I have a route with parameter
Route::get('forum/{ques}', "ForumQuestionsController#show");
Now I want a route something like
Route::get('forum/add', ['middleware' => 'auth:student', 'uses' => "ForumQuestionsController#add"]);
well when I hit localhost:800/forum/add I get routed to ForumQuestionsController#show instead of ForumQuestionsController#add
Well I know I can handle this in show method of ForumQuestionsController and return a different view based on the paramter. But I want it in this way.
First give this one
Route::get('forum/add', ['middleware' => 'auth:student', 'uses' => "ForumQuestionsController#add"]);
Then the following
Route::get('forum/{ques}', "ForumQuestionsController#show");
Another Method (using Regular Expression Constraints)
Route::pattern('ques', '[0-9]+');
Route::get('forum/{ques}', "ForumQuestionsController#show");
If ques is a number it will automatically go to the show method, otherwise add method
You can adjust the order of routes to solve the problem.
Place add before show , and then laravel will use the first match as route .
Route::get('forum/add', ['middleware' => 'auth:student', 'uses' => "ForumQuestionsController#add"]);
Route::get('forum/{ques}', "ForumQuestionsController#show");
I think your {ques} parameter do not get properly. You can try this:
Route::get('forum/show/{ques}', "ForumQuestionsController#show");
Route::get('forum/add', ['middleware' => 'auth:student', 'uses' => "ForumQuestionsController#add"]);
If you use any parameters in show method add parameters:
public function show($ques){
}
Related
I am trying to pass 3 variables values inside an html link that uses route to access a named routed with this code:
{{$nomos->name}}
also the route function is
Route::get('gegonota/{gid?}/{cid?}/{nid?}', ['uses' => 'GegonosController#index', 'as' => 'gegonota']);
but it doesnt work right.
How can i do it.
thanks
you can try this.
{{$nomos->name}}
Just remove ? from your routes params so it will be :
Route::get('gegonota/{gid}/{cid}/{nid}', [
'uses' => 'GegonosController#index',
'as' => 'gegonota'
]);
if you want to use ? you need to provide a default value check the docs
and if you use Laravel v5.4 you need to change your route to :
Route::get('gegonota/{gid}/{cid}/{nid}', [
'uses' => 'GegonosController#index'
])->name('gegonota');
I want my user to access its profile edit page by URL: /profile/slug/edit, where slug means $user->slug.
My web.php contans:
Route::group(['middleware' => 'auth'], function () {
Route::get('/profile/{slug}', [
'uses' => 'ProfilesController#index',
'as' => 'profile'
]);
Route::get('/profile/{slug}/edit', [
'uses' => 'ProfilesController#edit',
'as' => 'profile.edit'
]);
How to call ProfilesController#edit from view, how to pass parameters correctly? Tried:
<a href="{{route('profile', ['slug'=> Auth::user()->slug],'edit')}}">
Edit your profile</a>
Here is how I would do it..
Route::group(['middleware' => 'auth'], function () {
Route::get('/profile/{slug}', 'ProfilesController#index')->name('profile');
Route::get('/profile/{slug}/edit', 'ProfilesController#edit')->name('profile.edit');
});
And then in your view, you can use..
Edit your profile
As you can see, first we have to give the route() the route name we are interested in, in your case it's profile.edit that is the target route, and we know from our routes file that it's missing the slug value, so we provide it the slug value as the second argument (if there are more missing values, the second argument should be an array).
It takes some practice and time but try different ways to see what makes your code more readable. The number of lines doesn't matter that much to the computer, write the code so you can easily read and understand it if you want to change something a year or two from now.
You can use following codeline
Edit your profile
Your routes definitions seems to be fine.
Plus if you want to add some get params, you can add directly in the array passed as the second argument
Edit your profile
Hope this helps. :)
what I'm trying to do is set it up so that the user can go to "/project/index" ("/" being the route ofc) but I'm not quite sure how to do it in laravel?
