How can I improve this PHP MySQL call? - php

I'm trying to update an older MySQL PHP method call but I end up calling the same SELECT call twice to achieve the same result. Is there a better way to do this?
Here is the original:
function updateProbabilities()
{
// first update the word count of each category
$rs = $this->con->select("SELECT category_id, SUM(count) AS total FROM nb_wordfreqs WHERE 1 GROUP BY category_id");
$total_words = 0;
while (!$rs->EOF()) {
$total_words += $rs->f('total');
$rs->moveNext();
}
$rs->moveStart();
if ($total_words == 0) {
$this->con->execute("UPDATE nb_categories SET word_count=0, probability=0 WHERE 1");
return true;
}
while (!$rs->EOF()) {
$proba = $rs->f('total')/$total_words;
$this->con->execute("UPDATE nb_categories SET word_count=".(int)$rs->f('total').",
probability=".$proba."
WHERE category_id = '".$rs->f('category_id')."'");
$rs->moveNext();
}
return true;
}
Here is my version:
function updateProbabilities() {
$sql = "SELECT category_id, SUM(count) AS total FROM nb_wordfreqs WHERE 1 GROUP BY category_id";
$res = mysql_query($sql) or die (mysql_error());
$total_words = 0;
while ($row = mysql_fetch_array($res, MYSQL_ASSOC)) {
$total_words += $row['total'];
}
if ($total_words >= 1) {
$sql = "SELECT category_id, SUM(count) AS total FROM nb_wordfreqs WHERE 1 GROUP BY category_id";
$res = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($res, MYSQL_ASSOC)) {
$proba = $row['total']/$total_words;
$count = (int)$row['total'];
$sql = "UPDATE nb_categories SET word_count=".$count.",
probability=".$proba."
WHERE category_id = '".$row['category_id']."'";
mysql_query($sql) or die (mysql_error());
}
}
else {
$sql = "UPDATE nb_categories SET word_count=0, probability=0 WHERE 1";
mysql_query($sql) or die (mysql_error());
}
return true;
}
Do you see any way I can avoid this second duplicate SELECT call?

The first time you run the query, add this to the while loop to store the results:
$rowarray[] = $row; // added to prevent running it twice
Then the second time it comes up, replace this:
$sql = "SELECT category_id, SUM(count) AS total FROM nb_wordfreqs WHERE 1 GROUP BY category_id";
$res = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($res, MYSQL_ASSOC)) {
with this:
foreach ($rowarray as $row) {
ALSO: move away from mysql_ functions, as they are deprecated and will soon be removed from PHP. Change to a PDO or MySQLi. You're already upating the code, may as well make that change too.

The mysql equivalent of $rs->moveStart() is:
mysql_data_seek($res, 0);
P.S. If you're rewriting into a new API, why are you using the deprecated mysql extension? You should use mysqli or PDO? They have similar methods for rewinding the cursor.

You can set the first query to a unique variable, and re-use the results of that query.
function updateProbabilities() {
$sql = "SELECT category_id, SUM(count) AS total FROM nb_wordfreqs WHERE 1 GROUP BY category_id";
$res = mysql_query($sql) or die (mysql_error());
$total_words = 0;
$results = array();
while ($row1 = mysql_fetch_array($res, MYSQL_ASSOC)) {
$total_words += $row1['total'];
$results[] = $row1;
}
if ($total_words >= 1) {
foreach ($results as $row2) {
$proba = $row2['total']/$total_words;
$count = (int)$row2['total'];
$sql = "UPDATE nb_categories SET word_count=".$count.",
probability=".$proba."
WHERE category_id = '".$row2['category_id']."'";
mysql_query($sql) or die (mysql_error());
}
}
else {
$sql = "UPDATE nb_categories SET word_count=0, probability=0 WHERE 1";
mysql_query($sql) or die (mysql_error());
}
return true;
}

