About sql and str_replace function - php

First of all, thanks to everyone for helping me, and please apologize my English, I'm trying to do the best :)
This is what I wanna do:
I have a table in MySQL database, named acciones, I want to every "action" registered in that table make a replace in the text printed on screen:
<?php
include('../procesos/abre_conexion.php');
$query99 = "SELECT * from acciones";
// This line make the query
$result99 = mysql_query($query99);
$registro99 = mysql_fetch_array($result99)
?>
<?php
// create the function
function howls($valor) {
// set the variable // saving as array // possible texts
$variables = array('$registro99[original]',);
// $imagenes, tambien contendra un array
// with the replace text
$sus = array('$registro99[reemplazo]',);
// making the replace
return (str_replace($variables, $sus, $valor));
}
// starting function
ob_start("howls");
?>
#SalirA beber Cerveza Montoro en barrio santo con Andreita.
<?php
// ending function
ob_end_flush();
?>
<? include('../procesos/cierra_conexion.php'); ?>
But it don't works, any suggestion?

Firstly, you should NOT be using the mysql_* functions. They are deprecated and completely removed from PHP7.
As to what is happening with your code. You shouldn't single quote the $registro variables. If you do need them quoted for some reason, you need to double-quote them.
function howls($valor) {
// set the variable // saving as array // possible texts
$variables = array("{$registro99[original]}",);
// $imagenes, tambien contendra un array
// with the replace text
$sus = array("{$registro99[reemplazo]}",);
// making the replace
return (str_replace($variables, $sus, $valor));
}

Related

PHP replace {replace_me} with <?php include ?> in output buffer

I have a file like this
**buffer.php**
ob_start();
<h1>Welcome</h1>
{replace_me_with_working_php_include}
<h2>I got a problem..</h2>
ob_end_flush();
Everything inside the buffer is dynamically made with data from the database.
And inserting php into the database is not an option.
The issue is, I got my output buffer and i want to replace '{replace}' with a working php include, which includes a file that also has some html/php.
So my actual question is: How do i replace a string with working php-code in a output-buffer?
I hope you can help, have used way to much time on this.
Best regards - user2453885
EDIT - 25/11/14
I know wordpress or joomla is using some similar functions, you can write {rate} in your post, and it replaces it with a rating system(some rate-plugin). This is the secret knowledge I desire.
You can use preg_replace_callback and let the callback include the file you want to include and return the output. Or you could replace the placeholders with textual includes, save that as a file and include that file (sort of compile the thing)
For simple text you could do explode (though it's probably not the most efficient for large blocks of text):
function StringSwap($text ="", $rootdir ="", $begin = "{", $end = "}") {
// Explode beginning
$go = explode($begin,$text);
// Loop through the array
if(is_array($go)) {
foreach($go as $value) {
// Split ends if available
$value = explode($end,$value);
// If there is an end, key 0 should be the replacement
if(count($value) > 1) {
// Check if the file exists based on your root
if(is_file($rootdir . $value[0])) {
// If it is a real file, mark it and remove it
$new[]['file'] = $rootdir . $value[0];
unset($value[0]);
}
// All others set as text
$new[]['txt'] = implode($value);
}
else
// If not an array, not a file, just assign as text
$new[]['txt'] = $value;
}
}
// Loop through new array and handle each block as text or include
foreach($new as $block) {
if(isset($block['txt'])) {
echo (is_array($block['txt']))? implode(" ",$block['txt']): $block['txt']." ";
}
elseif(isset($block['file'])) {
include_once($block['file']);
}
}
}
// To use, drop your text in here as a string
// You need to set a root directory so it can map properly
StringSwap($text);
I might be misunderstanding something here, but something simple like this might work?
<?php
# Main page (retrieved from the database or wherever into a variable - output buffer example shown)
ob_start();
<h1>Welcome</h1>
{replace_me_with_working_php_include}
<h2>I got a problem..</h2>
$main = ob_get_clean();
# Replacement
ob_start();
include 'whatever.php';
$replacement = ob_get_clean();
echo str_replace('{replace_me_with_working_php_include}', $replacement, $main);
You can also use a return statement from within an include file if you wish to remove the output buffer from that task too.
Good luck!
Ty all for some lovely input.
I will try and anwser my own question as clear as I can.
problem: I first thought that I wanted to implement a php-function or include inside a buffer. This however is not what I wanted, and is not intended.
Solution: Callback function with my desired content. By using the function preg_replace_callback(), I could find the text I wanted to replace in my buffer and then replace it with whatever the callback(function) would return.
The callback then included the necessary files/.classes and used the functions with written content in it.
Tell me if you did not understand, or want to elaborate/tell more about my solution.

