How to select related columns by having just an id number? - php

I have this table:
// mytable
+----+---------+
| id | related |
+----+---------+
| 1 | 1 |
| 2 | 1 |
| 3 | 2 |
| 4 | 1 |
| 5 | 3 |
| 6 | 2 |
| 7 | 4 |
| 8 | 4 |
| 9 | 2 |
+----+---------+
I have just an id number like $id = 6. And I want to select all rows which have identical related. So this is expected result:
// newmytable
+----+---------+
| id | related |
+----+---------+
| 3 | 2 |
| 6 | 2 |
| 9 | 2 |
+----+---------+
How can I do that?
Here is my query but doesn't work:
SELECT *
FROM mytable m
WHERE (SELECT related
FROM mytable
WHERE id = :id) t m.related = t.related

select m2.id, m2.related
from
mytable m1
join mytable m2
on m2.related = m1.related
where m1.id = 6
SQL Fiddle sample

SELECT * FROM mytable
WHERE related = ( SELECT related FROM mytable WHERE id = 6)
Not tested...

Try this
select *from mytable
where related = (select related from mytable where id = 6)

Hello please replace your query with below query you will get your expected output.
SELECT * FROM mytable WHERE = (SELECT related FROM mytable WHERE id = :id)

This will work
SELECT * FROM mytable WHERE related = (SELECT releated FROM mytable WHERE id = 6)

Related

PHP SQL - Retrieve shared values from a another table not as expected

I'm needing to retrieve shared values from a table based on a value from another table, but don't show duplicates.
Example of what tables I have...
Table - members
+-----------------+
| ID | NAME |
+-----------------+
| 1 | Bob |
| 2 | Jack |
| 3 | Jane |
| 4 | Bruce |
| 5 | Clark |
| 6 | Peter |
+-----------------+
Table - groups
+--------------------------------+
| ID | NAME | MANAGER_ID |
+--------------------------------+
| 1 | Group A | 1 | (Bob)
| 2 | Group B | 2 | (Jack)
| 3 | Group C | 1 | (Bob)
+--------------------------------+
Table - group_members
+--------------------------------+
| ID | GROUP_ID | MEMBER_ID |
+--------------------------------+
| 1 | 1 | 3 | (Group A - Jane)
| 2 | 1 | 4 | (Group A - Bruce)
| 3 | 1 | 5 | (Group A - Clark)
| 4 | 1 | 6 | (Group A - Peter)
| 5 | 2 | 3 | (Group B - Jane)
| 6 | 3 | 4 | (Group B - Bruce)
| 7 | 3 | 5 | (Group C - Clark)
+--------------------------------+
What I am needing
(Note: I'm using * in queries here to shorten code.)
If 'Bob' sees all his groups.
Look at 'group_members' table and show all members that belong to it...
$q = SELECT * FROM groups WHERE manager_id = $id;
$r = mysqli_query($dbc, $q);
while ($row = mysqli_fetch-assoc($r) {
$q2 = SELECT *, count(MEMBERS_ID) AS group_count FROM group_members LEFT JOIN members ON group_members.MEMBER_ID = members.id WHERE group_id = '$row[GROUP_ID]';
$r2 = mysqli_query($dbc, $q2);
while ($row2 = mysqli_fetch-assoc($r2) {
echo $row2['name'];
}
}
This shows me the list as expected.
+------------------------+
| NAME | GROUP COUNT |
+------------------------+
| Jane | 1 |
| Bruce | 1 |
| Clark | 1 |
| Peter | 1 |
| Bruce | 1 |
| Clark | 1 |
+------------------------+
I Add GROUP BY group_members.group_id to my 2nd query and that shows.
+------------------------+
| NAME | GROUP COUNT |
+------------------------+
| Jane | 1 |
| Bruce | 2 |
| Clark | 2 |
| Peter | 1 |
+------------------------+
Which is perfect... But here is the problem
if I add a WHERE members.name LIKE \'%clark%\' then it outputs...
+------------------------+
| NAME | GROUP COUNT |
+------------------------+
| | |
| | |
| Clark | 1 |
| | |
| | |
| Clark | 1 |
+------------------------+
It ignores GROUP BY and shows blank rows where other entries would show.
So with all that said. Does any one know why or a better way to do this please?
Been at it for a while now and would really appreciate any assistance.
EDITED:
Here's the full query with all the columns used:
$q = SELECT * FROM groups WHERE manager_id = $id;
$r = mysqli_query($dbc, $q);
while ($row = mysqli_fetch-assoc($r) {
$q2 = SELECT members.id) AS memid, members.first, members.last, members.comname, members.email, members.sector, (members.status) AS memstatus, (group_members.id) AS groupid, (group_members.member_id) AS memidgroup, group_members.group_id, COUNT(group_members.member_id) AS groupcount, member_roles.role FROM members LEFT JOIN group_members ON members.id = group_members.member_id LEFT JOIN member_roles ON members.role_id = member_roles.id WHERE group_id = '$row[GROUP_ID]' AND members.name LIKE '%clark%' GROUP BY group_members.group_id;
$r2 = mysqli_query($dbc, $q2);
while ($row2 = mysqli_fetch-assoc($r2) {
echo $row2['name'];
}
}
Your query or problem is not completely stated. One cannot guess or assume.
Post your last query as well as all queries dont worry about saving the space.
Those blank rows have data that why they are in the table.
Base on your explanation or your query, here is my simple answer
SELECT id,
(select groups.id from groups where groups.id = group_members.group_id )AS group_members_id,
(select groups.name from groups where groups.id = group_members.group_id )AS group_members_name,
(select members.id from members where members.id = group_members.member_id )AS members_id,
(select members.name from members where members.id = group_members.member_id )AS members_name,
count((select members.id from members where members.id = group_members.member_id ) )as members_id_count FROM group_members WHERE (select members.name from members where members.id = group_members.member_id ) LIKE '%clark%' group by members_id
As you mentioned
WHERE members.name LIKE \'%clark%\'
you were selecting data from the members table whereas you have to select the data from group_members table.

