multiple routes in single Route::get() call Laravel 4 - php

Question

When defining a route in Laravel 4 is it possible to define multiple URI paths within the same route?
presently i do the following:
Route::get('/', 'DashboardController#index');
Route::get('/dashboard', array('as' => 'dashboard', 'uses' => 'v1\DashboardController#index'));
but this defeats my purpose, i would like to do something like
Route::get('/, /dashboard', array('as' => 'dashboard', 'uses' => 'DashboardController#index'));

Answer 1

I believe you need to use an optional parameter with a regular expression:
Route::get('/{name}', array(
'as' => 'dashboard',
'uses' => 'DashboardController#index')
)->where('name', '(dashboard)?');
* Assuming you want to route to the same controller which is not entirely clear from the question.
* The current accepted answer matches everything not just / OR /dashboard.

Answer 2

I find it interesting for curiosity sake to attempt to solve this question posted by #Alex as a comment under #graemec's answer to post a solution that works:
Route::get('/{name}', [
'as' => 'dashboard',
'uses' => 'DashboardController#index'
]
)->where('name', 'home|dashboard|'); //add as many as possible separated by |
Because the second argument of where() expects regular expressions so we can assign it to match exactly any of those separated by | so my initial thought of proposing a whereIn() into Laravel route is resolved by this solution.
PS:This example is tested on Laravel 5.4.30
Hope someone finds it useful

Answer 3

If I understand your question right I'd say:
Use Route Prefixing: http://laravel.com/docs/routing#route-prefixing
Or (Optional) Route Parameters: http://laravel.com/docs/routing#route-parameters
So for example:
Route::group(array('prefix' => '/'), function() { Route::get('dashboard', 'DashboardController#index'); });
OR
Route::get('/{dashboard?}', array('as' => 'dashboard', 'uses' => 'DashboardController#index'));