Convert Selected row to JSON - PHP - php

Question

I want to convert selected result into JSON.
Here is my code:
<?php
include("DbConnect.php");
$connection=new DbConnect();
$sth = mysqli_query($connection->_con,"SELECT * FROM account WHERE ac_id='1'");
if($sth){
$rows = array();
while($row = mysqli_fetch_assoc($sth)){
$users = mysqli_query($connection->_con,"SELECT user.user_id,user.name,user.email,ac_detail.ac_id,ac_detail.amount FROM user,ac_detail WHERE ac_detail.ac_id='1' AND user.user_id=ac_detail.user_id");
$usersArray = array();
while($userRow = mysqli_fetch_assoc($users)){
$usersArray[]=$userRow;
}
$a=array("users"=>$usersArray);
//$row["user"]=$usersArray
array_push($row,$a);
$rows[] = $row;
}
echo json_encode(array('data'=>$rows));
}else{
echo json_encode(array('message'=>'error - 2'));
}
?>
By executing this code it generate JSON like :
{"data":[{"ac_id":"1","user_id":"2","title":"Travel","ac_for":"Traveling","required_amount":"50","current_amount":"0","initial_date":"2014-11-11","final_date":"2014-11-14","is_shared":"1","status":"1","0":{"users":[{"user_id":"2","name":"Muhammad Imran","email":"macrotechnolgies#gmail.com","ac_id":"1","amount":"0"},{"user_id":"3","name":"Muhammad Imran","email":"macrotecholgies#gmail.com","ac_id":"1","amount":"0"}]}}]}
But i don't want "0"{"user::...}
How it should be (Expected Results) :
{"data":[{"ac_id":"1","user_id":"2","title":"Travel","ac_for":"Traveling","required_amount":"50","current_amount":"0","initial_date":"2014-11-11","final_date":"2014-11-14","is_shared":"1","status":"1","users":[{"user_id":"2","name":"Muhammad Imran","email":"macrotechnolgies#gmail.com","ac_id":"1","amount":"0"},{"user_id":"3","name":"Muhammad Imran","email":"macrotecholgies#gmail.com","ac_id":"1","amount":"0"}]}]}
Thanks in advance

Answer 1

You're doing:
while($row = mysqli_fetch_assoc($sth)){
[...snip...]
array_push($row,$a);
The while line creates an array $row, which you then use parts of to create $a. You then push that $a BACK onto the original $row array. But $row is an associative array already, so the pushed $a gets key 0.
Since you're now mixing an associative array (non-numeric keys) with a numeric-keyed array (the push operation), PHP MUST add the numeric key to your pushed item: You can't have an element in an array WITHOUT a key.
Then, since JS doesn't allow actual JS arrays ([]) to have non-numeric keys, the whole thing has to get converted into an object ({}).
What you probably want is something more like:
while($row = ...) {
... build $a ...
array_push($row['users'], $a);
instead.

Answer 2

Why don't you in stead array_push($row,$a) try following:
<?php
include("DbConnect.php");
$connection=new DbConnect();
$sth = mysqli_query($connection->_con,"SELECT * FROM account WHERE ac_id='1'");
if($sth){
$rows = array();
while($row = mysqli_fetch_assoc($sth)){
$users = mysqli_query($connection->_con,"SELECT user.user_id, user.name, user.email, ac_detail.ac_id, ac_detail.amount FROM user,ac_detail WHERE ac_detail.ac_id='1' AND user.user_id=ac_detail.user_id");
$usersArray = array();
while($userRow = mysqli_fetch_assoc($users)){
$usersArray[]=$userRow;
}
// here comes the change
// $a = array("users"=>$usersArray);
// //$row["user"]=$usersArray
// array_push($row,$a);
$row['users'] = $usersArray;
$rows[] = $row;
}
echo json_encode(array('data'=>$rows));
}else{
echo json_encode(array('message'=>'error - 2'));
}
This should work. Dont have sample data to test it.