How to get data from tables linked to a single user - php

First of all thank you for help me in advance.
I am looking to make a system were i am using 1 mysql DB and 2 tables or more and connect the tables to a user in a session. So lets suppose that the user logs in in a location, after login he can view from another table the data relative to this user, like a support ticket system (very simple one).
So i created a login system with sessions and then i want to display from another table only the data from that single user but when i do this i get all the data from the table, other users can see other users submissions and i wanna stop that and make it single user, single data display from that user only.
So here is the codes i am using:
<?php
// Validate Client Details
session_start();
if(!isset($_SESSION["user_username"]))
{
header("location:index.php?action=login");
}
?>
Then i got this code to display the records:
<?php
$connect = mysqli_connect("localhost", "root", "root", "helpdesk");
$sql = "SELECT * FROM users INNER JOIN tickets ON users.user_id = tickets.ticket_id";
$result = mysqli_query($connect, $sql);
?>
It works great but displays all and not just the single user details.
The Output i am using:
<table class="table table-striped">
<tr>
<th>Ticket ID</th>
<th>Client Username</th>
<th>Ticket Issue</th>
<th>Message</th>
<th>Priority</th>
</tr>
<?php
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["ticket_id"]; ?></td>
<td><?php echo $row["user_username"];?></td>
<td><?php echo $row["ticket_issue"]; ?></td>
<td><?php echo $row["ticket_message"]; ?></td>
<td><?php echo $row["ticket_priority"]; ?></td>
</tr>
<?php
}
}
?>
</table>
I hope someone can help me on this, my best regards and thanks in advance.

You missed where condition
$name=$_SESSION['user_username']
$sql = "SELECT * FROM users INNER JOIN tickets ON users.user_id = tickets.ticket_id where user_username='$name'";

Related

Display most recent logs for every user

How to display most recent logs for every user?
My database tables are user_log_id, username, login_date, logout_date, user_id. Can you please help me with the query? Thank you
Heres my code:
<?php
$user_query = $conn->query("select * from user_log order by user_log_id DESC ")or die(mysql_error());
while($row = $user_query->fetch()){
$id = $row['user_log_id'];
?>
<tr>
<td><?php echo $row['login_date']; ?></td>
<td><?php echo $row['logout_date']; ?></td>
<td><?php echo $row['username']; ?></td>
</tr>
<?php } ?>
The MySql query you used is correct for getting recent logs. But if you need to get only for specific users or only for logged in users, you have to add a where clause in the query.
select * from user_log where username=".$row['username']." order by user_log_id DESC

