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Trying to query db. I need to show all fields, but need to exclude one name that is in the db.
Example:
The db contains column 'marketer' when I try to query it I don't want marketer 'Tommy' but all the others. I have tried tried where clause with all the names and not working.
This is the query you're looking for
SELECT * FROM <table_name> WHERE marketer<>'Tommy';
use the 'where' to add your conditions
SELECT * FROM your_table WHERE marketer!='Tommy'
For your Reference
http://www.w3schools.com/sql/sql_where.asp
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I'm using
productinfo (`productId`, `productName`, `productPrice`, `productSaleprice`, `productImage`, `productLink`, `productColor`, `productSize`, `categoryId`, `sourceProductId`, `sourceId`)
where productinfo is table, And i display products on the basis of productPrice and productSaleprice.
At this moment I fetch all results and calculate everything in PHP like this:
$diff=$productPrice-$productSaleprice;
$result=($diff)/($productPrice/100);
My question is, is it possible to calculate the same things in MySQl without using PHP?
The result should be displayed in DESC Order
I think below SQL useful to you.
select `productId`, `productName`, productPrice, productPrice, productPrice-productSaleprice as diff ,
(productPrice-productSaleprice)/(productPrice/100) as result
from productinfo
where category= 5
order by result desc;
Thank you
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How do I display all field names from a MySQL table to a web page when I only know the table name?
Use the information_schema meta-DB:
SELECT COLUMN_NAME
FROM information_schema.TABLES
WHERE (TABLE_SCHEMA='Yourdb') AND (TABLE_NAME = 'Yourtablename')
In addition to #MarcB's suggestion, you can also do:
SHOW COLUMNS FROM table
http://dev.mysql.com/doc/refman/5.6/en/show-columns.html
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SELECT * FROM 'table' WHERE name IN ('abs', 'airbag_id', 'alarm')
This code make: 'abs' OR 'airbag_id' OR 'alarm'
I need to make: 'abs' AND 'airbag_id' AND 'alarm'
How can I do it with something like "IN".
I don't need something like this:
SELECT * FROM 'table' WHERE name = 'abs' AND name = 'airbag_id' AND name = 'alarm'
...because I will use to many AND's.
Any idea?
You probably need a single column result having all these names. You can do it like this
SELECT some_column_you_group_by
FROM your_table
WHERE name IN ('abs', 'airbag_id', 'alarm')
group by some_column_you_group_by
having count(distinct name) = 3
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I have a query that is returning a different amount of user_id's each time it's run (based on the number of subscribers).
What I need to do is insert each of these user_id results into separate rows within a table along with a simple message of "new alert" in a separate column.
How could I possibly go about doing this? Would a for each loop work in this situation?
Try this:
INSERT INTO alert_table SELECT user_id, 'new alert' FROM ... WHERE ...
Use your own query, just prepend it with the INSERT INTO alert_table clause.
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I have a mysql database where there is 3 tables 'groupstage', 'quarterfinal,' semifinal. All of these table have a column named 'Date'. Now I want to write a query from where I can get all the fields from those tables with a specific date? what should i write it in php?
To get what you want, you can write a query which join the 3 tables like :
SELECT *
FROM groupstage, quarterfinal, semifinal
WHERE groupstage.date = quarterfinal.date AND quarterfinal.date = semifinal.date
AND date = "YOUR DATE"
In php you should just create a var $query = "My query above"