How to use if condition in echo - php

I have a form to add product to cart and inside it there is a link.
This is link
<?php
echo $this->Html->link('<div class="single-products">'.'<div class="productinfo text-center myimg">'.$this->Html->image("product/".$row["Product"]["photo"],array(/*"width"=>"2500px",*/"height"=>"250px")).'<h2> &#8377 '.$row["Product"]["price"].'</h2>'.'<p>'.$row["Product"]["name"]."</p><a href='javascript:document.ff".($i++).".submit()' class='btn btn-default add-to-cart'><i class='fa fa-shopping-cart'></i>Add to cart</a>".'</div>'.'</div>',
array
(
'controller'=>'Public',
'action'=>'singleproduct?id='.$row["Product"]["id"],
),
array
(
'escape'=>false //NOTICE THIS
)
);
?>
And I want to use this code just above Add to cart button
<?php
if($row["Product"]["psize"]==1)
{
?>
Size<select name="psize">
<option value="S">S</option>
<option value="M">M</option>
<option value="L">L</option>
<option value="XL">XL</option>
</select>
<?php
}
elseif($row["Product"]["psize"]==2)
{
?>
Size<select name="psize">
<option value="28">28</option>
<option value="30">30</option>
<option value="32">32</option>
<option value="34">34</option>
</select>
<?php
}
?>
This code is working if I put it outside of this HTML helper link, but because of design problem and I want to display it just above the add to cart button
I have tried but couldn't figure out how to put this inside link.


<?php
if($row["Product"]["psize"]==1)
{
?>
Size<select name="psize">
<option value="S">S</option>
<option value="M">M</option>
<option value="L">L</option>
<option value="XL">XL</option>
</select>
<?php
} else{
if($row["Product"]["psize"]==2){
?>
Size<select name="psize">
<option value="28">28</option>
<option value="30">30</option>
<option value="32">32</option>
<option value="34">34</option>
</select>
<?php
} else{
echo "TEY IT"
}
}
?>
May Be it gone help.


Bring out your codes in the function $this->Html->link(), assign it to a variable and use if condition. And i think you should use CakePHP Form Helper to output select box.
Example:
<?php
$select = $this->Form->input('psize', array(type => 'select', 'options' => $sizeOptions)); // you can use if conditions here
$link = $this->Html->link('<div>...</div>' . $select . '<div>...</div>', $yourUrlArr);
echo $link;

Related

How to set Dropdown List default value based on user selection

I have a dropdown list. However i want to set a default based on user selection. Therefore the default value is not consistent. What can i do to achieve this? I have set $country = $_POST['country']; as user selection.
<td>Country:</td>
<td colspan="2"><select name="country">
<option value="93">93-Afghanistan</option>
<option value="355">355-Albania</option>
<option value="213">213-Algeria</option>
<option value="1-684">1-684-American Samoa</option>
<option value="376">376-Andorra</option>
<option value="244">244-Angola</option>
<option value="1-264">1-264-Anguilla</option>
<option value="672">672-Antarctica</option>
<option value="1-268">1-268-Antigua and Barbuda</option>
<option value="54">54-Argentina</option>
<option value="374">374-Armenia</option>
<option value="297">297-Aruba</option>
<option value="61">61-Australia</option>
</select>
To add on. There are 200 over options (I never list all down) so i hope to get a convenience way to achieve this

You can use 'selected' for relevant option
<option value="93" <?php if($country==93) echo "selected" ?> >93-Afghanistan</option>
<option value="355" <?php if($country==355) echo "selected" ?> >355-Albania</option>
like this add if conditon for each option.

Try using session for it.
The php code:
session_start();
$_SESSION['selectedCountry'] = $_POST['country'];
Then you can use JQuery to make dropdown selected:
$(document).ready(function(){
$(function() {
$("#country").val("<?php echo $_SESSION['selectedCountry'];?>");
});
})

Please try out this ..
HTML :-
<td>Country:</td>
<td colspan="2"><select id="country" name="country">
<option value="93">93-Afghanistan</option>
<option value="355">355-Albania</option>
<option value="213">213-Algeria</option>
<option value="1-684">1-684-American Samoa</option>
<option value="376">376-Andorra</option>
<option value="244">244-Angola</option>
<option value="1-264">1-264-Anguilla</option>
<option value="672">672-Antarctica</option>
<option value="1-268">1-268-Antigua and Barbuda</option>
<option value="54">54-Argentina</option>
<option value="374">374-Armenia</option>
<option value="297">297-Aruba</option>
<option value="61">61-Australia</option>
</select>
</td>
JQuery :-
$(document).ready(function(){
$(function() {
$("#country").val("<?php echo $_POST['country'];?>");
});
})

Try this...
<?php
(isset($_POST["country"])) ? $country = $_POST["country"] : $country=93;
?>
<form action='stackover.php' method='POST'>
<select id="country" name="country">
<option <?php if ($country == 93 ) echo 'selected' ; ?> value="93">93-Afghanistan</option>
<option <?php if ($country == 355 ) echo 'selected' ; ?> value="355">355-Albania</option>
<option <?php if ($country == 213 ) echo 'selected' ; ?> value="213">213-Algeria</option>
</select>
<input type="submit" value="Submit">
</form>

