mysql query skips first row - php

Question

$sqlList ="select title from podcast order by date_pd desc limit 5";
$rslt2 = mysqli_query($conn, $sqlList) or die ("Fail".mysqli_error($conn));
$record2 = mysqli_fetch_array($rslt2);
$nRows = mysqli_num_rows($rslt2);
for ($i=0; $i<$nRows; $i++) {
$record2 = mysqli_fetch_array($rslt2);
echo $record2["title"];
}
the echo result is skipping the first row of the query, what am I doing wrong?

Answer 1

You are loosing the first row of your result set because you read the first row and throw it ways/ignore it
$sqlList ="select title from podcast order by date_pd desc limit 5";
$rslt2 = mysqli_query($conn, $sqlList) or die ("Fail".mysqli_error($conn));
// this line gets the first row of your result set
// and you just ignore it therefore throw it away
$record2 = mysqli_fetch_array($rslt2);
$nRows = mysqli_num_rows($rslt2);
for ($i=0; $i<$nRows; $i++) {
$record2 = mysqli_fetch_array($rslt2);
echo $record2["title"];
}
As #Anant says, you are better advised to use a while as if the result set is empty, it just does nothing. Admittedly not always an advantage.
$sqlList ="select title from podcast order by date_pd desc limit 5";
$rslt2 = mysqli_query($conn, $sqlList) or die ("Fail".mysqli_error($conn));
while ( $record2 = mysqli_fetch_array($rslt2) ) {
echo $record2["title"];
}

Answer 2

remove the line $record2 = mysqli_fetch_array($rslt2);, which is placed before the for loop.
new code would be:
$sqlList ="select title from podcast order by date_pd desc limit 5";
$rslt2 = mysqli_query($conn, $sqlList) or die("Fail".mysqli_error($conn));
$nRows = mysqli_num_rows($rslt2);
for ($i=0; $i<$nRows; $i++) {
$record2 = mysqli_fetch_array($rslt2);
echo $record2["title"];
}