The Best Way For Two Sequential SELECT Table

Hello I have two tables to send consecutive queries.
For example, table A yields 1,2,3 ..
Then, look for data in table B of query 1,2,3 ..
tableA
_____________________
| uid | rate |
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 4 |
tableB
_________________________
| rate | text |
| 1 | ONE |
| 2 | TWO |
| 3 | THREE |
| 4 | FOUR |
===
<?php
$sql = $con->query("SELECT * FROM tableA WHERE uid=1");
$user = $sql->fetch_array();
$ratings = $user['rate']; //1,2,3
$sql2 = $con->query("SELECT * FROM tableB WHERE rate IN('".$ratings."')");
$text = $sql2->fetch_array();
$results = $text['text']; //ONE, TWO, THREE
?>
How best to do that?
You can use this query:
Select tableA.*,tableB.*
from tableA
join tableB on tableA.rate=tableB.rate
where tableA.uid=1

for each value of one table get and display count number of coresponding values from another table

unfortunately i have to do this in mysql / php . I looked for three days, and there is like 10.000 explantions of this but NONE (and I repeat NONE) works for me. I tried it all. I have to ask, sorry.
I have two tables - articles and control.
table "articles"
------------------
art_id | name |
------------------
1 | aaa |
2 | bbb |
3 | ccc |
4 | ddd |
table "control"
--------------------------------------------
con_id | art_id | data |
--------------------------------------------
1 | 1 | something-a |
2 | 2 | something-b |
3 | 1 | something-a |
4 | 2 | something-c |
5 | 3 | something-f |
art_id exists in both tables. Now what i wanted - for query:
"select * from articles order by art_id ASC" displayed in a table
to have also one cell displaying the count for each of art_id's from table CONTROL...
and so i tried join, left join, inner join - i get errors ... I also tried for each get only one result (for example 2 for everything)... this is semi-right but it displays the array of correct results and it's not even with join!!! :
$query = "SELECT art_id, count(*) as counting
FROM control GROUP BY art_id ORDER BY con_id ASC";
$result = mysql_query($query);
while($row=mysql_fetch_array($result)) {
echo $row['counting'];
}
this displays 221 -
-------------------------------------------------
art_id | name | count (this one from control) |
-------------------------------------------------
1 | aaa | 221 |
2 | bbb | 221 |
3 | ccc | 221 |
and it should be:
for art_id(value1)=2,
for art_id(2)=2,
for art_id(3)=1
it should be simple - like a count of values from CONTROL table displayed in query regarding the "articles" table...
The result query on page for table articles should be:
"select * from articles order by art_id ASC"
-------------------------------------------------
art_id | name | count (this one from control) |
-------------------------------------------------
1 | aaa | 2 |
2 | bbb | 2 |
3 | ccc | 1 |
So maybe i should go with JOIN or with join plus for each... Tried tha too, but then i'm not sure what is the proper thing to echo... all-in-all i'm completely lost here. Please help. Thank you.
So imagine this in two steps:
Get the counts per art_id from the control table
Using your articles table, pick up the counts from step 1
That will give you a query that looks like this:
SELECT a.art_id, a.name, b.control_count
FROM articles a
INNER JOIN
(
SELECT art_id, COUNT(*) AS control_count
FROM control
GROUP BY art_id
) b
ON a.art_id = b.art_id;
Which will give you the results you're looking for.
However, instead of using a subquery, you can do it all in one shot:
SELECT a.art_id, a.name, COUNT(b.art_id) AS control_count
FROM articles a
INNER JOIN control b
ON a.art_id = b.art_id
GROUP BY a.art_id, a.name;
SQL Fiddle demo
SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id DESC;
If I understood your question right, this query should do the trick.
Edit: Created the tables you have described, and it works.
SELECT * FROM articles;
+--------+------+
| art_id | name |
+--------+------+
| 1 | aaa |
| 2 | bbb |
| 3 | ccc |
| 4 | ddd |
+--------+------+
4 rows in set (0.00 sec)
SELECT * FROM control;
+--------+--------+------+
| con_id | art_id | data |
+--------+--------+------+
| 1 | 1 | NULL |
| 2 | 2 | NULL |
| 3 | 1 | NULL |
| 4 | 2 | NULL |
| 5 | 3 | NULL |
+--------+--------+------+
5 rows in set (0.00 sec)
SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC;
+--------+------+----------------+
| art_id | name | count_from_con |
+--------+------+----------------+
| 1 | aaa | 2 |
| 2 | bbb | 2 |
| 3 | ccc | 1 |
| 4 | ddd | 0 |
+--------+------+----------------+
You haven't quite explained what you want to accomplish with the print out but here is an example in PHP: (Use PDO instead of mysql_)
$pdo = new PDO(); // Make your connection here
$stm = $pdo->query('SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC');
while( $row = $stm->fetch(PDO::FETCH_ASSOC) )
{
echo "Article with id: ".$row['art_id']. " has " .$row['count_from_con'].' connected rows in control.';
}
Alternatively with the mysql_ extension:
$result = mysql_query('SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC');
while( $row = mysql_fetch_assoc($result) )
{
echo "Article with id: ".$row['art_id']. " has " .$row['count_from_con'].' connected rows in control.';
}
This should be enough examples to help you accomplish what you need.

