I need to get the keys from values that are duplicates. I tried to use array_search and that worked fine, BUT I only got the first value as a hit.
I need to get both keys from the duplicate values, in this case 0 and 2. The search result output as an array would be good.
Is there a PHP function to do this or do I need to write some multiple loops to do it?
$list[0][0] = "2009-09-09";
$list[0][1] = "2009-05-05";
$list[0][2] = "2009-09-09";
$list[1][0] = "first-paid";
$list[1][1] = "1";
$list[1][2] = "last-unpaid";
echo array_search("2009-09-09",$list[0]);
You want array_keys with the search value
array_keys($list[0], "2009-09-09");
which will return an array of the keys with the specified value, in your case [0, 2]. If you want to find the duplicates as well, you can first make a pass with array_unique, then iterate over that array using array_keys on the original; anything which returns an array of length > 1 is a duplicate, and the result is the keys in which the duplicates are stored. Something like...
$uniqueKeys = array_unique($list[0])
foreach ($uniqueKeys as $uniqueKey)
{
$v = array_keys($list[0], $uniqueKey);
if (count($v) > 1)
{
foreach ($v as $key)
{
// Work with $list[0][$key]
}
}
}
In array_search() we can read:
If needle is found in haystack more
than once, the first matching key is
returned. To return the keys for all
matching values, use array_keys() with
the optional search_value parameter
instead.
The following combination of function calls will give you all duplicate values:
$a = array(1, 1, 2, 3, 4, 5, 99, 2, 5, 2);
$unique = array_unique($a); // preserves keys
$diffkeys = array_diff_key($a, $unique);
$duplicates = array_unique($diffkeys);
echo 'Duplicates: ' . join(' ', $duplicates) . "\n"; // 1 2 5
You can achieve that using array_search() by using while loop and the following workaround:
while (($key = array_search("2009-09-09", $list[0])) !== FALSE) {
print($key);
unset($list[0][$key]);
}
Source: cue at openxbox at php.net
For one-multidimensional array, you may use the following function to achieve that (as alternative to array_keys()):
function array_isearch($str, $array){
$found = array();
foreach ($array as $k => $v) {
if (strtolower($v) == strtolower($str)) {
$found[] = $k;
}
}
return $found;
}
Source: robertark, php.net
The PHP manual states in the Return Value section of the array_search() function documentation that you can use array_keys() to accomplish this. You just need to provide the second parameter:
$keys = array_keys($list[0], "2009-09-09");
$userdb=Array
(
(0) => Array
(
(uid) => '100',
(name) => 'Sandra Shush',
(url) => 'urlof100'
),
);
$key = array_search(100, array_column($userdb, 'uid'));
Related
I need to remove values from an array that occur more than one time in the array.
For example:
$value = array(10,10,5,8);
I need this result:
$value = array(5,8);
Is there any in-built function in php?
I tried this, but this will not return my expected result:
$unique = array_unique($value);
$dupes = array_diff_key($value, $unique);
You can use array functions and ditch the foreach loops if you wish:
Here is a one-liner:
Code:
$value = [10, 10, 5, 8];
var_export(array_keys(array_intersect(array_count_values($value),[1])));
As multi-line:
var_export(
array_keys(
array_intersect(
array_count_values($value),
[1]
)
)
);
Output:
array (
0 => 5,
1 => 8,
)
This gets the value counts as an array, then uses array_intersect() to only retain values that occur once, then turns the keys into the values of a zero-index array.
The above snippet works identically to #modsfabio's and #axiac's answers. The ONLY advantage in my snippet is brevity. It is possible that their solutions may outperform mine, but judging speed on relatively small data sets may be a waste of dev time. For anyone processing relatively large data sets, do your own benchmarking to find the technique that works best.
For lowest computational/time complexity, use a single loop and as you iterate conditionally populate a lookup array and unset() as needed.
Code: (Demo) (Crosslink to my CodeReview answer)
$values = [10, 10, 5, 8];
$found = [];
foreach ($values as $index => $value) {
if (!isset($found[$value])) {
$found[$value] = $index;
} else {
unset($values[$index], $values[$found[$value]]);
}
}
var_export($values);
// [2 => 5, 3 => 8]
A couple of notes:
If processing float values, using a technique that stores the values as keys (as all of my snippets do), then the results may be incorrect because php will change floats to integers when used as keys.
PHP is consistently much faster at searching for keys than it is at searching for values.
