i got his small code
<?php
if (preg_match("/Remanufactured|REMANUFACTURED/",$product_info['products_description'] )
|| preg_match("/N2|N3|W1|W2|A1|A2|A3|R4/",$product_info['manufacturers_code'])) {
echo "Refurbished";
} else {
echo "New Boxed";
}
?>
if $product_info['manufacturers_code'] = '2122586R4' or 'MC-MCB43112U0C2/04/1' the above code works.
I want the above code to only match where the last two characters are "/N2|N3|W1|W2|A1|A2|A3|R4/"
i have tried "/N2$|N3$|W1$|W2$|A1$|A2$|A3$|R4$/" and it doesnt work.
regards
irfan
Replace
/N2|N3|W1|W2|A1|A2|A3|R4/
With
/^(.*)(N2|N3|W1|W2|A1|A2|A3|R4)$/
.* will match any string at the beginning and the specified two string at end
Try this
preg_match('/(N2|N3|W1|W2|A1|A2|A3|R4)$/',$product_info['manufacturers_code'])
( ) - Groups a series of pattern elements to a single element.
| - Separates alternate possibilities.
$ - Matches the end of a line or string.
so "(a|b)" means "a or b". "(a|b)$" means "a or b" at the end of a line or string.
Related
I have this autogenerated variable:
$var = "WXYZ 300700Z 32011KT 9999 FEW035 SCT200 24/16 Q1007 NOSIG";
How can I search and save "9999" in this var? I cant use substr cause $var's value is always changing and it is always in another "place" in the variable. It is always 4 numbers.
You can match 4 numbers wrapped by word boundaries or space characters, depending on what you need with regular expression (regex/regexp).
if( preg_match('/\b([0-9]{4})\b/', $var, $matches) > 0 ) {
// $matches[1] contains the number
}
Note, however, that the word boundary match will also match on non-letter characters (symbols like dollar sign ($), hyphen (-), period (.), comma (,), etc.). So a string of "XYZ ABC 9843-AB YZV" would match the "9843". If you want to just match based on numbers surrounded by white space (spaces, tabs, etc) you can use:
if( preg_match('/(?:^|\s)([0-9]{4})(?:\s|$)/', $var, $matches) > 0 ) {
// $matches[1] contains the number
}
Using explode is the way to go, we need to turn the string into an array, our variables are separated by white space, so we get a variable every time we face a white space " ", i made another example to understand how explode works.
<?php
$var = "WXYZ 300700Z 32011KT 9999 FEW035 SCT200 24/16 Q1007 NOSIG";
print_r (explode(" ",$var)); //Display the full array.
$var_search = explode(" ",$var);
echo $var_search[3];//To echo the 9999 (4th position).
?>
<br>
<?php
$var = "WXYZ+300700Z+32011KT+9999+FEW035+SCT200+24/16+Q1007+NOSIG";
print_r (explode("+",$var)); //Display the full array.
$var_search = explode("+",$var);
echo $var_search[3];//To echo the 9999 (4th position).
?>
I hop this is what you're looking for
Is this viable?
$var = "WXYZ 300700Z 32011KT 9999 FEW035 SCT200 24/16 Q1007 NOSIG";
if (strpos($var, '9999') == true {
// blah blah
}
else{
echo 'Value not found'
}
Personally haven't tested this yet, but I think you're looking for something along these lines...
Hello I would use a preg_match regex using this regular expression : \d{4}
here is the solution
var str1 = "WXYZ 300700Z 32011KT 9999 FEW035 SCT200 24/16 Q1007 NOSIG";
var str2 = "9999";
if(str1.indexOf(str2) != -1){
console.log(str2 + " found");
}
I've been trying to figure this out for 2 hours now with no success. Its a bit complicated for me i guess.
I am trying to parse a script file in PHP and return some values to the user. The ones i want are like this:
_value = object runFunction blah blah blah
Basically what i want is (in an algorithm):
IF case-insensitive runFunction is found in the line (because it might be runfunction)
AND the line starts with _ (underscore) (or if possible before the = there is a value that starts with _ to be sure of the result)
THEN return that underscore value before the = to me.