Related

Using a good SQL query instead of PHP code

I have a page that is taking a kind of long time to load, and I'm almost sure that this is caused by too many sql requests (AKA caused by my bad SQL skills). Is there anyway to join these 3 queries into one?
What I want to do with this query is to try to select a specific id from cardapios and, if there is anything there (if $num_rows > 0) the only thing I want to do is select that id. If there is nothing there, then I want to insert something and then select the id of that.
$query = "SELECT id FROM cardapios WHERE nome='$nome'";
$sql = mysqli_query($con,$query);
$num_rows = mysqli_num_rows($sql);
if ($num_rows > 0){
while ($row = mysqli_fetch_array($sql)){
$_SESSION['id_cardapio'] = $row['id'];
$num_rows = 0;
}}else{
$query = "INSERT INTO cardapios (nome, kcal, semana)
VALUES('$nome', '$kcal', '$semana')" or die(mysqli_error($con));
$sql = mysqli_query($con,$query);
$query = "SELECT id FROM cardapios WHERE nome='$nome' ";
$sql = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($sql)){
$_SESSION['id_cardapio'] = $row['id'];
}
}
I am trying to put all of this into one query but getting nowhere. Is there anyway to use just one query for doing all of this?
Thanks in advance!
You can replace the last query by getting the mysqli_insert_id($con); as you already have the insert id available after the insert
$query = "SELECT id FROM cardapios WHERE nome='$nome'";
$sql = mysqli_query($con,$query);
$num_rows = mysqli_num_rows($sql);
if ($num_rows > 0){
while ($row = mysqli_fetch_array($sql)){
$_SESSION['id_cardapio'] = $row['id'];
$num_rows = 0;
}
}else{
$query = "INSERT INTO cardapios (nome, kcal, semana)
VALUES('$nome', '$kcal', '$semana')" or die(mysqli_error($con));
$sql = mysqli_query($con,$query);
if ( $sql !== false) { // did insert work
$_SESSION['id_cardapio'] = mysqli_insert_id($con);
} else {
// insert did nto work??
}
}

PHP - Loop inside loop second loop runs only once

I'm running one while inside another while but the second one is running only one time why and how can I fix it. I have also try with for but running again only once.
$sql = "SELECT DISTINCT season FROM search WHERE link = '$getid' Order by id asc";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($list = mysql_fetch_assoc($result))
{
$season = $list['season'];
$sql = mysql_query("SELECT * FROM search WHERE link = '$getid' and season = '$season'");
$episodes = mysql_num_rows($sql);
echo '1st';
$sqls = "SELECT * FROM search WHERE link = '$getid' and season = '$season' Order by id asc";
$results = mysql_query($sqls, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($lists = mysql_fetch_assoc($results))
{
$episode = $lists['episode'];
echo'2nd';
}
}
You are overriding the variables, use different ones:
$sql = "SELECT DISTINCT season FROM search WHERE link = '$getid' Order by id asc";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($list = mysql_fetch_assoc($result))
{
$season = $list['season'];
$sql2 = mysql_query("SELECT * FROM search WHERE link = '$getid' and season = '$season'");
$episodes = mysql_num_rows($sql2);
echo '1st';
$sqls = "SELECT * FROM search WHERE link = '$getid' and season = '$season' Order by id asc";
$results2 = mysql_query($sqls, $conn) or trigger_error("SQL", E_USER_ERROR);
while ($lists2 = mysql_fetch_assoc($results2))
{
$episode = $list2['episode'];
echo'2nd';
}
}

