i need to write a case which only except the a-zA-Z0-9 characters with underscore and white space(1 or more than 1) and ignore all rest of the characters.I wrote a code but its not working properly.
In those case should be wrong but its show OK
1) test msg#
2) test#msg
3) test!msg
also those should be OK but currently shows wrong.
1) test msg.-(Two white space)
what i should to change in my code .pls help and see my code below.
$message=$_GET['msg'];
if(preg_match('/[^A-Za-z0-9]\W/',$message))
{
echo "Wrong";
}
else
{
echo "OK";
}
Here's an optimized version of the one left by riad:
$message = $_GET['msg'];
if ( preg_match('/^[a-z0-9_ ]+$/i', $message) )
{
echo 'Ok';
}
else
{
echo 'Wrong';
}
I've removed the A-Z (uppercase) from the regular expression since the i modifier is used.
I'd also like to explain what you did wrong in the example you provided.
First, by putting the ^ inside the square brackets ([]), you're essentially doing the opposite of what you were trying to do. Place a ^ inside the square brackets means "not including."
You were missing a *, + or ? at the end of the square bracket, unless you only wanted to match a single character. The * character means 0 or more, + means 1 or more and ? means 0 or 1.
The \W means any non-word character. That's probably not what you wanted.
Finally, to starting a regular expression with ^ means that the beginning of the string you're string to match must start with whatever is after the ^. Ending the regular expression with a $ means that the string must end with the characters preceding the $.
So by typing /^[a-z0-9_ ]+$/i you're saying match a string that starts with a-z0-9_ or a space, that contains at least of those characters (+) and ends.
PHP has a lot of documentation of the PCRE regular syntax which you can find here: http://ca2.php.net/manual/en/reference.pcre.pattern.syntax.php.
$message=$_GET['msg'];
if(preg_match('/^[a-zA-Z0-9_ ]+$/i',$message))
{
echo "Wrong";
}
else
{
echo "OK";
}
Related
I would like to validate a string with a pattern that can only contain letters (including letters with accents). Here is the code I use and it always returns "nok".
I don't know what I am doing wrong, can you help? thanks
$string = 'é';
if(preg_match('/^[\p{L}]+$/i', $string)){
echo 'ok';
} else{
echo 'nok';
}
Add the UTF-8 modifier flag (u) to your expression:
/^\p{L}+$/ui
There is also no need to wrap \p{L} inside of a character class.
I don't know if this helps anybody that will check this question / thread later. The code below allows only letters, accents and spaces. No symbols or punctuation like .,?/>[-< etc.
<?php
$string = 'États unis and états unis';
if(preg_match('/^[a-zA-Z \p{L}]+$/ui', $string)){
echo 'ok';
} else{
echo 'nok';
}
?>
If you want to add numbers too, just add 0-9 immediately after Z like this a-zA-Z0-9
Then if you are applying this to form validation and you are scared a client/user might just hit spacebar and submit, just use:
if (trim($_POST['forminput']) == "") {... some error message ...}
to reject the submission.
I would like to check and see if a given string contains any characters or if it is just all white space. How can I do this?
I have tried:
$search_term= " ";
if (preg_match('/ /',$search_term)) {
// do this
}
But this affects search terms like this as well:
$search_term= "Mark Zuckerburg";
I only want a condition that checks for all white space and with no characters.
Thanks!
ctype_space does this.
$search_term = " ";
if (ctype_space($search_term)) {
// do this
}
The reason your regular expression doesn’t work is that it’s not anchored anywhere, so it searches everywhere. The right regular expression would probably be ^\s+$.
The difference between ctype_space and trim is that ctype_space returns false for an empty string. Use whatever’s appropriate. (Or ctype_space($search_term) || $search_term === ''…)
Use trim():
if(trim($search_term) == ''){
//empty or white space only string
echo 'Search term is empty';
}
trim() will cut whitespace from both start and end of a string - so if the string contains only whitespace trimming it will return empty string.
I would like to validate a string with a pattern that can only contain letters (including letters with accents). Here is the code I use and it always returns "nok".
I don't know what I am doing wrong, can you help? thanks
$string = 'é';
if(preg_match('/^[\p{L}]+$/i', $string)){
echo 'ok';
} else{
echo 'nok';
}
Add the UTF-8 modifier flag (u) to your expression:
/^\p{L}+$/ui
There is also no need to wrap \p{L} inside of a character class.
I don't know if this helps anybody that will check this question / thread later. The code below allows only letters, accents and spaces. No symbols or punctuation like .,?/>[-< etc.
<?php
$string = 'États unis and états unis';
if(preg_match('/^[a-zA-Z \p{L}]+$/ui', $string)){
echo 'ok';
} else{
echo 'nok';
}
?>
If you want to add numbers too, just add 0-9 immediately after Z like this a-zA-Z0-9
Then if you are applying this to form validation and you are scared a client/user might just hit spacebar and submit, just use:
if (trim($_POST['forminput']) == "") {... some error message ...}
to reject the submission.
My current regular expression should be correct, though I wouldn't expect so, it doesn't work properly. It won't return "Got Match"
My currrent code is as follows:
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("^http://steamcommunity\.com/id/.*?\n$", $id)) {
print "Got match!\n";
}
You're missing delimiters on your regex:
if (preg_match("#^http://steamcommunity\.com/id/.*?\n$#", $id)) {
^--here ^--here
Note that I've used # as the delimiter here, since that saves you having to escape all of the internal / charrs, if you'd used the traditional / as the delimiter.
