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i need to compare the value of an array and based on that i need to check another array which is multidimensional , if the value is present in another array , then i need to delete the entire row from it . how to achieve this ?
<?php
$a1=array(
array("key1"=>"123","phone"=>"2234567890","val"=>"test1","color"=>"red"),
array("key1"=>"234","phone"=>"2234567890","val"=>"test2","color"=>"green"),
array("key1"=>"312","phone"=>"2234567890","val"=>"test3","color"=>"yellow"),
array("key1"=>"425","phone"=>"2234567890","val"=>"test4","color" => "orange"));
$a2=array("green");
foreach($a1 as $k => $value){
$result = array_diff($value, $a2);
print_r($result);
}
?>
I have tried with array_diff , but only that key,val pair is removing .. i need to remove entire row.
$a2 array has value "green" .. based on this array $a1 should have only 3 array as output by removing 2nd array of $a2.
Assuming you compare values of color key:
$a1 = array(
array("key1"=>"123","phone"=>"2234567890","val"=>"test1","color"=>"red"),
array("key1"=>"234","phone"=>"2234567890","val"=>"test2","color"=>"green"),
array("key1"=>"312","phone"=>"2234567890","val"=>"test3","color"=>"yellow"),
array("key1"=>"425","phone"=>"2234567890","val"=>"test4","color" => "orange")
);
$a2 = array("green");
$newArray = array_filter(
$a1,
function($v) use ($a2) { return !in_array($v['color'], $a2); }
);
Fiddle here.
If you don't want to compare a specific key, then just check if it is in the array and unset it:
foreach($a1 as $k => $value){
if(array_intersect($value, $a2)) {
unset($a1[$k]);
}
}
This would also work for checking an array with multiple values like:
$a2 = array("green", "test4");
//or
$a2 = array("green", "red");
I am reading value from CMD which is running a python program and my output as follows:
Let as assume those values as $A:
$A = [[1][2][3][4]....]
I want to make an array from that as:
$A = [1,2,3,4....]
I had tried as follows:
$val = str_replace("[","",$A);
$val = str_replace("]","",$val);
print_r($val);
I am getting output as:
Array ( [0] => 1 2 3 4 ... )
Please guide me
try this
// your code goes here
$array = array(
array("1"),
array("2"),
array("3"),
array("4")
);
$outputArray = array();
foreach($array as $key => $value)
{
$outputArray[] = $value[0];
}
print_r($outputArray);
Also check the example here https://ideone.com/qaxhGZ
This will work
array_reduce($a, 'array_merge', array());
Multidimensional array to single dimensional array,
$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($A));
$A = iterator_to_array($it, false);
But, if $A is string
$A = '[[1][2][3][4]]';
$A = explode('][', $A);
$A = array_map(function($val){
return trim($val,'[]');
}, $A);
Both codes will get,
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
)
This function will work when you do indeed have a multidimensional array, which you stated you have, in stead of the String representation of a multidimensional array, which you seem to have.
function TwoDToOneDArray($TwoDArray) {
$result = array();
foreach ($TwoDArray as $value) {
array_push($result, $value[0]);
}
return $result;
}
var_dump(TwoDToOneDArray([[0],[1]]));
You can transform $A = [[1],[2],[3],[4]] into $B = [1,2,3,4....] using this following one line solution:
$B = array_map('array_shift', $A);
PD: You could not handle an array of arrays ( a matrix ) the way you did. That way is only for managing strings. And your notation was wrong. An array of arrays (a matrix) is declared with commas.
If you have a string like you wrote in the first place you can try with regex:
$a = '[[1][2][3][4]]';
preg_match_all('/\[([0-9\.]*)\]/', $a, $matches);
$a = $matches[1];
var_dump($a);
If $A is a string that looks like an array, here's one way to get it:
$A = '[[1][2][3][4]]';
print "[".str_replace(array("[","]"),array("",","),substr($A,2,strlen($A)-4))."]";
It removes [ and replaces ] with ,. I just removed the end and start brackets before the replacement and added both of them after it finishes. This outputs: [1,2,3,4] as you can see in this link.
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
I need function that would return array('tomato','banana'), consider that it omits keys that don't exist in one or the other array. Apple has the same value in both arrays, so it should be omitted - returned should be only keys whose values differ and are set
This should work (demo):
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
$result = array_keys(array_diff(array_intersect_key($arr1, $arr2), $arr2));
print_r($result);
Output:
Array
(
[0] => tomato
[1] => banana
)
Reference:
array_intersect_key — Computes the intersection of arrays using keys for comparison
array_diff — Computes the difference of arrays
array_keys — Return all the keys or a subset of the keys of an array
$array3 = array();
foreach(array_intersect_key($array1, $array2) as $key => $v){
if($array1[$key] != $array2[$key]) $array3[] = $key;
}
<?php
/**
* Returns an array which contains keys which are in both $array1
* and $array2, and which have different values.
*/
function getKeysWhichMatchAndHaveDifferentValues($array1, $array2)
{
$arrIntersected = array_intersect_key($array1, $array2);
foreach($arrIntersected as $key => $value)
{
if($array2[$key] == $value) {
unset($arrIntersected[$key]);
}
}
return array_keys($arrIntersected);
}
$arr1 = array('potato'=>1,'tomato'=>2,'apple'=>5,'banana'=>10);
$arr2 = array('orange'=>20,'tomato'=>3,'apple'=>5,'banana'=>20);
$final = getKeysWhichMatchAndHaveDifferentValues($arr1, $arr2);
echo '<pre>' . print_r($final) . '</pre>';
?>
I would do simple loop.