json encode using php not able to get [] brackets

here is my code
<?
include '../dbConnect.php';
$amp=trim($_POST['amp']);
//$amp='AMP8';
//$sql=mysql_query("select tblRepairQueue.ackNo,tblRepairQueue.repairStatus,tblRepairQueue.savedAt from tblRepairQueue,AMPcustomers where AMPcustomers.phone1=tblRepairQueue.phoneNo and AMPcustomers.id='".$amp."'");
$sql=mysql_query("select phone1 from AMPcustomers where id='".$amp."'");
$response = array();
while($row=mysql_fetch_array($sql))
{
$sql_query=mysql_query("select ackNo,repairStatus,savedAt from tblRepairQueue where phoneNo='".$row['phone1']."'");
while($row1=mysql_fetch_array($sql_query)){
$ackNo=$row1['ackNo'];
$repairStatus=$row1['repairStatus'];
$savedAt=$row1['savedAt'];
$response[]=array('ackNo'=>$ackNo,'repairStatus'=>$repairStatus,'savedAt'=>$savedAt);
}}
print json_encode($response);
?>
output m getting as
{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
but i want the output to look like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]
Can anyone plz help in finding the mistake or what has to be done to get square brackets at the end
This is a bit strange because I have this code:
<?php
$array = array();
$array[] = array("ackNo"=>"26101211236759","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 00:55:25");
$array[] = array("ackNo"=>"26101211236780","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 10:55:25");
echo json_encode($array);
?>
And I get this correct form:
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"26101211236780","repairStatus":"Closed and Complete","savedAt":"2012-10-26 10:55:25"}]
This code should indeed output [{...},...]. So we can't really tell you what went wrong on your side. check the structure of the $response variable before the conversion to Json to see what went wrong.
Note that the code allows SQL injection. You must change it so that the parameters $amp and $row['phone1'] are escaped in the SQL queries. Even if you're relying on magic qoutes now, this solution is not future-proof (now-proof really) as support for this is was removed in PHP 5.4.
What you have written should work:
http://ideone.com/ErV9fr
// How many to add
$response_count=3;
// Your response, just templated
$response_template=array(
'response_number'=>0,
'ackNo'=>'dffdgd',
'repairStatus'=>'$repairStatus',
'savedAt'=>'$savedAt'
);
// Your empty response array
$response = array();
for($i=0;$i<$response_count;$i++) {
$response_template['response_number'] = $i; // Set the 'response number' to the itteration.
$response[]= $response_template; // Add the template to the collection
}
print json_encode($response);
Result:
[{"response_number":0,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":1,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":2,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"}]
In addition to this, you should sanitize your $amp variable. In it's current form it would be trivial for a user to escape your query and execute an arbitrary query against your DB.
http://www.php.net/manual/en/mysqli.real-escape-string.php
Please recheck it can not give you the output like that {"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
as it is creating an array of array so it can not print like that.
It will always print like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]

