I have this timestamp from the database 1496592689
the problem is I don't know how to get the remaining days, hours and minutes
but I have this code bellow
this is my variable from where the timestamp stored $db_user_timestamp
and now I have this current time now $timenow = time();
I tried to calculate it with
$remainingtime = $db_user_timestamp - $timenow;
But I don't know how to put it in the days, hours and minutes.
Thanks in advance for helping me :)
Always use DateTime
$create_time = "1496592689";
$current_time = time();
$dtCurrent = DateTime::createFromFormat('U', $current_time);
$dtCreate = DateTime::createFromFormat('U', $create_time);
$diff = $dtCurrent->diff($dtCreate);
$interval = $diff->format("%y years %m months %d days %h hours %i minutes %s seconds");
$interval = preg_replace('/(^0| 0) (years|months|days|hours|minutes|seconds)/', '', $interval);
echo $interval;
result
6 months 30 days 5 hours 52 minutes
If your PHP version is 5.3 or latest, you should check
http://php.net/manual/en/class.dateinterval.php
and
http://php.net/manual/en/datetime.diff.php
$datetime1 = new DateTime(date('Y-m-d H:i:s', $db_user_timestamp));
$datetime2 = new DateTime(date('Y-m-d H:i:s'));
$interval = $datetime1->diff($datetime2);
echo $interval->format('%y years %m months %d days %h hours %m minutes %s seconds');
<?php
$db_user_timestamp = 1496592689;
$difference = $db_user_timestamp - time();
echo "Day : ".$day = date('d',$difference);
echo "<br>Hour : ".$hour = date('H',$difference);
echo "<br>Minute : ".$minute = date('i',$difference);
?>
Using date('M/d/Y H:i:s', $theTimestamp); will give you date in day, month, year, hour, minute, seconds in the order you want (change 'M/d/Y H:i:s' to your string depending on http://php.net/manual/en/function.date.php)
Related
i am trying to display 'Days' and 'hours' code is working fine, but issue is i don't want to show 0 days. if day= 0 then show only hours.
<?php
$datetime1 = new DateTime();
$datetime2 = new DateTime($feed['dt_date_added']);
$interval = $datetime1->diff($datetime2);
$elapsed = $interval->format('%a days %h hours');
echo $elapsed;
?>
Output : - 0 Days 5 Hour
Expected Output: 5 Hour
You can just check whether the number of days is 0 or not, and adjust your output format accordingly. The DateInterval object provides the "d" property which lets you see the number of days (see documentation).
$datetime1 = new DateTime();
$datetime2 = new DateTime($feed['dt_date_added']);
$interval = $datetime1->diff($datetime2);
$format = "%h hours";
if($interval->d > 0) $format = "%a days ".$format; //adjust the format according to the number of days
$elapsed = $interval->format($format);
echo $elapsed;
Demo: http://sandbox.onlinephpfunctions.com/code/d01ae70566b1b4466664fcff8f7c70b261766c48
You just have to check if the days are 0:
$datetime1 = new DateTime();
$datetime2 = new DateTime($feed['dt_date_added']);
$interval = $datetime1->diff($datetime2);
$elapsed = $interval->format( $interval->format('%a') ? '%a days %h hours' : '%h hours' );
echo $elapsed;
i want to calculate different between two datetime in seconds and check if the result > 300sec
$d1 = new DateTime("2016-03-25 19:29:21");
$d2 = new DateTime(date('Y-m-d H:i:s'));
please check following code:
$datetime1 = new DateTime();
$datetime2 = new DateTime('2016-03-25 19:29:21');
$interval = $datetime1->diff($datetime2);
$elapsed = $interval->format('%y years %m months %a days %h hours %i minutes %S seconds');
echo $elapsed;
check this
if($d2->format('U')-$d1->format('U')>300){
// greater than 300
}else{
// less than 300
}
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 8 years ago.
I have two timestamps let us say
$end_date = 2014-09-09 15:03:10 and now date
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
I want to calculate number of days remaining .Suppose if that particular date crosses now date and it should display remaining days with -ve value.
