Unable to GET Data from mysql with AJAX call - php

Question

I'm having trouble trying to get data from a database. The code will only retrieve the first row of data from the Database. The data is correct but it does not matter what information I put into my html input field the data is the same in the new row that is added. Any help resolving this would be fantastic.
If someone was going to point out that I have both "POST" and "GET" mixed in my code, I could understand as that being a possible problem, but neither when matching would retrieve data from the DB, other than the first row of data in the table.
Any help with this would be great!!! Thanks to all who provide an answer in advance.
My HTML code:
index.php
<div class="row">
<div class="col-md-1"></div>
<div class="col-xs-3">
<h3 class="h4 text-center"><input type="text" name="barcode" id="barcode" size="90" class="col-md-9" value="" method="GET" placeholder="Barcode / Product Name"></h3>
</div>
</div>
<br />
<div class="row">
<div class="col-md-1"><p class=""></p></div>
<div class="col-md-6">
<table id="report" class="table table-bordered table-hover">
<thead>
<tr>
<td>SKU</td>
<td>Model</td>
<td>Item Description</td>
<td>Qty</td>
</tr>
</thead>
<tbody>
<?php get_item(); ?>
</tbody>
</table>
</div>
</div>
This is my AJAX script
<script>
var inp = $("#barcode");
// where #txt is the id of the textbox
$("#barcode").keyup(function (event) {
if (event.keyCode == 13)
{
if (inp.val().length > 0)
{
$.ajax({
url: "index.php",
type: "GET", //Also tried POST method. Didn't work either
data: {id: inp.val()},
success: function(response)
{
values = response.split(' - ');
$('#report tr:last').after(
"<tr class='table-row'>" +
"<td class=''>" + values[1] + "</td>" +
"<td class=''>" + values[2] + "</td>" +
"<td class=''>" + values[3] + "</td>" +
"<td class=''>" + values[4] + "</td></tr>");
}});
}
$('input[name=barcode]').val('');
}
});
</script>
Here is my php code
function get_item(){
global $con;
if(!empty($_POST))
{
$query = query("SELECT * FROM items");
confirm($query);
while($row = fetch_array($query)) {
$sku = $row['sku'];
$model = $row['category'];
$desc = $row['description'];
$qty = $row['qty'];
echo($id.' - '.$sku.' - '.$model.' - '.$desc.' - '.$qty);
die();
}
}
}

Answer 1

Move the die(); function call out of your while loop. It gets called rigth at the end of the first loop terminating your php script.