You need a delimiter, like this:
if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) {
^ ^
And what's with the newline at the end? Surely you don't need that.
You're missing delimiters. For example:
"#^http://steamcommunity\.com/id/.*?\n$#"
Also, you're trying to match a newline (\n) that isn't in your string.
You need to add the pattern delimiter:
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("#^http://steamcommunity\.com/id/.*?(\n|$)#", $id)) {
print "Got match!\n";
}
There are a couple of things that are wrong with it. First of all, you need to delimit the start and end of your regex with a character. I used #. You're also matching for a new line at the end of your regex, which you don't have and likely won't ever have in your string.
<?php
$id = "http://steamcommunity.com/id/TestID";
if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) {
print "Got match!\n";
}
?>
http://codepad.viper-7.com/L7XctT
First of all, your regex shouldn't even compile because it's missing delimiters.
if (preg_match("~^http://steamcommunity\.com/id/.*?\n$~", $id)) {
^---- these guys here -----^
Second of all, why do you have a \n if your string doesn't contain a new line?
And finally, why are you using regex at all? Effectively, you are just trying to match a constant string. This should be equivalent to what you are trying to match:
if (strpos($id, 'http://steamcommunity.com/id/') === 0) {
You need to have starting and ending delimiter in your pattern like /pattern/ or #pattern# or with brackets (pattern). Why is that? To have some pattern modifiers after ending delimiter like #pattern#i (ignore case)
preg_match('(^http://steamcommunity\.com/id/.*?\n$)', $id)
As the say your patten is start and end wrong. (Delimiter)
But this will be a better match of a 64-bit Steam ID. (Minimum 17 and Maximum 25 numbers)
if( preg_match("#^http://steamcommunity\.com/id/([0-9]{17,25})#i", $id, $matches) )
{
echo "Got match! - ".$matches;
}
I believe that there is no need for you to require that the string must end with a line break.
Explanation.
http://steamcommunity\.com/id/([0-9]{17,25})
^--- string ---^^-- Regexp --^
[0-9] - Match a number between 0 to 9
{17,25} - Make 17 to 25 matches
() - Returns match
Or use pattern as those (It is the same):
/^http:\/\/steamcommunity\.com\/id\/([0-9]{17,25})/i
(^http://steamcommunity\.com/id/([0-9]{17,25}))i
Regular Expressions PHP Tutorial
Online regular expression testing <- Dont use delimiter.
<?php
# URL that generated this code:
# http://txt2re.com/index-php.php3?s=http://steamcommunity.com/id&-1
$txt='http://steamcommunity.com/id';
$re1='(http:\\/\\/steamcommunity\\.com\\/id)'; # HTTP URL 1
if ($c=preg_match_all ("/".$re1."/is", $txt, $matches))
{
$httpurl1=$matches[1][0];
print "($httpurl1) \n";
}
#-----
# Paste the code into a new php file. Then in Unix:
# $ php x.php
#-----
?>
Resorces:
http://txt2re.com/index.php3?s=http://steamcommunity.com/id&-1
I am searching through text line by line and want to see if the line contains the phrase "see details" and is not case sensitive, so will find:
See Details, See details, SEE Details etc
I have this so far.
if(preg_match("/^(\see details)/", strtolower($line)))
{
echo 'SEE DETAILS FOUND';
}
A simple example would be helpful thanks.
If you want to check if a sub-string is present in a string, no need for regular expressions : stripos() will do just fine :
if (stripos(strtolower($line), 'see details') !== false) {
// 'see details' is in the $line
}
stripos() will return the position of the first occurrence of the sub-string in the string ; or false if the sub-string is not found.
Which means that if it returns something else than false, the sub-string is found.
Your regex is actually broken.
/^(\see details)/
This breaks down into:
At the beginning
Open a capturing group
Look for one whitespace character
Followed by all of the following characters: ee details
Close the group
\s is an escape sequence matching whitespace. You could also have added the i modifier to make the regex case-insensitive. You also don't seem to be doing anything with the captured group, so you can ditch that.
Therefore:
/^see details/i
is what you'd want.
You mentioned that you're going through input line by line. If you only need to know that the entire input contains the specific string, and you have the input as a string, you can use the m modifier to make ^ match "beginning of a line" instead of / in addition to "beginning of the string":
/^see details/im
If this is the case, then you would end up with:
if(preg_match('/^see details/im', $whole_input)) {
echo "See Details Found!";
}
But as others have mentioned, a regex isn't needed here. You can (and should) do the job with the more simple stripos.
As Pascal said, you can use stripos() function although correct code would be:
if (stripos(strtolower($line), 'see details') !== false) {
// 'see details' is in the $line
}
accoding to the php documentation (http://www.php.net/manual/en/function.preg-match.php):
<?php
/* The \b in the pattern indicates a word boundary, so only the distinct
* word "web" is matched, and not a word partial like "webbing" or "cobweb" */
if (preg_match("/\bweb\b/i", "PHP is the web scripting language of choice.")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
if (preg_match("/\bweb\b/i", "PHP is the website scripting language of choice.")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
?>
which it looks pretty simple and nice :-).