I am using the following code
$remaining_days =strtotime($end_date) - strtotime($now) ;
$Result_days = floor($remaining_days /86400);
echo $remaining_days.' '.$Result_days.'<br/>'
Problem is that if the end date = today's date it is displaying -1 . I want to calculate based on time and display remaining days and hours.
Please help me to find out the solution.
Try this:
<?php
$end_date = "2014-10-09 15:03:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$diff = strtotime($now) - strtotime($end_date);
$fullDays = floor($diff/(60*60*24));
$fullHours = floor(($diff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Difference is $fullDays days, $fullHours hours and $fullMinutes minutes.";
Output:
Difference is -30 days, 0 hours and 39 minutes.
Demo:
http://3v4l.org/3auqe
Edit (using DATE OBJECT):
<?php
// Example 1
$end_date = "2014-09-11 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
+2 days, 3 hours, 0 minutes, 44 seconds
// Example 2
$end_date = "2014-09-08 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
-0 days, 20 hours, 0 minutes, 16 seconds
Demo:
http://3v4l.org/dPSgX#vhhvm-320
you can use date_diff php method .you can see example here http://php.net/manual/en/function.date-diff.php
You may try like this:
<?php
$dateDiff = $date1 - $date2;
$fullDays = floor($dateDiff/(60*60*24));
$fullHours = floor(($dateDiff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($dateDiff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Differernce is $fullDays days, $fullHours hours and $fullMinutes minutes.";
?>
See the Source for more options
$date1 = new DateTime("2014-09-09");
$date2 = new DateTime("2014-09-12");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";
The duplicate
I'm calculating a timedifference with this bit of php and formatting it in days, hours and minutes.
// Compares expires_at with the current time
$now = new DateTime();
$future_date = new DateTime($contest->expires_at);
$interval = $future_date->diff($now);
$enddate = $interval->format("%a days, %h hours, %i minutes");
// if current time is higher than expiration date set contest to finished.
if($now > $future_date) {
$enddate = 'Date ended';
}
Now I want to have the format to only display the total amount of days when it's over a day(24 hours) and start to format in hours and minutes when it's less than a day(24 hours). So it will format to hours and minutes starting from like 23 hours 59 minutes, you get the idea hopefully.
Can anyone tell me how does it done the easiest?
Do it like this:
// Compares expires_at with the current time
$now = new DateTime();
$future_date = new DateTime($contest->expires_at);
$interval = $future_date->diff($now);
if ($now > $future_date) {
// if current time is higher than expiration date set contest to finished.
$enddate = 'Date ended';
} else if ($interval >= new DateInterval("P1D")) {
$enddate = $interval->format("%a days, %h hours, %i minutes");
} else {
$enddate = $interval->format("%a days, %h hours, %i minutes");
}
I'm calculating the difference between 2 dates using DateTime() and it's working fine. The problem is that I want to have the days format be able to go above a full month so 30/31 or higher.
$now = new DateTime();
$future_date = new DateTime($contest->expires_at);
$interval = $future_date->diff($now);
$enddate = $interval->format("%m month, %d days, %h hours, %i minutes");
The current problem with this is that when I don't display the months, the days can only go up to 30/31 and anything over that will be carried over to make a new month resetting the days count with the leftover days.
I want to be able to display 42 days when the difference is 6 weeks with this kind of format:
$enddate = $interval->format("%d days, %h hours, %i minutes");
Is there a quick fix for this or do I need to manually convert the timestamp to seconds and use my own function with modulus operators for this?
You can try:
$enddate = $interval->format("%a days, %h hours, %i minutes");
See the DateInterval::format in the manual.
NOTE
Take care of the bug if you're working on windows.
This should solve your porblem:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the differnce
$interval = $future_date->diff($now);
echo($interval->days) . ' days';
For today: echo returns '61 days'
// EDIT
To avoid running into the dataInterval-Bug you can use:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the difference in second
$diffTimestamp = $future_date->getTimestamp() - $now->getTimestamp();
// convert to days
// 1 day = 86.400 seconds
$diffDays = $diffTimestamp/86400;
echo(floor($diffDays)) . ' days';
Update my php version since this is a bug in my old and it works perfectly now.
How to get aggregate days from PHP's DateTime::diff?