Usually 99.9% the format is like this...But there are small cases it can be like this:
_value = _object runFunction blah blah blah
(in case the _ after the = messes things up).
Any help here :) ?
Thanks
try something like:
$str = 'YOUR FILE CONTENTS HERE';
$match = preg_match_all('/(_[a-zA-Z0-9_]+) ?= ?[a-zA-Z0-9_]+ runFunction/s',$str,$matches);
var_dump($matches);
you'll probably need to add the multiline flag.
How about
if (preg_match('/^_([^=]+?)(?=\s*=).*runfunction/im', $subject, $regs)) {
$result = $regs[1];
} else {
$result = "";
}
You can exclude the initial "start" anchor is your underscore might not be at the beginning of the line
Here is the regex by itself. The results are in capturing group 1
^_([^=]+?)(?=\s*=).*runfunction
The regex
look for beginning of line
match the first underscore
capture everything that is not an '=' into capturing group 1
provided it is followed by 0 or more spaces and an equal sign.
then capture everything up to a runfunction.
Case insensitive and multiline options need to be set
If the first underscore does not need to be at the beginning of the line, eliminate the anchor.
My current regular expression should be correct, though I wouldn't expect so, it doesn't work properly. It won't return "Got Match"
My currrent code is as follows:
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("^http://steamcommunity\.com/id/.*?\n$", $id)) {
print "Got match!\n";
}
You're missing delimiters on your regex:
if (preg_match("#^http://steamcommunity\.com/id/.*?\n$#", $id)) {
^--here ^--here
Note that I've used # as the delimiter here, since that saves you having to escape all of the internal / charrs, if you'd used the traditional / as the delimiter.
You need a delimiter, like this:
if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) {
^ ^
And what's with the newline at the end? Surely you don't need that.
You're missing delimiters. For example:
"#^http://steamcommunity\.com/id/.*?\n$#"
Also, you're trying to match a newline (\n) that isn't in your string.
You need to add the pattern delimiter:
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("#^http://steamcommunity\.com/id/.*?(\n|$)#", $id)) {
print "Got match!\n";
}
There are a couple of things that are wrong with it. First of all, you need to delimit the start and end of your regex with a character. I used #. You're also matching for a new line at the end of your regex, which you don't have and likely won't ever have in your string.
<?php
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) {
print "Got match!\n";
}
?>
http://codepad.viper-7.com/L7XctT
First of all, your regex shouldn't even compile because it's missing delimiters.
if (preg_match("~^http://steamcommunity\.com/id/.*?\n$~", $id)) {
^---- these guys here -----^
Second of all, why do you have a \n if your string doesn't contain a new line?
And finally, why are you using regex at all? Effectively, you are just trying to match a constant string. This should be equivalent to what you are trying to match:
if (strpos($id, 'http://steamcommunity.com/id/') === 0) {
You need to have starting and ending delimiter in your pattern like /pattern/ or #pattern# or with brackets (pattern). Why is that? To have some pattern modifiers after ending delimiter like #pattern#i (ignore case)
preg_match('(^http://steamcommunity\.com/id/.*?\n$)', $id)
As the say your patten is start and end wrong. (Delimiter)
But this will be a better match of a 64-bit Steam ID. (Minimum 17 and Maximum 25 numbers)
if( preg_match("#^http://steamcommunity\.com/id/([0-9]{17,25})#i", $id, $matches) )
{
echo "Got match! - ".$matches;
}
I believe that there is no need for you to require that the string must end with a line break.
Explanation.
http://steamcommunity\.com/id/([0-9]{17,25})
^--- string ---^^-- Regexp --^
[0-9] - Match a number between 0 to 9
{17,25} - Make 17 to 25 matches
() - Returns match
Or use pattern as those (It is the same):
/^http:\/\/steamcommunity\.com\/id\/([0-9]{17,25})/i
(^http://steamcommunity\.com/id/([0-9]{17,25}))i
Regular Expressions PHP Tutorial
Online regular expression testing <- Dont use delimiter.