Print calculated Value of variable before its been calculated

This is a tricky question to search, hence my post here. I have a a header that displays the sum of all the values in a column of a table that is printed below it. However the table is generated from a MYSQL table and the sum of the column values is calculated as it is generated. So somehow I have to have a variable printed but only after the table is generated and I am not sure how to pass the variables back up to the print statement so it doesn't always print out a 0
I feel like the solution is that the sum should call a script (Javascipt) that generates and prints the table returning the sum of columns to then be printed. But I am not sure how I would do this
echo "
<h3>EPL</h3>
<h5>Total Score: $total</h5>
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>"?>
<?php
require('db_config.php');
$tablename = $_SESSION['username'] . "_epl";
$_SESSION['tablename'] = $tablename;
$sql = "SELECT * FROM $tablename ORDER BY position_order";
$users = $mysqli->query($sql);
while($user = $users->fetch_assoc()){
$con = mysqli_connect('localhost', 'root', 'root', 'predictions');
$sql1 = "SELECT * FROM `predictions`.`".$tablename."` WHERE (CONVERT(`title` USING utf8) LIKE '%".$user['title']."%')";
$sql2 = "SELECT * FROM `predictions`.`epl` WHERE (CONVERT(`title` USING utf8) LIKE '%".$user['title']."%')";
$result = mysqli_query($con, $sql1);
$row = $result->fetch_assoc();
$position1 = $row['position_order'];
$result->close();
$result = mysqli_query($con, $sql2);
$row = $result->fetch_assoc();
$position2 = $row['position_order'];
$total += abs($position1-$position2);
?>
<tr id="<?php echo $user['id'] ?>">
<td><?php echo $user['position_order'] ?></td>
<td><?php echo $user['title'] ?></td>
<td><?php echo abs($position1-$position2); ?></td>
</tr>
<?php } ?>
</tbody>
</table>
To explain the table further, each user has their own table with the same format username_league, so I use some php code to grab the table. Additionally I have a base case table in this case 'epl' in which I compare the tables and calculate the scores based on the absolute difference in the column 'position_order'.
You should always aim for separation of your code and presentation. And beyond that, your database code is extremely inefficient. You're re-creating an entire database object for every instance of your original query.
Just put your PHP code before the HTML, or better yet in a separate file.
<?php
$total = 0;
require('db_config.php');
$tablename = $_SESSION['username'] . "_epl";
$_SESSION['tablename'] = $tablename;
$sql = "SELECT id, position_order, title FROM `$tablename` ORDER BY position_order";
$users_result = $mysqli->query($sql);
while($user = $users_result->fetch_assoc()) {
$users[] = $user;
}
foreach ($users as $user) {
$sql1 = "
SELECT position_order FROM `$tablename` WHERE CONVERT(`title` USING utf8) LIKE '%$user[title]%' LIMIT 1
UNION
SELECT position_order FROM `epl` WHERE CONVERT(`title` USING utf8) LIKE '%$user[title]%' LIMIT 1
";
$result = $mysqli->query($sql1);
$row = $result->fetch_assoc();
$position1 = $row['position_order'];
$user["position1"] = $position1;
$row = $result->fetch_assoc();
$position2 = $row['position_order'];
$user["position2"] = $position2;
$total += abs($position1 - $position2);
}
?>
There you are; using a single database object, one third fewer queries, all your values in an array. They're ready to use later in the file, or in your separate HTML view:
<h3>EPL</h3>
<h5>Total Score: <?=$total?></h5>
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>
<?php foreach($users as $user):?>
<tr id="<?=$user['id'] ?>">
<td><?=$user['position_order'] ?></td>
<td><?=$user['title'] ?></td>
<td><?=abs($user["position1"]-$user["position2"]); ?></td>
</tr>
<?php endforeach; ?>
</tbody>
</table>
I don't know enough about the structure here, but I'd be very surprised if you couldn't make this a single database query.
Output buffering is your friend! Simply call ob_start before outputting the table i.e.
ob_start();
echo "
<table class='table table-bordered'>
<tr>
<th>#</th>
<th>Name</th>
<th>Score</th>
</tr>
<tbody class='row_position'>"?>
...
then once you have done generating the table, you can collect the output of the table's content using ob_get_clean, output the header and then the table content:
...
$table = ob_get_clean();
echo "<h3>EPL</h3>
<h5>Total Score: $total</h5>";
echo $table;

Using a SELECT Query to retrieve data from a database using a multidimensional array