What I currently have:
Routing:
Route::get('project.index', array('as' => 'project/index', 'uses' => 'ProjectController#indexPage'));
Also in routing:
View::addLocation('project'); //Project View
View::addNamespace('project', 'project');
In my Project Controller:
public function indexPage()
{
return View::make('index', array('pageTitle' => 'Project Index'));
}
Any ideas? Thanks in advance.
PS: It's Laravel 4
You have your routing a little wrong. Try out the following
Route::get('project/index', ['as' => 'project.index', 'uses' => 'ProjectController#index']);
So the first parameter into the Route::get() function should be the URL the user is visiting for example http://example.com/project/index. The as key in the array provided is the name you're giving to the route.
By giving the route a name you can use this throughout your application, rather than using the url the user is visiting. For example you might want to generate a link to your route
Link
This will generate a link to http://example.com/project/index. This makes it convenient in the future should you wish to change your URLs without changing lots of links throughout your view files.
Route::get('foobar/index', ['as' => 'project.index', 'uses' => 'ProjectController#index']);
The URL generated through route('project/index') would now be http://example.com/foobar/index
Checkout the routing documentation for further information http://laravel.com/docs/4.2/routing
Well I have a little problem, and I don't know if I'm blind to find it inside the Laravel 4 Documentation or it doesn't even exist ...
I have two routes that route to one and the same controller function...
//List blog_posts
Route::get('/', 'BlogController#listPosts');
//List deleted blog_posts
Route::get('/bin', 'BlogController#listPosts');
Now, is there a way to determine inside the 'listPosts' function what route was hit ?
Of course I could create another function inside 'BlogController' but I dont like that idea ^^
You can try using Route::current(). It will return an object of type Illuminate\Routing\Route which has a method on it called getUri:
var_dump(Route::current()->getUri());
If you gave your routes a name, you can also make a decision based off of that:
var_dump(Route::currentRouteName());
You can also use named routes:
Route::get('/', ['as' => 'listIndex', 'uses' => 'BlogController#listPosts']);
Route::get('/bin', ['as' => 'listBin', 'uses' => 'BlogController#listPosts']);
This will set Route::currentRouteName() which you could if/else on.
When defining a route in Laravel 4 is it possible to define multiple URI paths within the same route?
presently i do the following:
Route::get('/', 'DashboardController#index');
Route::get('/dashboard', array('as' => 'dashboard', 'uses' => 'v1\DashboardController#index'));
but this defeats my purpose, i would like to do something like
Route::get('/, /dashboard', array('as' => 'dashboard', 'uses' => 'DashboardController#index'));
I believe you need to use an optional parameter with a regular expression:
Route::get('/{name}', array(
'as' => 'dashboard',
'uses' => 'DashboardController#index')
)->where('name', '(dashboard)?');
* Assuming you want to route to the same controller which is not entirely clear from the question.
* The current accepted answer matches everything not just / OR /dashboard.
I find it interesting for curiosity sake to attempt to solve this question posted by #Alex as a comment under #graemec's answer to post a solution that works:
Route::get('/{name}', [
'as' => 'dashboard',
'uses' => 'DashboardController#index'
]
)->where('name', 'home|dashboard|'); //add as many as possible separated by |
Because the second argument of where() expects regular expressions so we can assign it to match exactly any of those separated by | so my initial thought of proposing a whereIn() into Laravel route is resolved by this solution.
PS:This example is tested on Laravel 5.4.30
Hope someone finds it useful
If I understand your question right I'd say:
Use Route Prefixing: http://laravel.com/docs/routing#route-prefixing
Or (Optional) Route Parameters: http://laravel.com/docs/routing#route-parameters
So for example:
Route::group(array('prefix' => '/'), function() { Route::get('dashboard', 'DashboardController#index'); });
OR
Route::get('/{dashboard?}', array('as' => 'dashboard', 'uses' => 'DashboardController#index'));