MySQL run query inside a query

I have a query that gets 5 lines of data like this example below
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
}
I want to run a query inside each results like this below
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}
but for some reason it's only display the first line when I add the query inside it. I can seem to make it run all 5 queries.
SELECT
t1.ref,
t1.user,
t1.id,
t2.domain,
t2.title
FROM
table AS t1
LEFT JOIN anothertable AS t2 ON
t2.domain = t1.ref
LIMIT
0, 5
The problem is that inside the while-cycle you use the same variable $result, which then gets overridden. Use another variable name for the $result in the while cycle.
You change the value of your $query in your while loop.
Change the variable name to something different.
Ex:
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$qry = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$rslt = mysql_query($qry) or die(mysql_error());
if (mysql_num_rows($rslt) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}
Use the following :
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query_domain = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result_domain = mysql_query($query_domain) or die(mysql_error());
if (mysql_num_rows($result_domain) )
{
$row_domain = mysql_fetch_row($result_domain);
$title = $row_domain['title'];
} else {
$title = "No Title";
}
echo "$ref - $title";
}
This is a logical problem. It happens that way, because you are same variable names outside and inside the loop.
Explanation:
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
// Now $results hold the result of the first query
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
//Using same $query does not affect that much
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
//But here you are overriding the previous result set of first query with a new result set
$result = mysql_query($query) or die(mysql_error());
//^ Due to this, next time the loop continues, the $result on whose basis it would loop will already be modified
//..............
Solution 1:
Avoid using same variable names for inner result set
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$sub_result = mysql_query($query) or die(mysql_error());
// ^ Change this variable so that it does not overrides previous result set
Solution 2:
Avoid the double query situation. Use joins to get the data in one query call. (Note: You should always try to optimize your query so that you will minimize the number of your queries on the server.)
SELECT
ref,user,id
FROM
table t
INNER JOIN
anothertable t2 on t.ref t2.domain
LIMIT 0, 5
Learn about SQL joins:
SELECT table.ref, table.user, table.id, anothertable.title
FROM table LEFT JOIN anothertable ON anothertable.domain = table.ref
LIMIT 5
You're changing the value of $result in your loop. Change your second query to use a different variable.
it is not give proper result because you have used same name twice, use different name like this edit.
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query1 = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result1 = mysql_query($query1) or die(mysql_error());
if (mysql_num_rows($result1) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}

trying to show a total from mysql in php

I am trying to get the qunt with are int and add them all up and show a total
$qunt = 0;
$result = mysql_query("SELECT *
FROM properties_items
WHERE user_propid='$view'
ORDER BY id DESC") or die (mysql_error());
while ($row = mysql_fetch_array($result)) {
$itemid = $row['itemid'];
$qunt = $row['qunt'];
$qunt++;
}
echo $qunt;
$qunt = 0;
$result = mysql_query("SELECT *
FROM properties_items
WHERE user_propid='$view'
ORDER BY id DESC") or die (mysql_error());
while ($row = mysql_fetch_array($result)) {
$itemid = $row['itemid'];
$qunt += $row['qunt'];
}
echo $qunt;
Dare I say that you probably aren't using the itemid, in which case there's no point in looping through a result set in code. Instead, try something like this:
$qunt = mysql_query "SELECT SUM(qunt) FROM properties_items WHERE user_propid='$view'";
$qunt += $row['qunt'];
And get rid of the ++ line.

Checking if mysql_query returned anything or not

$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
If 'table' has no rows. whats the easiest way to check for this.?
Jeremy Ruten's answer above is good and executes quickly; on the other hand, it only gives you the number of rows and nothing else (if you want the result data, you have to query the database again). What I use:
// only ask for the columns that interest you (SELECT * can slow down the query)
$query = "SELECT some_column, some_other_column, yet_another_column FROM `table`";
$results = mysql_query($query, $connection);
$numResults = mysql_num_rows($results);
if ($numResults > 0) {
// there are some results, retrieve them normally (e.g. with mysql_fetch_assoc())
} else {
// no data from query, react accordingly
}
You could use mysql_num_rows($results) to check if 0 rows were returned, or use this faster alternative:
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
Alternatively you can simply check if the result of mysql_fetch_assoc is false.
$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
$Row = mysql_fetch_assoc($results);
if ($Row == false)
{
$Msg = 'Table is empty';
}
One thing i noticed that was missed was the fact that the query might not succeed, so you do need to check if the $results variable is set. I'll use the answer given by yjerem as an example.
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
if ($results) { // or use isset($results)
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
}
If you loop through the results, you can have a counter and check that.
$x = 1;
$query = mysql_query("SELECT * FROM table");
while($row = mysql_fetch_assoc($query))
{
$x++;
}
if($x == 1)
{
//No rows
}

Categories