I want to use a SELECT Query to retrieve data from a database, that displays the list of categories and the number of DVDs in each category using a multidimensional array.
Table Name: dvds_table
dv_id dv_caid dv_name
1 4 Matrix Reloaded
2 2 Johnny English
3 4 The Recruit
4 4 Minority Report
5 3 Two Weeks Notice
6 2 Bend It Like Beckham
Table Name: categories_table
ca_id ca_name
2 Comedy
4 Action
1 Drama
3 Romance
5 TV
This is what I've come up with so far, excuse my basic knowledge:
<?php
$link = mysqli_connect("localhost", "root", "", "dvddb");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$categories=getNumDvdsInCategories();
function getNumDvdsInCategories() {
$this->db->select('*');
$this->db->from('categories_table');
$this->db->order_by('ca_name', 'DESC');
$query = $this->db->get();
return $query->result();
}
$this->load->model("model");
$data['results'] = $this->model->list_categories();
$this->load->view('categories_list_view', $data);
?>
<html>
<body>
<table border=1>
<tr>
<td>Category ID</td>
<td>Category Name</td>
<td>Num. DVDs</td>
</tr>
<?php foreach ($categories as $category) { ?>
<tr>
<td><?php echo $category['ca_id']; ?></td>
<td><?php echo $category['ca_name']; ?></td>
<td><?php echo $category['num']; ?></td>
</tr>
<?php } ?>
</table>
</body>
</html>
I Belief that this code will give the results you are looking for. Please Google for information about mysql COUNT which counts the number of rows in a selection, and LEFT JOIN which joins rows from two tables together in a selection.
I've tried to keep as much from the original code in tact. Only the query part has changed. I can advice you to read-up about the SQL.
You can play around with the AS aliases or removed them. Please note they will affect the $catetory key names. And maybe you want to remove the ID from the selection. But that's up to you.!
<?php
// * These where the create queries that I have used to make a similar table as you.
// create table dvds_table ( dv_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT, dv_caid INT NOT NULL, FOREIGN KEY (dv_caid) references categories_table(ca_id), dv_name varchar(20));
// create table categories_table (ca_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT, ca_name varchar(20));
$link = mysqli_connect('localhost', 'root', '', 'dvddb');
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// * use $sql example below if you dont want the ID (Then also remove $category['ID'] in your HTML).
// * Also you can remove the AS aliases or rename them as you see fit (then also change the $category key names).
// $sql = 'SELECT categories_table.ca_name AS Category, COUNT(dvds_table.dv_caid) AS Amount FROM categories_table LEFT JOIN dvds_table ON dvds_table.dv_caid = categories_table.ca_id GROUP BY categories_table.ca_name ORDER BY categories_table.ca_name DESC;';
$sql = 'SELECT categories_table.ca_id AS ID,
categories_table.ca_name AS Category,
COUNT(dvds_table.dv_caid) AS Amount
FROM categories_table
LEFT JOIN dvds_table
ON dvds_table.dv_caid = categories_table.ca_id
GROUP BY categories_table.ca_id
ORDER BY categories_table.ca_name DESC;';
$result = mysqli_query($link, $sql);
?>
<html>
<body>
<table border=1>
<tr>
<td>Category ID</td>
<td>Category Name</td>
<td>Num. DVDs</td>
</tr>
<?php foreach ($result as $category) { ?>
<tr>
<td><?php echo $category['ID']; ?></td>
<td><?php echo $category['Category']; ?></td>
<td><?php echo $category['Amount']; ?></td>
</tr>
<?php } ?>
</table>
</body>
</html>
<?php
mysqli_free_result($result);
mysqli_close($link);
?>

Put link and session on array

Hello I am doing a query for search using like clause it work and I want to add a link on the result and when I click the link it will display each file. I am using session for the link but when 3 records that display on search which I'm using like example:
I search grace and it display 3 records that start with Grace
1 - Grace Napoles
2 - Grace Urgel
3 - Grace Smith
And I want to add link when i click the click it will redirect another page that display there individual record A am using the code below which have the problem display only the last record
3 - Grace Smith will display even i click the 1 or 2 i need your help if i click the 1 or 2 or 3 it display each records thanks
<?php
session_start();
include'database.php';
$ssmain = $_SESSION['sessionsmain'];
$conn = mysqli_connect($server, $dbusername, $dbpassword, $database);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM employee where E_ID = '$ssmain' || LastName like '%$ssmain' || FirstName like '%$ssmain'";
$no=0;
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) { ?>
<table class="table table-hover">
<thead>
<tr>
<th>ID</th>
<th>Last Name</th>
<th>First Name</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result)) {
$no++;
?>
<tr>
<td><?php $_SESSION['ttid'] = $row['E_ID']; echo"{$row['E_ID']}"; ?></td>
<td><?php echo"{$row['FirstName']}"; ?></td>
<td><?php echo"{$row['LastName']}"; ?></td>
</tr>
<?php
}
}
else
{
header('location: error404.php');
}
?>
</tbody>
</table>
You're only ever going to get the last result (ie: 3 - Grace Smith) because you're overwriting the $_SESSION['ttid'] value in each iteration.
You should append a GET query string to your link and adjust your code. For example;
<td><a href="employeerecord.php?id=<?php echo $row['E_ID']; ?>">
<?php echo $row['E_ID']; ?> - <?php echo implode(" ", array($row['FirstName'], $row['LastName'])); ?>
</a>
</td>
Now in your query, look for the query string.
if( isset($_GET['id']) AND ctype_digit($_GET['id']) ) {
//Query for the specific E_ID
$sql = "SELECT `FirstName`,`LastName` FROM employee where E_ID = ?";
$objGet = mysqli_prepare($conn, $sql);
mysqli_stmt_bind_param($objGet, 'i', $_GET['id']);
mysqli_stmt_execute($objGet);
mysqli_stmt_bind_result($objGet, $strFirstName, $strLastName);
echo 'Viewing: '. $strFirstName .' '. $strLastName;
} else {
//Query all records to show to the user
}