Error setting the selected value from a select list

I have a HTML select list where one can chose an option.
<select name='price' id='price'>
<option value='' >Select....</option>
<option value='0-50,000' selected>0-50,000</option>
<option value='50,000-100,000'>50,000-100,000</option>
<option value='100,000-150,000'>100,000-150,000</option>
<option value='150,000-200,000'>150,000-200,000</option>
<option value='200,000 and above'>200,000 and above</option>
<option value='see all'>See All</option>
</select>
When this list is submitted via a HTML submit button, this list shows again in another page. Now, I want the option the user selected to be new selected value. I am doing this:
<select name='price' id='price'>
<option value='{$_POST['price']}'>{$_POST['price']}</option>
<option value='0-50,000'>0-50,000</option>
<option value='50,000-100,000'>50,000-100,000</option>
<option value='100,000-150,000'>100,000-150,000</option>
<option value='150,000-200,000'>150,000-200,000</option>
<option value='200,000 and above'>200,000 and above</option>
<option value='see all'>See All</option>
</select>
But values are appearing twice. The option the user selected is shown as the selected and still appears in the list. For example, we now have something like this:
0-50,000 (this is the selected value)
0-50,000
50,000-100,000
100,000-150,000
150,000-200,000
200,000 and above
How do I solve this?

In other page, make sure the selected option has selected="selected"
<select name='price' id='price'>\
<option value='' >Select....</option>
<option selected="selected" value='0-50,000'>0-50,000</option>
<option value='50,000-100,000'>50,000-100,000</option>
<option value='100,000-150,000'>100,000-150,000</option>
<option value='150,000-200,000'>150,000-200,000</option>
<option value='200,000 and above'>200,000 and above</option>
<option value='see all'>See All</option>
</select>

try this
/**
* Takes To values (First for option value Second for value to be compare)
* #param Srting $option stores Option Value String
* #param String $value Stores to be compare
* #return String
* #access public
*/
function selectBoxSelection($option, $value) {
if ($option == $value) {
return "selected";
}
}
<select name='price' id='price'>
<option value='0-50,000' <?php echo selectBoxSelection('0-50,000', $_POST['price']);?> >0-50,000</option>
<option value='50,000-100,000' <?php echo selectBoxSelection('50,000-100,000', $_POST['price']);?> >50,000-100,000</option>
<option value='100,000-150,000' <?php echo selectBoxSelection('100,000-150,000', $_POST['price']);?> >100,000-150,000</option>
<option value='150,000-200,000' <?php echo selectBoxSelection('150,000-200,000', $_POST['price']);?> >150,000-200,000</option>
<option value='200,000 and above' <?php echo selectBoxSelection('200,000 and above', $_POST['price']);?> >200,000 and above</option>
<option value='see all' <?php echo selectBoxSelection('see all', $_POST['price']);?> >See All</option>
</select>

instead of your code,
<select name='price' id='price'>
<option value='{$_POST['price']}'>{$_POST['price']}</option>
<option value='0-50,000'>0-50,000</option>
<option value='50,000-100,000'>50,000-100,000</option>
<option value='100,000-150,000'>100,000-150,000</option>
<option value='150,000-200,000'>150,000-200,000</option>
<option value='200,000 and above'>200,000 and above</option>
<option value='see all'>See All</option>
</select>
try like this,
<select name='price' id='price'>
<option value='' >Select....</option>
<?php foreach ($arr as $key=>$value)
{
if($key == $_POST['price'])
{
echo "<option selected value=$key>$value</option>";
unset($arr[$key]);
}
else
echo "<option value=$key>$value</option>";
}?>
</select>

This will do it :
<form name="myform" method="post" action="testsel.php">
<select name='price' id='price'>
<option value='' >Select....</option>
<option value='0-50,000' <?php if(isset($_POST["price"]) && $_POST["price"]=="0-50,000") print "selected"; ?>>0-50,000</option>
<option value='50,000-100,000' <?php if(isset($_POST["price"]) && $_POST["price"]=="50,000-100,000") print "selected"; ?>>50,000-100,000</option>
<option value='100,000-150,000' <?php if(isset($_POST["price"]) && $_POST["price"]=="100,000-150,000") print "selected"; ?>>100,000-150,000</option>
<option value='150,000-200,000' <?php if(isset($_POST["price"]) && $_POST["price"]=="150,000-200,000") print "selected"; ?>>150,000-200,000</option>
<option value='200,000 and above' <?php if(isset($_POST["price"]) && $_POST["price"]=="200,000 and above") print "selected"; ?>>200,000 and above</option>
<option value='see all' <?php if(isset($_POST["price"]) && $_POST["price"]=="see all") print "selected"; ?>>See All</option>
</select>
<input type="submit" value="submit">
</form>
<?php
if(isset($_POST["price"]))
print $_POST["price"];
?>
Save this file as "testsel.php" and view. It will serve the purpose.

