This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 6 years ago.
I have two values:
$c_time = 2016-03-21 14:56:05
$e_time = 2016-03-24 14:56:05
Now I want to show remaining time and days like this:
3 days 0 hour 0 minute 0 second
How I can do this using PHP?
You can try this
$c_time = new DateTime('2016-03-21 14:56:05');
$e_time = new DateTime('2016-03-24 14:56:05');
$date_diff = $c_time->diff($e_time);
echo "{$date_diff->days} days {$date_diff->h} hour {$date_diff->i} minute {$date_diff->s} second";
- first way:
$datetime1 = strtotime('May 3, 2012 10:38:22 GMT');
$datetime2 = strtotime('06 Apr 2012 07:22:21 GMT');
$secs = $datetime2 - $datetime1;// == return sec in difference
$days = $secs / 86400;
- Another way:
$date1= new DateTime("May 3, 2012 10:38:22 GMT");
$date2= new DateTime("06 Apr 2012 07:22:21 GMT");
echo $date1->diff($date2)->("%d");
$c_time = new DateTime('2016-03-21 14:56:05');
$e_time = new DateTime('2016-03-24 14:56:05');
$interval = $c_time->diff($e_time);
print $interval->format('%a days %h hour %i minutes %s seconds');
print $interval->days; // to obtain the number of days
print $interval->h; // to obtain the number of hours
print $interval->i; // to obtain the number of minutes
print $interval->s; // to obtain the number of seconds
You can use date_diff():
$c_time = "2016-03-21 15:56:05";
$e_time = "2016-03-24 15:56:05";
$start = date_create($c_time);
$end = date_create($e_time);
$diff=date_diff($end,$start);
//print_r($diff);
echo $diff->d." days, ".$diff->h." hours, ".$diff->m." minutes, ".$diff->s." seconds";
Result:
3 days, 0 hours, 0 minutes, 0 seconds
Related
The expiry date is in unix timestamp approx 30th sept 2020 6AM
$expiry_date_time = 160142766; //30 sept 2020 6AM
$dt1 = new DateTime();
$dt1->setTimestamp($expiry_date_time);
$now = new DateTime();
$i = $now->diff($dt1);
$time_remaining = $i->format('%y years %m months %a days %h hours %i minutes');
echo $time_remaining;
Output today when i ran the code (11th OCT 2020)
0 years 0 months 11 days 7 hours 19 minutes
This code doesn't give incorrect result but it cannot differentiate between expired and not expired, like in the above case the subscription had expired it gives the output 11 days which is not entirely incorrect because it has been 11 days since its expired if you calculate but shouldn't it be Negative 11 days ?
If I make the expiry date to two days in the future it will correctly calculate and output 2 days, xx hours and xx minutes.
How to make it differentiate between expired and not expired ?
DateInterval has an invert flag for this very purpose:
invert
Is 1 if the interval represents a negative time period and 0 otherwise.
$expiry_date_time = 160142766; //30 sept 2020 6AM
$dt1 = new DateTime();
$dt1->setTimestamp($expiry_date_time);
$now = new DateTime();
// What you're doing right now
$i = $now->diff($dt1);
var_dump($i->invert); // int(1)
// If you're doing it the other way around
$i = $dt1->diff($now);
var_dump($i->invert); // int(0)
Demo
$expiry_date_time = 160142766; //30 sept 2020 6AM
$dt1 = new DateTime();
$dt1->setTimestamp($expiry_date_time);
$now = new DateTime();
$i = $now->diff($dt1);
$time_remaining = $i->format('%y years %m months %a days %h hours %i minutes');
if($expiry_date_time - $now()->getTimestamp() < 0) {
$time_remaining = "expired $time_remaining ago";
}
echo $time_remaining;
This will add some text to the text if it is in the past, to make sure you know if it is expired or not yet.
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Converting timestamp to time ago in PHP e.g 1 day ago, 2 days ago...
