i want to use json result in some calculation but whatever i try it didn't work.
<?php
//product id
$gp_id=$_GET['gp_id'];
//Importing the database connection
require_once('dbConnect.php');
$sql2 = "SELECT sum(rating_score) AS total_rate ,count(consumer_id) AS consumer
FROM productrate
WHERE gp_id='$gp_id'";
//Getting result
$result = mysql_query($sql2);
//Adding results to an array
$res = array();
while($row = mysql_fetch_array($result))
{
array_push($res, array(
// "gp_id"=>$row['gp_id'],
"total_rate"=>$row['total_rate'],
"consumer"=>$row['consumer']
)
); }
//Displaying the array in json format
$objJson=json_encode($res);
echo $objJson;
//calculate avg rate of specific product
$avg_rate = (int)"total_rate" / (int)"consumer";
echo $avg_rate ;
?>
as you see at the end i try to do some calculation but it didn't work.
this is the output...
[{"total_rate":"18","consumer":"4"}]
Warning: Division by zero in C:\xampp\htdocs\totalrate\highRate.php on line 33
$objJson=json_encode($res); makes json string. For example '{"a":1,"b":2,"c":3,"d":4,"e":5}'. You cannot use it like variables. Its string.
$avg_rate = "total_rate" / "consumer";
Looks like you trying to divide a string with another string.
Try using the array element instead, like:
$avg_rate = $res["total_rate"] / $res["consumer"];
finally i solve the problem ...
//product id
$gp_id=$_GET['gp_id'];
//Importing the database connection
require_once('dbConnect.php');
$sql2 = "SELECT sum(rating_score) AS total_rate ,count(consumer_id) AS consumer
FROM productrate
WHERE gp_id='$gp_id'";
//Getting result
$result = mysql_query($sql2) or die(mysql_error());
//Adding results to an array
$res = array();
while($row = mysql_fetch_array($result))
{
array_push($res, array(
"avg_rate"=>$row['total_rate']/ $row['consumer'],
"total_rate"=>$row['total_rate'],
"consumer"=>$row['consumer']
)
); }
//Displaying the array in json format
$objJson=json_encode($res);
echo $objJson;
?>
Related
i want to put comma's in numbers
The output is this which is encoded in json array
[{"total2":"7619627.0000"}]
I want to change the number in this format
[{"total2":"7,619,627"}]
heres the php code
$sql2 = "SELECT SUM(NettoPrice) AS total2 FROM Sales WHERE OrderType = 8";
$result2 = $conn->query($sql2);
// output data of each row
while($row[] = $result2->fetch_assoc()) {
$json = json_encode($row);
}
echo $json;
$conn->close();
?>
With MYSQL 5.5:
SELECT FORMAT(SUM(NettoPrice),0) AS total2;
SQL fiddle
With PHP
number_format('7619627.0000',0);
Use number_format();
$row[count($row)-1]['total2'] = number_format($row[count($row)-1]['total2']);
$json = json_encode($row);
I am trying to fetch the list of id's associated with mobile number using following code.
$sql = "SELECT id FROM complaints WHERE mobile=1555521555";
$r = mysqli_query($conn,$sql);
$res = mysqli_fetch_array($r);
$result = array();
array_push($result,array(
"id"=>$res['id']
)
);
header('Content-Type:application/json');
echo json_encode(array("result"=>$result));
mysqli_close($conn);
But it only result me a single id every time as below instead of list of id's
{"result":[{"id":"82925318"}]}
Actual query result is -
How do I get the multiple results in array of arrays format or in multidimensional array? Like below -
{"result":[{"id":"82925318"}, {"id":"82925319"}]}
You need loop to get all data
$result = array();
while($res = mysqli_fetch_array($r))
{
array_push($result,array(
"id"=>$res['id']
)
);
}
I have two tables billing_all and payment_details. I am trying to write php code such that I can run the 2 queries in the same php code and encode their data in json format.I am currently using the following code to achieve that without json encode :-
<?php
include "config.php";
$dbname ="webappdb";
$con = mysqli_connect($server_name,$mysql_user,$mysql_pass,$dbname);
if(!$con)
{
echo "Connection Error".mysqli_connect_error();
}
else{
//echo "";
}
$sql = "SELECT SUM(total_wt) FROM `billing_all` WHERE date ='15-Apr-2016';";
$sql .= "SELECT pymt_amount, mode_of_pymt FROM `payment_details` WHERE DATE ='15-Apr-2016';";
// Execute multi query
if (mysqli_multi_query($con,$sql))
{
do
{
// Store first result set
if ($result=mysqli_store_result($con)) {
// Fetch one and one row
while ($row=mysqli_fetch_row($result))
{
printf("%s%s\n",$row[0],$row[1]);
}
// Free result set
mysqli_free_result($result);
}
}
while (mysqli_next_result($con));
}
mysqli_close($con);
?>
How can I encode the received data in json format? I tried something like:-
// Store first result set
if ($result=mysqli_store_result($con))
{
$r = array();
while($row = mysqli_fetch_array($result))
{
array_push($r,
array('total_wt'=>$row[0],
'pymt_amount'=>$row[0],$row[1],
'mode_of_pymt'=>$row[0],$row[1]));
}
echo json_encode(array("result"=>$r));
Which does not give me the expected result.How can I encode the data
in the right way? The following is the structure for the 2 tables
I am new to programming any help is appreciated.Thank you?
