SQL SELECT id WHERE emails are the same - php

Question

I do not know if it's possible at all, but I have two tables, userBasic and carPlateConfidence, in carPlateConfidence I would like to insert id of userBasic where emails are matched.
$query .= "INSERT IGNORE INTO userBasic (id_uM, userNameG, userEmailG) values ((SELECT id_uM FROM userMore WHERE userEmailG='$userEmailG'),'$userNameG', '$userEmailG');";
$query .= "INSERT IGNORE INTO carPlateConfidence (emailConfid, id_uB,plateNumber, confidencePlate, plateNumberUn) values ('$userEmailG', (SELECT id_uB FROM userBasic WHERE userEmailG='(SELECT max(emailConfid) FROM carPlateConfidence)'), '$plateNumber','$confidencePlate', '$plateNumberUn');";
So if I have:
userBasic:
id_uM = 555;
userNameG = BlaBla;
userEmailG = blabla#blabla.com
And in this table I would like
carPlateConfidence:
emailConfid = blabla#blabla.com;
id_uB = 555
plateNumber = 1111
confidencePlate = 70
plateNumberUn = 2222
AND if email do not matched:
emailConfid = blabla2#blabla.com;
id_uB = NULL
plateNumber = 1111
confidencePlate = 70
plateNumberUn = 222
P>S> Currently I have tried this, to select id from userBasic:
(SELECT id_uB FROM userBasic WHERE userEmailG='(SELECT max(emailConfid) FROM carPlateConfidence)')
id_uB in carPlateConfidence is set as foreign key;
Tables:
--
-- Table structure for table `carPlateConfidence`
--
DROP TABLE IF EXISTS `carPlateConfidence`;
CREATE TABLE IF NOT EXISTS `carPlateConfidence` (
`id_cof` int(11) NOT NULL AUTO_INCREMENT,
`id_uB` int(11) NOT NULL,
`emailConfid` varchar(50) NOT NULL,
`plateNumber` varchar(10) NOT NULL,
`confidencePlate` varchar(10) DEFAULT NULL,
`plateNumberUn` varchar(10) DEFAULT NULL,
PRIMARY KEY (`id_cof`),
KEY `id_uB` (`id_uB`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;
-- --------------------------------------------------------
--
-- Table structure for table `userBasic`
--
DROP TABLE IF EXISTS `userBasic`;
CREATE TABLE IF NOT EXISTS `userBasic` (
`id_uB` int(11) NOT NULL AUTO_INCREMENT,
`id_uM` int(11) NOT NULL,
`userNameG` varchar(50) NOT NULL,
`userEmailG` varchar(50) NOT NULL,
PRIMARY KEY (`id_uB`),
UNIQUE KEY `userEmailG` (`userEmailG`),
KEY `id_uM` (`id_uM`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=119 ;
--
-- Constraints for dumped tables
--
--
-- Constraints for table `carPlateConfidence`
--
ALTER TABLE `carPlateConfidence`
ADD CONSTRAINT `carPlateConfidence_ibfk_1` FOREIGN KEY (`id_uB`) REFERENCES `userBasic` (`id_uB`);
--
-- Constraints for table `userBasic`
--
ALTER TABLE `userBasic`
ADD CONSTRAINT `userBasic_ibfk_1` FOREIGN KEY (`id_uM`) REFERENCES `userMore` (`id_uM`);

Answer 1

So you want an update, not an insert :
UPDATE carPlateConfidence t
SET t.id_uB = (SELECT distinct s.id_uM FROM userBasic s
WHERE s.userEmailG = t.emailConfid)
This will work only if there can be only 1 match, if there can be more then one match you should specify which one you want, if it doesn't matter, either use MAX() or limit :
UPDATE carPlateConfidence t
SET t.id_uB = (SELECT max(s.id_uM) FROM userBasic s
WHERE s.userEmailG = t.emailConfid)