Put link and session on array - php

Question

Hello I am doing a query for search using like clause it work and I want to add a link on the result and when I click the link it will display each file. I am using session for the link but when 3 records that display on search which I'm using like example:
I search grace and it display 3 records that start with Grace
1 - Grace Napoles
2 - Grace Urgel
3 - Grace Smith
And I want to add link when i click the click it will redirect another page that display there individual record A am using the code below which have the problem display only the last record
3 - Grace Smith will display even i click the 1 or 2 i need your help if i click the 1 or 2 or 3 it display each records thanks
<?php
session_start();
include'database.php';
$ssmain = $_SESSION['sessionsmain'];
$conn = mysqli_connect($server, $dbusername, $dbpassword, $database);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM employee where E_ID = '$ssmain' || LastName like '%$ssmain' || FirstName like '%$ssmain'";
$no=0;
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) { ?>
<table class="table table-hover">
<thead>
<tr>
<th>ID</th>
<th>Last Name</th>
<th>First Name</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result)) {
$no++;
?>
<tr>
<td><?php $_SESSION['ttid'] = $row['E_ID']; echo"{$row['E_ID']}"; ?></td>
<td><?php echo"{$row['FirstName']}"; ?></td>
<td><?php echo"{$row['LastName']}"; ?></td>
</tr>
<?php
}
}
else
{
header('location: error404.php');
}
?>
</tbody>
</table>

Answer 1

You're only ever going to get the last result (ie: 3 - Grace Smith) because you're overwriting the $_SESSION['ttid'] value in each iteration.
You should append a GET query string to your link and adjust your code. For example;
<td><a href="employeerecord.php?id=<?php echo $row['E_ID']; ?>">
<?php echo $row['E_ID']; ?> - <?php echo implode(" ", array($row['FirstName'], $row['LastName'])); ?>
</a>
</td>
Now in your query, look for the query string.
if( isset($_GET['id']) AND ctype_digit($_GET['id']) ) {
//Query for the specific E_ID
$sql = "SELECT `FirstName`,`LastName` FROM employee where E_ID = ?";
$objGet = mysqli_prepare($conn, $sql);
mysqli_stmt_bind_param($objGet, 'i', $_GET['id']);
mysqli_stmt_execute($objGet);
mysqli_stmt_bind_result($objGet, $strFirstName, $strLastName);
echo 'Viewing: '. $strFirstName .' '. $strLastName;
} else {
//Query all records to show to the user
}