<?php
//Joining both tables on the basis of doc_no column
$sql = "SELECT billing_all.SUM(total_wt) AS total
,payment_details.pymt_amount
,payment_details.mode_of_pymt
FROM billing_all
,payment_details
WHERE billing_all.doc_no = payment_details.doc_no
AND billing_all.DATE = '15-Apr-2016'";
// Executing query
$res = mysqli_query($con,$sql);
//initializing array to store result
$rows = array();
//Iterating result and storing each row in $r then array $rows to covert result set into array because json accept array as parameter.
while($r = mysqli_fetch_assoc($res))
{
$rows[] = $r;
}
//print whole array in json format
echo json_encode($rows); ?>
I want to convert selected result into JSON.
Here is my code:
<?php
include("DbConnect.php");
$connection=new DbConnect();
$sth = mysqli_query($connection->_con,"SELECT * FROM account WHERE ac_id='1'");
if($sth){
$rows = array();
while($row = mysqli_fetch_assoc($sth)){
$users = mysqli_query($connection->_con,"SELECT user.user_id,user.name,user.email,ac_detail.ac_id,ac_detail.amount FROM user,ac_detail WHERE ac_detail.ac_id='1' AND user.user_id=ac_detail.user_id");
$usersArray = array();
while($userRow = mysqli_fetch_assoc($users)){
$usersArray[]=$userRow;
}
$a=array("users"=>$usersArray);
//$row["user"]=$usersArray
array_push($row,$a);
$rows[] = $row;
}
echo json_encode(array('data'=>$rows));
}else{
echo json_encode(array('message'=>'error - 2'));
}
?>
By executing this code it generate JSON like :
{"data":[{"ac_id":"1","user_id":"2","title":"Travel","ac_for":"Traveling","required_amount":"50","current_amount":"0","initial_date":"2014-11-11","final_date":"2014-11-14","is_shared":"1","status":"1","0":{"users":[{"user_id":"2","name":"Muhammad Imran","email":"macrotechnolgies#gmail.com","ac_id":"1","amount":"0"},{"user_id":"3","name":"Muhammad Imran","email":"macrotecholgies#gmail.com","ac_id":"1","amount":"0"}]}}]}
But i don't want "0"{"user::...}
How it should be (Expected Results) :
{"data":[{"ac_id":"1","user_id":"2","title":"Travel","ac_for":"Traveling","required_amount":"50","current_amount":"0","initial_date":"2014-11-11","final_date":"2014-11-14","is_shared":"1","status":"1","users":[{"user_id":"2","name":"Muhammad Imran","email":"macrotechnolgies#gmail.com","ac_id":"1","amount":"0"},{"user_id":"3","name":"Muhammad Imran","email":"macrotecholgies#gmail.com","ac_id":"1","amount":"0"}]}]}
Thanks in advance
You're doing:
while($row = mysqli_fetch_assoc($sth)){
[...snip...]
array_push($row,$a);
The while line creates an array $row, which you then use parts of to create $a. You then push that $a BACK onto the original $row array. But $row is an associative array already, so the pushed $a gets key 0.
Since you're now mixing an associative array (non-numeric keys) with a numeric-keyed array (the push operation), PHP MUST add the numeric key to your pushed item: You can't have an element in an array WITHOUT a key.
Then, since JS doesn't allow actual JS arrays ([]) to have non-numeric keys, the whole thing has to get converted into an object ({}).
What you probably want is something more like:
while($row = ...) {
... build $a ...
array_push($row['users'], $a);
instead.
Why don't you in stead array_push($row,$a) try following:
<?php
include("DbConnect.php");
$connection=new DbConnect();
$sth = mysqli_query($connection->_con,"SELECT * FROM account WHERE ac_id='1'");
if($sth){
$rows = array();
while($row = mysqli_fetch_assoc($sth)){
$users = mysqli_query($connection->_con,"SELECT user.user_id, user.name, user.email, ac_detail.ac_id, ac_detail.amount FROM user,ac_detail WHERE ac_detail.ac_id='1' AND user.user_id=ac_detail.user_id");
$usersArray = array();
while($userRow = mysqli_fetch_assoc($users)){
$usersArray[]=$userRow;
}
// here comes the change
// $a = array("users"=>$usersArray);
// //$row["user"]=$usersArray
// array_push($row,$a);
$row['users'] = $usersArray;
$rows[] = $row;
}
echo json_encode(array('data'=>$rows));
}else{
echo json_encode(array('message'=>'error - 2'));
}
This should work. Dont have sample data to test it.
I would want to create an array that will hold records retrieved from a database using a query of SELECT statement.
The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function?
alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..
<?php
// run query
$query = mysql_query("SELECT * FROM table");
// set array
$array = array();
// look through query
while($row = mysql_fetch_assoc($query)){
// add each row returned into an array
$array[] = $row;
// OR just echo the data:
echo $row['username']; // etc
}
// debug:
print_r($array); // show all array data
echo $array[0]['username']; // print the first rows username
You shouldn't search through that array, but use database capabilities for this
Suppose you're passing username through GET form:
if (isset($_GET['search'])) {
$search = mysql_real_escape_string($_GET['search']);
$sql = "SELECT * FROM users WHERE username = '$search'";
$res = mysql_query($sql) or trigger_error(mysql_error().$sql);
$row = mysql_fetch_assoc($res);
if ($row){
print_r($row); //do whatever you want with found info
}
}
$mysearch="Your Search Name";
$query = mysql_query("SELECT * FROM table");
$c=0;
// set array
$array = array();
// look through query
while($row = mysql_fetch_assoc($query)){
// add each row returned into an array
$array[] = $row;
$c++;
}
for($i=0;$i=$c;$i++)
{
if($array[i]['username']==$mysearch)
{
// name found
}
}
$memberId =$_SESSION['TWILLO']['Id'];
$QueryServer=mysql_query("select * from smtp_server where memberId='".$memberId."'");
$data = array();
while($ser=mysql_fetch_assoc($QueryServer))
{
$data[$ser['Id']] =array('ServerName','ServerPort','Server_limit','email','password','status');
}