERE pd_id = $id";
$result = mysql_query($sqlname);
while($row = mysql_fetch_assoc($result)) {
$names['names'] = $row['pd_name'];
}
echo "".$names['names']."<br />";
}
?>
<table width='550' border='1' align='center' cellpadding='5' cellspacing='1'>
<tr>
<td>Description</td>
<td>Code</td>
</tr>
<tr>
<td> <?php echo "". $names['names'].":"."<br>"?> </td>
<td> <?php echo "". $codes['codes']."<br>"?> </td>
</tr>
</table>
A better solution
Change your logic so that you only use one SQL query and make use of a join.
SELECT p.pd_name,
oc.od_code
FROM tbl_product p
LEFT JOIN tbl_order_code oc ON oc.pd_id = p.pd_id
WHERE p.pd_id = $id
So this should be the following using PDO:
$dbh = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
$stmt = $dbh->prepare("
SELECT p.pd_name,
oc.od_code
FROM tbl_product p
LEFT JOIN tbl_order_code oc ON oc.pd_id = p.pd_id
WHERE p.pd_id = ?");
if ($stmt->execute(array($id))) {
while ($row = $stmt->fetch()) {
// print out table rows here
}
}
Immediate fix (yuck)
This should solve your immediate problem, but there is a much better way of doing this.
<?php
foreach ($ids as $id) {
$sqlcode = "SELECT od_code FROM tbl_order_code WHERE pd_id = $id LIMIT 1";
$result = mysql_query($sqlcode);
$codes = array();
while($row = mysql_fetch_assoc($result)) {
$codes[] = $row['od_code'];
}
//Get Product Name
foreach ($ids as $id) {
$sqlname = "SELECT pd_name FROM tbl_product WHERE pd_id = $id";
$result = mysql_query($sqlname);
$names = array();
while($row = mysql_fetch_assoc($result)) {
$names[] = $row['pd_name'];
}
}
?>
<table width='550' border='1' align='center' cellpadding='5' cellspacing='1'>
<tr>
<td>Description</td>
<td>Code</td>
</tr>
<?php foreach($names as $key => $name): ?>
<tr>
<td> <?php echo $name .":"."<br>"?> </td>
<td> <?php echo $codes[$key]."<br>"?> </td>
</tr>
<?php endforeach; ?>
</table>
$names['names'][] = $row['pd_name'];
<td> <?php foreach($names['names'] as $name){ echo "". $name.":"."<br>" } ?> </td>
Or as suggested in comments:
while($row = mysql_fetch_assoc($result)) {
$names['names'] = $row['pd_name'];
$codes['codes'] = $row['pd_code'];
?>
<tr>
<td> <?php echo "". $names['names'].":"."<br>"?> </td>
<td> <?php echo "". $codes['codes']."<br>"?> </td>
</tr>
<?php } ?>
Please try to use PDO instead for interacting with mysql http://net.tutsplus.com/tutorials/php/why-you-should-be-using-phps-pdo-for-database-access/
You have to iterate through the array within the table, the same way you do it above the table-tags.
you are using
foreach($ids as $id)
make table to be populated inside foreach
or else use 2d array $name and $codes and count the array size and loop your table structure for count no of times