Bootstrap dropdown based on content of MySQL table [closed] - php

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Using Bootstrap, PHP and MySQL, how do I populate a dropdown selection based on the contents of a mysql table.
For example I have a table user.
tblUsers
- id
- name
- email
How would a simple example of the PHP and HTML code look?

<?PHP
$yourquery = (select id, name from tblUsers);
echo '<select>';
foreach($yourquery as $qry){
echo '<option value="'.$qry->id.'">'.$qry->name.'</option>';
}
echo '</select>';
?>

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How to fetch only numerical values from table field [closed]

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I have a table which stores student details like name,Phone no,address and other basic details.In address field stores student address like : ABC apartment;Lat:21.1111;Long:71.1111.Now I want to write a MySQL select query that gives me only 21.1111 and 71.1111 as result.which matching function should i use to get the required result.
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(`address`, 'Lat:', -1), ';', 1) AS Latitude,
SUBSTRING_INDEX(SUBSTRING_INDEX(`address`, 'Long:', -1), ';', 1) AS Longtude
FROM student_details;

Query db with in exlusion [closed]

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Trying to query db. I need to show all fields, but need to exclude one name that is in the db.
Example:
The db contains column 'marketer' when I try to query it I don't want marketer 'Tommy' but all the others. I have tried tried where clause with all the names and not working.
This is the query you're looking for
SELECT * FROM <table_name> WHERE marketer<>'Tommy';
use the 'where' to add your conditions
SELECT * FROM your_table WHERE marketer!='Tommy'
For your Reference
http://www.w3schools.com/sql/sql_where.asp

Echo name of fields from MySQL table to web page [closed]

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How do I display all field names from a MySQL table to a web page when I only know the table name?
Use the information_schema meta-DB:
SELECT COLUMN_NAME
FROM information_schema.TABLES
WHERE (TABLE_SCHEMA='Yourdb') AND (TABLE_NAME = 'Yourtablename')
In addition to #MarcB's suggestion, you can also do:
SHOW COLUMNS FROM table
http://dev.mysql.com/doc/refman/5.6/en/show-columns.html

How to print data from SQL database to HTML table based on query [closed]

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so I have records in my database that I would like to print to a HTML table IF they belong to the user.
$sql="SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
The table would read :
Date, Room, Period , Cancel
With cancel being a red cross designed to delete that specific entry from the database :
Booking ID, Date, Period,Type,RoomID, Username are the fields in the database.
How would I go about doing this? I was thinking echoing a table using a for loop but I wouldn't know where to begin?
Try:
$query_rsSearch = "SELECT * FROM ".$tbl_name." WHERE Username='".$username."'";
$rsSearch = mysql_query($query_rsSearch) or die(mysql_error());
$row_rsSearch = mysql_fetch_assoc($rsSearch);
$totalRows_rsSearch = mysql_num_rows($rsSearch);
do {
echo $row_rsSearch['Date']." | ".$row_rsSearch['Room']." | ".$row_rsSearch['Period'];
} while($row_rsSearch = mysql_fetch_assoc($rsSearch));

How to select all fields where a string is common in all the tables in a mysql database? [closed]

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I have a mysql database where there is 3 tables 'groupstage', 'quarterfinal,' semifinal. All of these table have a column named 'Date'. Now I want to write a query from where I can get all the fields from those tables with a specific date? what should i write it in php?
To get what you want, you can write a query which join the 3 tables like :
SELECT *
FROM groupstage, quarterfinal, semifinal
WHERE groupstage.date = quarterfinal.date AND quarterfinal.date = semifinal.date
AND date = "YOUR DATE"
In php you should just create a var $query = "My query above"

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