How to call function with input variables in PHP? - php

Question

there is two parameters to return Object as JSON
I try to get Posts By Id And attach to Array :
// Get Considered Posts, Training, Service, Intall
public function get_considered_posts() {
$item = new stdclass();
$item->msg = 'Empty';
$item->status = false;
$result = Array();
$post = $get_post_by_id( 156 ); // Training
if ( $post ) {
$result[] = $post ;
}
$post = $get_post_by_id( 164 ); // Service
if ( $post ) {
$result[] = $post ;
}
$post = $get_post_by_id( 161 ); // Intall
if ( $post ) {
$result[] = $post ;
}
if (count( $result ) == 0 ) {
$item->msg = 'Empty';
$item->status = false;
} else {
$item->msg = 'Success';
$item->status = true;
}
$item->result = $result;
return $item;
}
Here I want to use Only 5 Properties of Every Post :
// Get Post By Id
private function get_post_by_id( $pid ) {
$post = get_post( $pid = 0 );
if ( $post ) {
if ($post->post_status == 'publish') {
$object = new stdclass();
$object->id = $post->ID;
$object->cid = $pid;
$object->title = $post->post_title;
$object->content = $post->post_content;
$object->image = ''.wp_get_attachment_url( get_post_thumbnail_id($post->ID) );
return $object;
}
}
return $post;
}
But it shows 500 Internal Server Error
When I check error_log it show :
[17-May-2016 14:27:54 UTC] PHP Notice: Undefined variable: get_post_by_id in /home/codypars/public_html/app/wp-webservice/helper.php on line 62
[17-May-2016 14:27:54 UTC] PHP Fatal error: Function name must be a string in /home/codypars/public_html/app/wp-webservice/helper.php on line 62
How I can fix it ?
Solved: thank you CD-jS And JustOnUnderMillions. To call own functions inside PHP class the right syntax is :
this->myFunctionName( $Param1, $Param2, $Param3, ...);

Answer 1

Remove the $ from the front of your function names when you're calling them.
e.g.
$post = $get_post_by_id( 164 );
Should be
$post = get_post_by_id( 164 );