You can do it like this using array_count_values() and a foreach loop:
<?php
$input = array(10,10,5,8);
$output = array();
foreach(array_count_values($input) as $value => $count)
{
if($count == 1)
{
$output[] = $value;
}
}
var_dump($output);
Output:
array(2) {
[0]=>
int(5)
[1]=>
int(8)
}
Example: https://eval.in/819461
A possible approach:
$value = array(10,10,5,8);
$output = array_keys(
array_filter(
array_count_values($value),
function ($count) {
return $count == 1;
}
)
)
array_count_values() produces an array that associates to each unique value from $value the number of times it appears in the array.
array_filter() keeps in this result only the entries (the keys) that appear only once in the original array.
array_keys() produces the desired result.
I would use array_count_values to get an array with how often every element occurs in the array. Then remove all the elements from the original array that occur more than once.
You need to use array_count_values(), array_search() and unset() functions.
<?php
$value = array(10,10,5,8);
echo '<pre>';print_r($value);echo '</pre>';
$cnt = array_count_values($value);
$dup = array();
foreach ($cnt as $k => $repeated) {
if ($repeated > 1) {
if(($key = array_search($k, $value)) !== false) {
unset($value[$key]);
}
}
}
echo '<pre>';print_r($cnt);echo '</pre>';
echo '<pre>';print_r($value);echo '</pre>';
?>
Demo
you can use
foreach loop
and
array_diff() function:
$value=array(10,10,5,8);
$duplicated=array();
foreach($value as $k=>$v)
{
if($kt=array_search($v,$value))!==false and
$k!=$kt)
{if (count(array_keys($array, $value)) > 1)
{
/* Execute code */
}
unset($value[$kt];$duplicated[]=$v;
}
}
$result=array_diff($values,$duplicated);
print_r($result);
output
Array([2]=>5[3]=>8)
If, for example, i have an array :
$random = array("Woodpecker","Pecking","Kayaking");
Using HTML Forms, how can I get all possible matches of an input string.
For example if the input is 'Peck', i should get the output as Woodpecker and Pecking. Case insensitive.
Use loop to achieve this
<?php
$random = array("Woodpecker","Pecking","Kayaking");
foreach($random as $r)
{
if(stripos($r,'peck') !== false)
echo $r;
}
?>
Iterate over the array in a loop and use a function for matching strings.
Iterate an array
Match string with regular expression
Your friend is array_search or array_keys()
$array = array(0 => 'blue', 1 => 'red', 2 => 'green', 3 => 'red');
$key = array_search('green', $array); // $key = 2;
$key = array_search('red', $array); // $key = 1;
Returns the key for needle if it is found in the array, FALSE
otherwise.
If needle is found in haystack more than once, the first matching key
is returned. To return the keys for all matching values, use
array_keys() with the optional search_value parameter instead.
I have an associative PHP array and I would like to generate a list of keys that pass a certain test. For example
$myArray = ('28'=>0.01,'51'=>-0.1,'48'=>0.4,'53'=>-0.3);
And I'd like to filter the keys in the same way I can simply filter the values. So if I filter the values on "return the elements that are bigger than 0.2" would be
print_r(array_filter($myArray,"biggerThanFilter");
with
function biggerThanFilter($v){
return $v>0.2;
}
But how would I apply a filter to the keys which say the "keyValueIsBiggerThan50"
i.e something like this
print_r(array_KEY_filter($myArray,"keyValueIsBiggerThan50");
function keyValueIsBiggerThan50($key){
return $key*1>50;
}
I would loop through the array_keys and unset, personally:
function array_filter_keys($array, callable $fn)
foreach (array_keys($array) as $key) {
if (!$fn($key)) unset($array[$key])
}
return $array;
}
$filtered_array = array_filter_keys($array, function($key) { return $key > 50 });
This assumes PHP >= 5.4
function keyValueIsBiggerThan50 ($myArray) {
$newArray = array();
foreach($myArray as $key => $value){
if($key * 1 > 50){
$newArray[$key] = $value
}
}
return $newArray;
}
to be used like
print_r(keyValueIsBiggerThan50 ($myArray));
Are you looking for this specific case, or a generic?
