Finds related data from mysql table - php

Question

These are the two table structure of my db
-- Table structure for table `gf_actor`
CREATE TABLE IF NOT EXISTS `gf_actor` (
`actor_id` bigint(20) NOT NULL auto_increment,
`actor_name` varchar(100) default NULL,
PRIMARY KEY (`actor_id`),
UNIQUE KEY `actor_name` (`actor_name`)
) ENGINE=MyISAM;
-- Table structure for table `gf_film_actor`
CREATE TABLE IF NOT EXISTS `gf_film_actor` (
`film_id` int(20) NOT NULL,
`actor_id` int(20) NOT NULL,
KEY `film_id` (`film_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
So i need a query which fetches five related actors name and id from gf_actor table who is having acted in movies which was performed by the actor_id lets say actor_id=1 and movies must be different that means five related actors must be acted in different movies with the actor_id=1

Answer 1

Try this
select ga.actor_id, actor_name from gf_actor ga inner join gf_film_actor gf on ga.actor_id = gf.actor_id where gf.film_id in (select gf1.film_id from gf_film_actor gf1 where gf1.actor_id=1) AND gf.actor_id != 1 LIMIT 5

Answer 2

You have wrong table structure. It should be like:
CREATE TABLE IF NOT EXISTS `gf_actor` (
`actor_id` bigint(20) NOT NULL auto_increment,
`actor_name` varchar(100) default NULL,
PRIMARY KEY (`actor_id`),
UNIQUE KEY `actor_name` (`actor_name`)
) ENGINE=MyISAM;
CREATE TABLE IF NOT EXISTS `gf_film` (
`film_id` int(20) NOT NULL,
`performed_by_actor_id` bigint(20) NOT NULL,
KEY `film_id` (`film_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS `gf_film_actor` (
`film_id` int(20) NOT NULL,
`actor_id` bigint(20) NOT NULL,
KEY `film_actor_id` (`film_id`, `actor_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
And now you can create your query like this:
SELECT a.*
FROM `gf_film` AS f
LEFT JOIN `gf_film_actor` AS fa ON f.`film_id` = fa.`film_id`
LEFT JOIN `gf_actor` AS a ON fa.`actor_id` = a.`actor_id`
WHERE f.`performed_by_actor_id` = 1
LIMIT 0, 5;