Using Simple HTML DOM to extract an 'a' URL

I have this code for scraping team names from a table
$url = 'http://fantasy.premierleague.com/my-leagues/303/standings/';
$html = #file_get_html($url);
//Cut out the table
$FullTable = $html->find('table[class=ismStandingsTable]',0);
//get the text from the 3rd cell in the row
$teamname = $FullTable->find('td',2)->innertext;
echo $teamname;
This much works.. and gives this output....
Why Always Me?
But when I add these lines..
$teamdetails = $teamname->find('a')->href;
echo $teamdetails;
I get completely blank output.
Any idea why? I am trying to get the /entry/110291/event-history/33/ as one variable, and the Why Always Me? as another.
Instead do this:
$tdhtml = DOMDocument::loadHTML($teamdetails);
$link = $tdhtml->getElementsByTagName('a');
$url = $link->item(0)->attributes->getNamedItem('href')->nodeValue;
$teamdetails = $teamname->find('a')->href;
^^^^^^^^^---- never defined in your code
I also fail to see how your "works" code could possibly work. You don't define $teamname in there either, so all you'd never get is the output of a null/undefined variable, which is...no output all.
Marc B is right, I get that you don't have to initialize a variable, but he is saying you are trying to access a property of said variable:
$teamdetails = $teamname->find('a')->href;
^^^^^^^^^---- never defined in your code
This is essentially:
$teamname = null;
$teamname->find('a')->href;
The problem in your example is that $teamname is a string and you're treating it like a simple_html_dom_node

Drupal render() - make printed content ucfirst

I have a drupal template that renders some content like this:
<?php $field_collection_state_info = reset($content['field_state_information']['0']['entity']['field_collection_item']); ?>
<?php print render($field_collection_state_info['field_state_name']); ?>
but I would like to run the php ucfirst() so all rendered content is capitalized on the first letter.
I tried this:
<?php print ucfirst(render($field_collection_state_info['field_state_name'])); ?>
But that didn't work.
How should I achieve this?
Any advise is very much appreciated.
C
I think you will have to change the content of your render array before calling render():
// the 'und' part is depending on the translation of the node
$field_collection_state_info['field_state_name']['und'][0]['value'] =
ucfirst($field_collection_state_info['field_state_name']['und'][0]['value']);
// render
print render($field_collection_state_info['field_state_name']);
// or you could try to modify the safe_value part of the array depending on your
// filter settings for the field
$field_collection_state_info['field_state_name']['und'][0]['safe_value'] =
ucfirst($field_collection_state_info['field_state_name']['und'][0]['safe_value']);
// render
print render($field_collection_state_info['field_state_name']);
EDIT Try adding this into your template.php, it changes the value for a collection_field using hook_preprocess_node():
function YOURTHEME_preprocess_node(&$vars) {
if($vars['type'] == 'YOUR-CONTENT-TYPE') {
// you might need to replace the field_content_block with the name of your field <field_state_information>
$data = reset($vars['content']['field_content_block'][0]['entity']['field_collection_item']);
// turn the first character to uppercase
$data['field_text']['#object']->field_text['und'][0]['value'] = ucwords($data['field_text']['#object']->field_text['und'][0]['value']);
// set the data in the array, like I said above your might need to change the `field_collection_block` to `field_state_information`
$vars['content']['field_content_block'][0]['entity']['field_collection_item'] = $data;
}
}

Stripping text from url

Im trying to strip find_loc= and &cflt=pizza I got the majority stripped its just these last 2 things and whenever I try to use trim it doesn't delete it out it keeps saying array even when i try to print it, it says array.
<?php
$foo = 'http://www.yelp.com/search?find_loc=2190+W+Washington+Blvd%2C+Los+Angeles+90018&cflt=pizza ';
$blah = parse_url($foo);
$blah[query];
//the code above echos out find_loc=2190+W+Washington+Blvd%2C+Los+Angeles+90018&cflt=pizza
$thids = trim(''.$blah.'','find_loc=');
echo $thids;
?>
$thids = str_replace(array('&cflt=pizza','find_loc='), '', $blah);
parse_str($blah['query'], $query_vars); // decompose query string into components
unset($query_vars['find_loc']); // delete this particular query variable/value
unset($query_vars['cflt']);
$blah['query'] = http_build_query($query_vars); // rebuild the query string
$foo = http_build_url($blah); // rebuild the url

Categories