For PHP 5.6+ my answer to a similar question also applies to this one: use ARRAY_FILTER_USE_KEY
<?php
$myArray = ['28' => 0.01, '51' => -0.1, '48' => 0.4, '53' => -0.3];
$filtered = array_filter(
$myArray,
function ($key) {
return $key > 50;
},
ARRAY_FILTER_USE_KEY
);
?>
For PHP < 5.6, array_diff_ukey performs a custom comparison of two arrays by key and appears to do a full N x M comparison so you can filter a single array by using a dummy as the second array.
Using PHP 5.5.9, I used the following to remove the numeric key elements from an array:
$res = array_diff_ukey($res, array(0), function ($a,$b){ return is_string($a); });
I'm using the max() function to find the largest value in an array. I need a way to return the key of that value. I've tried playing with the array_keys() function, but all I can get that to do is return the largest key of the array. There has to be a way to do this but the php manuals don't mention anything.
Here's a sample of the code I'm using:
$arrCompare = array('CompareOne' => $intOne,
'CompareTwo' => $intTwo,
'CompareThree' => $intThree,
'CompareFour' => $intfour);
$returnThis = max($arrCompare);
I can successfully get the highest value of the array, I just can't get the associated key. Any ideas?
Edit: Just to clarify, using this will not work:
$max_key = max( array_keys( $array ) );
This compares the keys and does nothing with the values in the array.
array_search function would help you.
$returnThis = array_search(max($arrCompare),$arrCompare);
If you need all keys for max value from the source array, you can do:
$keys = array_keys($array, max($array));
Not a one-liner, but it will perform the required task.
function max_key($array)
{
$max = max($array);
foreach ($array as $key => $val)
{
if ($val == $max) return $key;
}
}
From http://cherryblossomweb.de/2010/09/26/getting-the-key-of-minimum-or-maximum-value-in-an-array-php/
I know there is array_unique function, but I want to remove duplicates. Is there a built-in function or do I have to roll my own.
Example input:
banna, banna, mango, mango, apple
Expected output:
apple
You can use a combination of array_unique, array_diff_assoc and array_diff:
array_diff($arr, array_diff_assoc($arr, array_unique($arr)))
You can use
$singleOccurences = array_keys(
array_filter(
array_count_values(
array('banana', 'mango', 'banana', 'mango', 'apple' )
),
function($val) {
return $val === 1;
}
)
)
See
array_count_values — Counts all the values of an array
array_filter — Filters elements of an array using a callback function
array_keys — Return all the keys or a subset of the keys of an array
callbacks
Just write your own simple foreach loop:
$used = array();
$array = array("banna","banna","mango","mango","apple");
foreach($array as $arrayKey => $arrayValue){
if(isset($used[$arrayValue])){
unset($array[$used[$arrayValue]]);
unset($array[$arrayKey]);
}
$used[$arrayValue] = $arrayKey;
}
var_dump($array); // array(1) { [4]=> string(5) "apple" }
have fun :)
If you want to only leave values in the array that are already unique, rather than select one unique instance of each value, you will indeed have to roll your own. Built in functionality is just there to sanitise value sets, rather than filter.
You want to remove any entries that have duplicates, so that you're left with only the entries that were unique in the list?
Hmm it does sound like something you'll need to roll your own.
There is no existing function; You'll have to do this in two passes, one to count the unique values and one to extract the unique values:
$count = array();
foreach ($values as $value) {
if (array_key_exists($value, $count))
++$count[$value];
else
$count[$value] = 1;
}
$unique = array();
foreach ($count as $value => $count) {
if ($count == 1)
$unique[] = $value;
}
The answer on top looks great, but on a side note: if you ever want to eliminate duplicates but leave the first one, using array_flip twice would be a pretty simple way to do so. array_flip(array_flip(x))
Only partially relevant to this specific question - but I created this function from Gumbo's answer for multi dimensional arrays:
function get_default($array)
{
$default = array_column($array, 'default', 'id');
$array = array_diff($default, array_diff_assoc($default, array_unique($default)));
return key($array);
}
In this example, I had cached statuses and each one other than the default was 0 (the default was 1). I index the default array from the IDs, and then turn it into a string. So to be clear - the returned result of this is the ID of the default status providing it's in the same part of the multi dimensional array and not the key of it
PHP.net http://php.net/manual/en/function.array-unique.php
array array_unique ( array $array [, int $sort_flags = SORT_STRING ] )
Takes an input array and returns a new array without duplicate values.
New solution:
function remove_dupes(array $array){
$ret_array = array();
foreach($array as $key => $val){
if(count(array_keys($val) > 1){
continue;
} else {
$ret_array[$key] = $val;
}
}