(32 answers)
Closed 4 years ago.
how can I get difference between 2 time in hours.
For ex:
$data1 = '2018-04-24 02:30:00';
$date2 = now();
how to get diff between $date1 and $date2.
EDIT: code posted by OP in comments
<?php //date_default_timezone_set('UTC+6');
$time1 = strtotime('2018-04-25 12:00:00');
$time2 = time();
echo $time2.'<br>';
echo date('Y-m-d h:i:s', $time2).'<br>';
echo ($time1-$time2)/3600; ?>
<?php
$datetime1 = new DateTime('2018-04-24 02:30:00');
$datetime2 = new DateTime(date('Y-m-d H:i:s'));
$interval = $datetime1->diff($datetime2);
echo $interval->format('%Y %m %d %H:%I:%S');
The result will be:
00 0 1 08:06:15
00 --> years
0 --> months
1 --> days
08 --> hours
06 --> minutes
15 --> seconds
You can modify it as you like but i suggest you keep at least days cause the hours may differ by a few hours but the days can differ by many days.
$data1 = '2018-04-24 02:30:00';
$data2 = date('y-m-d H:i:s');
$formated_in = date('Y-m-d H:i:s', strtotime($data1));
$formated_out = date('Y-m-d H:i:s', strtotime($data2));
$formated_new_in = strtotime($formated_in);
$formated_new_out = strtotime($formated_out);
$sub_total = $formated_new_out - $formated_new_in;
$sub_total = gmdate("H:i", $sub_total);
echo $sub_total;
I have this timestamp from the database 1496592689
the problem is I don't know how to get the remaining days, hours and minutes
but I have this code bellow
this is my variable from where the timestamp stored $db_user_timestamp
and now I have this current time now $timenow = time();
I tried to calculate it with
$remainingtime = $db_user_timestamp - $timenow;
But I don't know how to put it in the days, hours and minutes.
Thanks in advance for helping me :)
Always use DateTime
$create_time = "1496592689";
$current_time = time();
$dtCurrent = DateTime::createFromFormat('U', $current_time);
$dtCreate = DateTime::createFromFormat('U', $create_time);
$diff = $dtCurrent->diff($dtCreate);
$interval = $diff->format("%y years %m months %d days %h hours %i minutes %s seconds");
$interval = preg_replace('/(^0| 0) (years|months|days|hours|minutes|seconds)/', '', $interval);
echo $interval;
result
6 months 30 days 5 hours 52 minutes
If your PHP version is 5.3 or latest, you should check
http://php.net/manual/en/class.dateinterval.php
and
http://php.net/manual/en/datetime.diff.php
$datetime1 = new DateTime(date('Y-m-d H:i:s', $db_user_timestamp));
$datetime2 = new DateTime(date('Y-m-d H:i:s'));
$interval = $datetime1->diff($datetime2);
echo $interval->format('%y years %m months %d days %h hours %m minutes %s seconds');
<?php
$db_user_timestamp = 1496592689;
$difference = $db_user_timestamp - time();
echo "Day : ".$day = date('d',$difference);
echo "<br>Hour : ".$hour = date('H',$difference);
echo "<br>Minute : ".$minute = date('i',$difference);
?>
Using date('M/d/Y H:i:s', $theTimestamp); will give you date in day, month, year, hour, minute, seconds in the order you want (change 'M/d/Y H:i:s' to your string depending on http://php.net/manual/en/function.date.php)
This question already has answers here:
Converting timestamp to time ago in PHP e.g 1 day ago, 2 days ago...
(32 answers)
Closed 7 years ago.
I have two date times of the form
Start Date: 2015-11-15 11:40:44pm
End Date: 2015-11-22 10:50:88am
Now I need to find the difference between these two in the following form:
0 years, 0 months, 7 days, 22 hours, 44 mints, 35 sec
How can I do this in PHP?