mysql fetch data in where condition

I have 3 table now:
First is : member_username
+-------------+------------------+
| uid | username |
+-------------+------------------+
| 1 | theone |
| 2 | ohno |
| 3 | prayforpr |
+-------------+------------------+
Second is : member_data
+-------------+-------------------+-----------------+
| uid | talk | etc |
+-------------+-------------------+-----------------+
| 1 | talk1 | |
| 2 | talkeee | |
| 3 | iojdfnl | |
+---------------------------------------------------+
Third is : member_level
+-------------+-------------------+-----------------+
| uid | level | fid |
+-------------+-------------------+-----------------+
| 1 | 2 | 1 |
| 1 | 10 | 2 |
| 2 | 1 | 1 |
| 2 | 99 | 2 |
| 1 | 40 | 3 |
| 3 | 50 | 1 |
| 1 | 44 | 4 |
+---------------------------------------------------+
I would like to query data and display the only one uid when member_level is higher in when SUM member_level.level Where fid in 1,2,3.
my query now is like below, but this query is sum all the level including fid 4 also, how to specify only sum in fid 1,2,3? and how do I assign the SUM of member_level.level Where fid in 1,2,3 to $levelKingTotalLevel?
$levelKing = DB::query("SELECT t1.uid,t1.username,t2.talk FROM ".DB::table('member_level')." t3 JOIN ".DB::table('member_username')." t1 ON(t3.uid = t1.uid) JOIN ".DB::table('member_data')." t2 ON (t1.uid = t2.uid) GROUP BY t3.uid ORDER BY SUM(t3.level) DESC LIMIT 1");
while($rowlevelKing = DB::fetch($levelKing)) {
$levelKingTotalLevel = $rowlevelKing['???'];
$levelKingN = $rowlevelKing['username'];
$levelKingUID = $rowlevelKing['uid'];
$levelKingT = $rowlevelKing['talk'];
};
echo "The ".$levelKingN." total level is ".$levelKingTotalLevel." and he talk about ".$levelKingT;
Thank you.
To filter records having fid values as 1, 2 or 3, use IN statement in WHERE clause. Alias totalLevel in select statement will give you total level for a user.
SELECT t1.uid, t1.username, t2.talk, SUM(t3.level) AS totalLevel
FROM member_level t3
JOIN member_username t1
ON (t3.uid = t1.uid)
JOIN member_data t2
ON (t1.uid = t2.uid)
WHERE t3.fid IN (1,2,3)
GROUP BY t3.uid
ORDER BY totalLevel DESC
LIMIT 1