retrieving and echoing multiple values from mysql column

I have created these 3 columns in my mysql table so I can have a list of each users transactions.
ticket_date, ticket_num, ticket_result
I also created a function to echo the value in those columns and it worked successfully.
function.php:
$sql = "SELECT *
FROM members
WHERE user_id = '{$_SESSION['user_id']}'";
$query = $this->db_connection->query($sql);
while ($row = $query->fetch_object()) {
global $me, $me2, $date;
$me = $row->ticket_num;
$me2 = $row->ticket_result;
$date = $row->ticket_date;
}
transactions.php
<table class="table">
<thead>
<th>Date</th>
<th>Ticket ID</th>
<th>Result</th>
</thead>
<tr>
<td><?php echo $date; ?> </td>
<td><?php echo $me; ?> </td>
<td><?php echo $me2; ?> </td>
</tr>
</table>
My problem now is that if a user has more than one transaction how would I be able to echo each value from a particular column separately. I am trying to echo each transaction into a .
Would I be able to store each value as an array so I could call it like this?
$row->ticket_num['0']
EDIT: I meant to ask how can I store the transactions into their respective columns. Such as storing more than one $ticket_date that apply to each transaction. Could I store information into the columns as an array so I can call each transaction using the array pointer?
I think the best thing to do, would be not to use global variables for this, unless there is any reason that your function can't return this data, i.e. it's returning something else. You could have something like this in your function.php:
$sql = "SELECT *
FROM members
WHERE user_id = '{$_SESSION['user_id']}'";
$query = $this->db_connection->query($sql);
$return = array();
while ($row = $query->fetch_object()) {
array_push($return, array($row->ticket_num, $row->ticket_result, $row->ticket_date ));
}
return $return
Then you can do this in your transactions.php:
<table class="table">
<thead>
<th>Date</th>
<th>Ticket ID</th>
<th>Result</th>
</thead>
<?php
$ticket = Whatever_Function();
foreach($ticket as $t){
echo"<tr> <td> ".$t[0]." </td><td>".$t[1]."</td><td>".$t[2]."</td></tr>";
}
?>
</table>
Edit
In relation to your additional question in the comments, a database structure like this should be set up:
By doing this, you are separating it, so that every table belongs to one thing or action. These can then be related to each other using an SQL Join like this:
SELECT * FROM Transactions tr
JOIN Users u ON u.UID = tr.UID
JOIN Tickets ti ON ti.TID = tr.TID
By looking at the above SQL code snippet, you should be able to see how it matches up the columns on the different tables. This creates one big virtual table that you can then search for stuff with, where their column names prepended with their given pseudonyms.
So if you wanted to get the email address of everyone that bought the ticket whose price was over £20, even though the tables you need aren't directly connected you could do:
SELECT u.email FROM Transactions tr
JOIN Users u ON u.UID = tr.UID
JOIN Tickets ti ON ti.TID = tr.TID
WHERE ti.Price > 20
Do something like this:
global $me, $me2, $date;
while ($row = $query->fetch_object()) {
$me[] = $row->ticket_num;
$me2[] = $row->ticket_result;
$date[] = $row->ticket_date;
}
transactions.php
<table class="table">
<thead>
<th>Date</th>
<th>Ticket ID</th>
<th>Result</th>
</thead>
<?php foreach($me as $k => $m){
echo "<tr>";
echo "<td>".$date[$k]."</td>";
echo "<td>".$m."</td>";
echo "<td>".$me2[$k]."</td>";
echo "</tr>";
?>
</table>

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