Jquery ajax json post to php variable - php

Question

I am looping through a mysql table and printing an HTML "Play" link for each row.
I'm trying to avoid refreshing the page on every click of the 'Play' link so I'm placing javascript in the link's 'href':
<a href='javascript:void(0)' onclick='playMV(\"".$rows["v_type"]."\",\"".$rows["v_id"]."\");'>Play</a>
The playMV() function will send necessary info to the server via jquery ajax post to get back out needed values. The php script on the server will use the values posted as values in a mysql query.
// javascript:
<script type="text/javascript">
function playMV(p1, p2) {
$.post("?opt=music", {
var1: p1,
var2: p2
}, function (data) {
//$('#result').html(p2);
});
}
</script>
// PHP:
$var1 = $_POST['var1'];
$var2 = $_POST['var2'];
$q = mysql_query("SELECT * FROM table WHERE v_lang='".$var1."' AND v_id='".$var2."'");
My question is: I don't know how to call both 'p1' and 'p2' values and assigned into php variable. the commented line $('#result').html(p2) was only output the values in a div block with id='result' but don't really can get it pass to php. I've been read through some answer regarding on json stuffs but end up can't even get what I want.
Please help as I've been stuck quite long in this part.
Thanks very much!!!
// whole code
<script type="text/javascript">
function playMV(p1, p2) {
$.post("<?php echo curPageURL() ?>", {
var1: p1,
var2: p2
}, function (data) {
//$('#result').html(p2);
//$('#result').html(data);
});
}
</script>
<?php
mysql_set_charset("utf8");
$var1 = $_POST['var1'];
$mvid = $_POST['var2'];
echo $var1.$var2;
//echo var_dump($_POST);
$count = 1;
if((strpos(curPageURL(),'mv')==false) || (strpos(curPageURL(),'type')==false)){
$type = ucwords("C");
$mvid = 1;
}
$mtv_data = array();
$mtvlist = mysql_query("SELECT * FROM ".$tb01." WHERE mtv_type='".$type."' ORDER BY mtv_order ASC LIMIT 0, 10") or die(mysql_error());
while($rows = mysql_fetch_array($mtvlist)){
$mtv_data[] = $rows;
}
$q = mysql_query("SELECT * FROM ".$tb01." WHERE mtv_id='".$mvid."'") or die(mysql_error());
$r = mysql_fetch_array($q);
?>
<span id="result"></span>
<div align="center" class="content-layer1" style="height:600px;padding-bottom:20px;">
<div class="content-layer2">
<div style="width:900px;text-align:left;padding:18px 18px 8px 18px;">
<h1>MUSIC ZONE</h1>
</div>
<div style="width:900px;text-align:left;padding:10px;">
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="55%">
<div id='mediaspace' align='center'>
<img src="images/ajax-loader.gif">
</div>
<div><?php echo $r["mtv_title"] ?><br /><?php echo $r["mtv_artist"] ?> </div>
</td>
<td width="45%" valign="top">
<div style="border:0px #000 solid;">
<table width='100%' border='1' cellspacing='2' cellpadding='2'>
<?php
foreach($mtv_data as $rows){
echo "<tr>
<td>".$count."</td>
<td><div>".$rows["mtv_title"]."</div><div>".$rows["mtv_artist"]."</div></td>
<td><a href='javascript:void(0)' onclick='playMV(\"".$rows["mtv_type"]."\",\"".$rows["mtv_id"]."\");' id='playmv'>Play</a>
</td>
</tr>";
$count += 1;
}
?>
</table>
</div>
</td>
</tr>
</table>
</div>
</div>
</div>

Answer 1

use json_decode()
$object = json_decode(json_string)