how use order by clause in group by statement

I have two table tbl_issue_log, tbl_magazine_issue
tbl_issue_log
============
+----------+--------+--------+-----------+---------------------+
| issue_id | mag_id | log_id | operation | updated_time |
+----------+--------+--------+-----------+---------------------+
| 2 | 1 | 1 | 1 | 2014-01-30 21:29:44 |
| 3 | 4 | 1 | 1 | 2015-01-30 21:29:44 |
| 2 | 1 | 1 | 3 | 2015-01-31 21:29:44 |
+----------+--------+--------+-----------+---------------------+
tbl_magazine_issue
=================
+----------+-------------+-------------+------------------+------------+------------+-------------------+---------------+
| ISSUE_ID | ISSUE_NAME | MAGAZINE_ID | COVER_PAGE_THUMB | FROM_DATE | TO_DATE | issue_description | login_page_no |
+----------+-------------+-------------+------------------+------------+------------+-------------------+---------------+
| 2 | test issue | 1 | cover page | 2014-01-30 | 2015-01-30 | sdssdg fsdf | 20 |
| 3 | test issue1 | 4 | cover page1 | 2014-01-30 | 2015-01-30 | sdssdg fsdf | 20 |
+----------+-------------+-------------+------------------+------------+------------+-------------------+---------------+
in tbl_issue_log contain multiple records for same issue id. i want only one issue at a time
and this must latest updated time.
My query is this
SELECT
`tbl_issue_log`.`operation`,
`tbl_magazine_issue`.`ISSUE_ID`,
`tbl_magazine_issue`.`ISSUE_NAME`,
`tbl_magazine_issue`.`MAGAZINE_ID`,
`tbl_magazine_issue`.`COVER_PAGE_THUMB`,
`tbl_magazine_issue`.`FROM_DATE`,
`tbl_magazine_issue`.`TO_DATE`,
`tbl_magazine_issue`.`issue_description`,
`tbl_magazine_issue`.`login_page_no`
FROM
`tbl_issue_log`
LEFT JOIN
`tbl_magazine_issue` ON tbl_magazine_issue.ISSUE_ID = tbl_issue_log.issue_id
WHERE
(tbl_issue_log.mag_id = '1')
AND (tbl_magazine_issue.ISSUE_STATUS = 3)
AND (tbl_issue_log.updated_time > '2014-02-25 00:42:22')
GROUP BY tbl_issue_log.issue_id
ORDER BY tbl_issue_log updated_time DESC;
Here i got issue id based output . But not getting the latest updated timeed record.
If any one about this please help me.
Try this
SELECT * FROM
(SELECT
`tbl_issue_log`.`operation`,
`tbl_magazine_issue`.`ISSUE_ID`,
`tbl_magazine_issue`.`ISSUE_NAME`,
`tbl_magazine_issue`.`MAGAZINE_ID`,
`tbl_magazine_issue`.`COVER_PAGE_THUMB`,
`tbl_magazine_issue`.`FROM_DATE`,
`tbl_magazine_issue`.`TO_DATE`,
`tbl_magazine_issue`.`issue_description`,
`tbl_magazine_issue`.`login_page_no`
FROM
`tbl_issue_log`
LEFT JOIN
`tbl_magazine_issue` ON tbl_magazine_issue.ISSUE_ID = tbl_issue_log.issue_id
WHERE
(tbl_issue_log.mag_id = '1')
AND (tbl_magazine_issue.ISSUE_STATUS = 3)
AND (tbl_issue_log.updated_time > '2014-02-25 00:42:22')
ORDER BY tbl_issue_log.updated_time DESC ) TEMP_TABLE
GROUP BY ISSUE_ID
Can you try changing order by clause as
ORDER BY tbl_issue_log.updated_time DESC;
Edit ---
As you are grouping on issue_id, mysql will select first row that matches the issue_id. The order by runs later which essentially does not return what you are looking for. You may need to use a subquery approach for this.
select some_table.* FROM
(
SELECT
MAX(tbl_issue_log.updated_time) AS updated_time,
`tbl_issue_log`.`operation`,
`tbl_magazine_issue`.`ISSUE_ID`,
`tbl_magazine_issue`.`ISSUE_NAME`,
`tbl_magazine_issue`.`MAGAZINE_ID`,
`tbl_magazine_issue`.`COVER_PAGE_THUMB`,
`tbl_magazine_issue`.`FROM_DATE`,
`tbl_magazine_issue`.`TO_DATE`,
`tbl_magazine_issue`.`issue_description`,
`tbl_magazine_issue`.`login_page_no`
FROM
`tbl_issue_log`
LEFT JOIN
`tbl_magazine_issue` ON tbl_magazine_issue.ISSUE_ID = tbl_issue_log.issue_id
WHERE
(tbl_issue_log.mag_id = '1')
AND (tbl_magazine_issue.ISSUE_STATUS = 3)
AND (tbl_issue_log.updated_time > '2014-02-25 00:42:22')
GROUP BY tbl_issue_log.issue_id
) some_table
ORDER BY some_table.updated_time DESC;

Categories