Of course if you will need to compare large arrays, the native PHP functions could help a lot. Still can't answer right now what would be the most optimal way to do this.
You could do this using array_intersect and array_keys.
$arr3 = array_intersect(array_keys($arr1), array_keys($arr2));
I know there is array_unique function, but I want to remove duplicates. Is there a built-in function or do I have to roll my own.
Example input:
banna, banna, mango, mango, apple
Expected output:
apple
You can use a combination of array_unique, array_diff_assoc and array_diff:
array_diff($arr, array_diff_assoc($arr, array_unique($arr)))
You can use
$singleOccurences = array_keys(
array_filter(
array_count_values(
array('banana', 'mango', 'banana', 'mango', 'apple' )
),
function($val) {
return $val === 1;
}
)
)
See
array_count_values — Counts all the values of an array
array_filter — Filters elements of an array using a callback function
array_keys — Return all the keys or a subset of the keys of an array
callbacks
Just write your own simple foreach loop:
$used = array();
$array = array("banna","banna","mango","mango","apple");
foreach($array as $arrayKey => $arrayValue){
if(isset($used[$arrayValue])){
unset($array[$used[$arrayValue]]);
unset($array[$arrayKey]);
}
$used[$arrayValue] = $arrayKey;
}
var_dump($array); // array(1) { [4]=> string(5) "apple" }
have fun :)
If you want to only leave values in the array that are already unique, rather than select one unique instance of each value, you will indeed have to roll your own. Built in functionality is just there to sanitise value sets, rather than filter.
You want to remove any entries that have duplicates, so that you're left with only the entries that were unique in the list?
Hmm it does sound like something you'll need to roll your own.
There is no existing function; You'll have to do this in two passes, one to count the unique values and one to extract the unique values:
$count = array();
foreach ($values as $value) {
if (array_key_exists($value, $count))
++$count[$value];
else
$count[$value] = 1;
}
$unique = array();
foreach ($count as $value => $count) {
if ($count == 1)
$unique[] = $value;
}
The answer on top looks great, but on a side note: if you ever want to eliminate duplicates but leave the first one, using array_flip twice would be a pretty simple way to do so. array_flip(array_flip(x))
Only partially relevant to this specific question - but I created this function from Gumbo's answer for multi dimensional arrays:
function get_default($array)
{
$default = array_column($array, 'default', 'id');
$array = array_diff($default, array_diff_assoc($default, array_unique($default)));
return key($array);
}
In this example, I had cached statuses and each one other than the default was 0 (the default was 1). I index the default array from the IDs, and then turn it into a string. So to be clear - the returned result of this is the ID of the default status providing it's in the same part of the multi dimensional array and not the key of it
PHP.net http://php.net/manual/en/function.array-unique.php
array array_unique ( array $array [, int $sort_flags = SORT_STRING ] )
Takes an input array and returns a new array without duplicate values.
New solution:
function remove_dupes(array $array){
$ret_array = array();
foreach($array as $key => $val){
if(count(array_keys($val) > 1){
continue;
} else {
$ret_array[$key] = $val;
}
}
I need to get the keys from values that are duplicates. I tried to use array_search and that worked fine, BUT I only got the first value as a hit.
I need to get both keys from the duplicate values, in this case 0 and 2. The search result output as an array would be good.
Is there a PHP function to do this or do I need to write some multiple loops to do it?
$list[0][0] = "2009-09-09";
$list[0][1] = "2009-05-05";
$list[0][2] = "2009-09-09";
$list[1][0] = "first-paid";
$list[1][1] = "1";
$list[1][2] = "last-unpaid";
echo array_search("2009-09-09",$list[0]);
You want array_keys with the search value
array_keys($list[0], "2009-09-09");
which will return an array of the keys with the specified value, in your case [0, 2]. If you want to find the duplicates as well, you can first make a pass with array_unique, then iterate over that array using array_keys on the original; anything which returns an array of length > 1 is a duplicate, and the result is the keys in which the duplicates are stored. Something like...
$uniqueKeys = array_unique($list[0])
foreach ($uniqueKeys as $uniqueKey)
{
$v = array_keys($list[0], $uniqueKey);
if (count($v) > 1)
{
foreach ($v as $key)
{
// Work with $list[0][$key]
}
}
}
In array_search() we can read:
If needle is found in haystack more
than once, the first matching key is
returned. To return the keys for all
matching values, use array_keys() with
the optional search_value parameter
instead.
The following combination of function calls will give you all duplicate values:
$a = array(1, 1, 2, 3, 4, 5, 99, 2, 5, 2);
$unique = array_unique($a); // preserves keys
$diffkeys = array_diff_key($a, $unique);
$duplicates = array_unique($diffkeys);
echo 'Duplicates: ' . join(' ', $duplicates) . "\n"; // 1 2 5
You can achieve that using array_search() by using while loop and the following workaround:
while (($key = array_search("2009-09-09", $list[0])) !== FALSE) {
print($key);
unset($list[0][$key]);
}
Source: cue at openxbox at php.net
For one-multidimensional array, you may use the following function to achieve that (as alternative to array_keys()):
function array_isearch($str, $array){
$found = array();
foreach ($array as $k => $v) {
if (strtolower($v) == strtolower($str)) {
$found[] = $k;
}
}
return $found;
}
Source: robertark, php.net
The PHP manual states in the Return Value section of the array_search() function documentation that you can use array_keys() to accomplish this. You just need to provide the second parameter:
$keys = array_keys($list[0], "2009-09-09");
$userdb=Array
(
(0) => Array
(
(uid) => '100',
(name) => 'Sandra Shush',
(url) => 'urlof100'
),
);
$key = array_search(100, array_column($userdb, 'uid'));