<select name='price' id='price'>
<option value='' >Selec</option>
<option value='0-50,000'<?php if($_POST['price']=='0-50,000'){echo "selected==selected";}?>>0-50,000</option>
<option value='50,000-100,000'<?php if($_POST['price']=='50,000-100,000'){echo "selected==selected";}?>>50,000-100,000</option>
<option value='100,000-150,000'<?php if($_POST['price']=='100,000-150,000'){echo "selected==selected";}?>>100,000-150,000</option>
<option value='150,000-200,000'<?php if($_POST['price']=='150,000-200,000'){echo "selected==selected";}?>>150,000-200,000</option>
<option value='200,000 and above'<?php if($_POST['price']=='200,000 and above'){echo "selected==selected";}?>>200,000 and above</option>
<option value='see all'<?php if($_POST['price']=='see all'){echo "selected==selected";}?>>See All</option>
</select>

PHP/JQuery Dynamic Drop Down not sending variable via POST

I have a two step drop down menu. The second select is triggered with jquery. Since I have put this step in, my form does not pass the variable of the selected option. I expect it to just post but it doesn't. I have always had it loaded dynamically, so I didn't think that was the issue. I can't get it to work by passing it through the URL either.
Here is my code:
search.php
while($row = mysqli_fetch_array($result)) { ?>
<option value="<?=$row['id']?>"> <? echo $row['name'] ?></option>
<?php }
<form method = "post" action="index.php?page=users&id=<?php echo $row['id']; ?>">
<p>
<select name="list-select" id="list-select">
<option value="AL">Alabama</option>
<option value="AK">Alaska</option>
<option value="AZ">Arizona</option>
<option value="AR">Arkansas</option>
<option value="CA">California</option>
<option value="CO">Colorado</option>
<option value="CT">Connecticut</option>
<option value="DE">Delaware</option>
</select>
<?php
echo '<select name="list-target" id="list-target">';
echo '</select>';
$installation_id = $_POST['list-target'];
mysqli_close($con);
?>
users.php:
$installation_id = $_POST['list-target'];
.js
$(document).ready(function($) {
$("#list-select").change(function() {
$("#list-target").load("index.php?page=search&svalue=" + $("#list-select").val());
});
});
Thanks.

Removing duplicated options from select box in PHP

I want to generate select boxes based on the number of elements in the $chosen array and each of them will have the default selected options. The first one is A, and the second one is D. The following code is almost okay except I want to remove the duplicated options. Here's the output:
<select>
<option>Select</option>
<option value="A" selected="selected">A</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
<option value="E">E</option>
</select>
<select>
<option>Select</option>
<option value="D" selected="selected">D</option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
<option value="D">D</option>
<option value="E">E</option>
</select>
I tried array_merge with array_unique to merge $options and $chosen before foreach($options as $option) but it isn't working. Can anyone suggest a solution?
<?php
$options = array("A","B","C","D","E");
$chosens = array("A","D");
foreach($chosens as $chosen)
{
print "<select><option>Select</option>";
if(in_array($chosen,$options))
{
print "<option value='".$chosen."' selected='selected'>$chosen</option>";
}
/* $options = array_unique(array_merge($chosen,$options)); */
foreach($options as $option)
{
print "<option value='".$option."'>$option</option>";
}
print "</select>";
}
?>*

Actually, just a simple if condition is enough. Like this:
<?php
$options = array("A","B","C","D","E");
$chosens = array("A","D");
?>
<?php foreach($chosens as $chosen): ?>
<select name="">
<?php foreach($options as $option): ?>
<option value="<?php echo $option; ?>" <?php echo ($option == $chosen) ? 'selected' : ''; ?>><?php echo $option; ?></option>
<?php endforeach; ?>
</select><br/>
<?php endforeach; ?>

PHP: select form menu list error

Hi my select menu list is not working.
<?php
<tr>
<select name="package">
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="mercedes">Mercedes</option>
<option value="audi">Audi</option>
if(isset($_POST['package'])) echo "<option>" . $_POST['package'] . "</option>";
</tr>
?>
Help, would be appreciated.
Many thanks!

you have mixed php with html and also you didnt close SELECT tag.
try that:
<tr>
<select name="package">
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="mercedes">Mercedes</option>
<option value="audi">Audi</option>
<?php
if(isset($_POST['package'])){ echo "<option value='".$_POST['package'] ."'>" . $_POST['package'] . "</option>"};
?>
</select> <-----you missed this
</tr>
when using php and html you need either :
<?php echo "<select name='package'>
<option value='volvo'>Volvo</option>
....................................";
?>
or the code i provided above without before and after html code.

You can't use html inside php directory. If you want to use html mixed with php either do it using echo or outside <?php //inside ?> //outside. Here try this.
<tr>
<select name="package">
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="mercedes">Mercedes</option>
<option value="audi">Audi</option>
<?php
if(isset($_POST['package']))
echo "<option>" . $_POST['package'] . "</option>";
?>
</tr>

Categories