I already try:
$strStart = date('Y-m-d h:i:s', time() - 3600);
$strEnd = '2015-11-22 02:45:25';
$dteStart = new DateTime($strStart);
$dteEnd = new DateTime($strEnd);
$dteDiff = $dteStart->diff($dteEnd);
echo $dteDiff->format("%H:%I:%S");
Output:22:53:58
Output not shown perfectly.
Now I need to find the difference between these two in the following form:
0 years, 0 months, 7 days, 22 hours, 44 mints, 35 sec
So that’s your main problem here, getting this exact output structure?
Well then you simply have to format the DateInterval differently:
echo $dteDiff->format("%y years, %m months, %d days, %h hours, %i mints, %s sec");
$startDate = "2015-11-15 11:40:44pm";
$endDate = "2015-11-22 10:50:48am"; // You had 50:88 here? That's not an existing time
$startEpoch = strtotime($startDate);
$endEpoch = strtotime($endDate);
$difference = $endEpoch - $startEpoch;
The script above converts the start and end date to epoch time (seconds since January 1 1970 00:00:00 GMT). Then it does the maths and gets the difference between them.
Since years and months aren't a static value, I haven't added them in the script below
$minute = 60; // A minute in seconds
$hour = $minute * 60; // An hour in seconds
$day = $hour * 24; // A day in seconds
$daycount = 0; // Counts the days
$hourcount = 0; // Counts the hours
$minutecount = 0; // Counts the minutes
while ($difference > $day) { // While the difference is still bigger than a day
$difference -= $day; // Takes 1 day from the difference
$daycount += 1; // Add 1 to days
}
// Now it continues with what's left
while ($difference > $hour) { // While the difference is still bigger than an hour
$difference -= $hour; // Takes 1 hour from the difference
$hourcount += 1; // Add 1 to hours
}
// Now it continues with what's left
while ($difference > $minute) { // While the difference is still bigger than a minute
$difference -= $minute; // Takes 1 minute from the difference
$minutecount += 1; // Add 1 to minutes
}
// What remains are the seconds
echo $daycount . " days ";
echo $hourcount . " hours ";
echo $minutecount . " minutes ";
echo $difference . " seconds ";
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 8 years ago.
I have two timestamps let us say
$end_date = 2014-09-09 15:03:10 and now date
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
I want to calculate number of days remaining .Suppose if that particular date crosses now date and it should display remaining days with -ve value.
I am using the following code
$remaining_days =strtotime($end_date) - strtotime($now) ;
$Result_days = floor($remaining_days /86400);
echo $remaining_days.' '.$Result_days.'<br/>'
Problem is that if the end date = today's date it is displaying -1 . I want to calculate based on time and display remaining days and hours.
Please help me to find out the solution.
Try this:
<?php
$end_date = "2014-10-09 15:03:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$diff = strtotime($now) - strtotime($end_date);
$fullDays = floor($diff/(60*60*24));
$fullHours = floor(($diff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Difference is $fullDays days, $fullHours hours and $fullMinutes minutes.";
Output:
Difference is -30 days, 0 hours and 39 minutes.
Demo:
http://3v4l.org/3auqe
Edit (using DATE OBJECT):
<?php
// Example 1
$end_date = "2014-09-11 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
+2 days, 3 hours, 0 minutes, 44 seconds
// Example 2
$end_date = "2014-09-08 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
-0 days, 20 hours, 0 minutes, 16 seconds
Demo:
http://3v4l.org/dPSgX#vhhvm-320
you can use date_diff php method .you can see example here http://php.net/manual/en/function.date-diff.php
You may try like this:
<?php
$dateDiff = $date1 - $date2;
$fullDays = floor($dateDiff/(60*60*24));
$fullHours = floor(($dateDiff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($dateDiff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Differernce is $fullDays days, $fullHours hours and $fullMinutes minutes.";
?>
See the Source for more options
$date1 = new DateTime("2014-09-09");
$date2 = new DateTime("2014-09-12");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";
The duplicate