<?php
# URL that generated this code:
# http://txt2re.com/index-php.php3?s=http://steamcommunity.com/id&-1
$txt='http://steamcommunity.com/id';
$re1='(http:\\/\\/steamcommunity\\.com\\/id)'; # HTTP URL 1
if ($c=preg_match_all ("/".$re1."/is", $txt, $matches))
{
$httpurl1=$matches[1][0];
print "($httpurl1) \n";
}
#-----
# Paste the code into a new php file. Then in Unix:
# $ php x.php
#-----
?>
Resorces:
http://txt2re.com/index.php3?s=http://steamcommunity.com/id&-1
I want a regex solution to allow only
http://www.imdb.com/title/ttANYNumberWOrdetc/ links
Otherwise SHOW us error.. Incorrect link
I am not too good with regex
I just create this petren ..
preg_match('/http:\/\/www.imdb.com\/title\/(.*)\//is', 'http://www.imdb.com/title/tt0087469/', $result);
Its show me corect result but i think i missed some thing..
Thanks,
How about something like this: http://(?:www\.)?imdb.com/title/tt[^/]+/.
Example:
<?php
if ( preg_match('#^http://(?:www\.)?imdb\.com/title/tt[^/]+/$#', 'http://www.imdb.com/title/tt0448303/') )
echo 'Matches' . PHP_EOL;
Explanation:
The regular expression matches a string that starts with http:// followed either by imdb.com or www.imdb.com, then /title/tt followed by any character except for a / and that ends with a /.
The # is the delimiter, the ^ indicated the beginning of the string and the $ the end.
This should work:
if (preg_match("#^(http://www.|https://www.)imdb.com/title/tt([a-zA-Z0-9]+)(?:/)(?:^[a-zA-Z0-9]+)?$#s", 'http://www.imdb.com/title/tt0364845/', $matches)) {
echo 'yay';
} else {
echo 'nay';
}
i need to write a case which only except the a-zA-Z0-9 characters with underscore and white space(1 or more than 1) and ignore all rest of the characters.I wrote a code but its not working properly.
In those case should be wrong but its show OK
1) test msg#
2) test#msg
3) test!msg
also those should be OK but currently shows wrong.
1) test msg.-(Two white space)
what i should to change in my code .pls help and see my code below.
$message=$_GET['msg'];
if(preg_match('/[^A-Za-z0-9]\W/',$message))
{
echo "Wrong";
}
else
{
echo "OK";
}
Here's an optimized version of the one left by riad:
$message = $_GET['msg'];
if ( preg_match('/^[a-z0-9_ ]+$/i', $message) )
{
echo 'Ok';
}
else
{
echo 'Wrong';
}
I've removed the A-Z (uppercase) from the regular expression since the i modifier is used.
I'd also like to explain what you did wrong in the example you provided.
First, by putting the ^ inside the square brackets ([]), you're essentially doing the opposite of what you were trying to do. Place a ^ inside the square brackets means "not including."
You were missing a *, + or ? at the end of the square bracket, unless you only wanted to match a single character. The * character means 0 or more, + means 1 or more and ? means 0 or 1.
The \W means any non-word character. That's probably not what you wanted.
Finally, to starting a regular expression with ^ means that the beginning of the string you're string to match must start with whatever is after the ^. Ending the regular expression with a $ means that the string must end with the characters preceding the $.
So by typing /^[a-z0-9_ ]+$/i you're saying match a string that starts with a-z0-9_ or a space, that contains at least of those characters (+) and ends.
PHP has a lot of documentation of the PCRE regular syntax which you can find here: http://ca2.php.net/manual/en/reference.pcre.pattern.syntax.php.
$message=$_GET['msg'];
if(preg_match('/^[a-zA-Z0-9_ ]+$/i',$message))
{
echo "Wrong";
}
else
{
echo "OK";
}