PHP mysqli while loop called twice - php

Question

I have this code:
$q = 'SELECT * FROM languages ORDER BY id DESC';
$r = mysqli_query($dbc, $q);
while($langs = mysqli_fetch_assoc($r)){
$l_id = $langs['id'];
$l_name = $langs['name_en'];
?>
<li <?php if($l_id == '1'){ echo 'class="active"'; }?>><?php echo $l_name;?></li>
<?php } // closing 1st while loop
?>
</ul>
<div class="tab-content">
<?php
$q = 'SELECT * FROM languages ORDER BY id DESC';
$r = mysqli_query($dbc, $q);
while($langs = mysqli_fetch_assoc($r)){
$l_id = $langs['id'];
$l_lang = $langs['language'];
$l_name = $langs['name_en'];
?>
<div class="tab-pane fade <?php if($l_id == '1'){ echo 'in active'; }?>" id="<?php echo $l_name;?>">
<div class="form-group col-xs-4">
<label for="title_<?php echo $l_lang;?>">Title:</label>
<input class="form-control" type="text" name="title_<?php echo $l_lang;?>" id="title_<?php echo $l_lang;?>" value="<?php echo $opened['title_'.$l_lang.'']; ?>" placeholder="Page Title">
</div>
<div class="form-group col-xs-4">
<label for="header_<?php echo $l_lang;?>">Header:</label>
<input class="form-control" type="text" name="header_<?php echo $l_lang;?>" id="header_<?php echo $l_lang;?>" value="<?php echo $opened['header_'.$l_lang.'']; ?>" placeholder="Page Header">
</div>
<div class="form-group col-xs-<?php if($page_type == 'tour'){ echo 8;}else {echo 12;} ?>">
<label for="body_<?php echo $l_lang;?>">Body:</label>
<textarea class="form-control editor" name="body_<?php echo $l_lang;?>" id="body_<?php echo $l_lang;?>" rows="7" placeholder="Page Body"><?php echo $opened['body_'.$l_lang.'']; ?></textarea>
</div>
</div>
<?php } //closing 2nd while loop
?>
</div>
When running it, the result is a tabbed form (I skipped the form tags and some html from above, to reduce the code writen) and everything is OK.
My questions are:
How to have the same output, but with a single query and while loop?
Is it possible to make this a function? Any hints?
Thank you!

Answer 1

I think you will have to loop twice, but you don't need to make two queries at all!
Use mysqli_fetch_all to store the results in an array and then loop through it
For example:
$q = 'SELECT * FROM languages ORDER BY id DESC';
$r = mysqli_query($dbc, $q);
$langs = mysqli_fetch_all($r);
foreach($langs as $lang){
//render links
}
//...
foreach($langs as $lang){
//render tabs
}
Your script will run much faster

Answer 2

Try
<?php
function get_rows()
{
$q = 'SELECT * FROM languages ORDER BY id DESC';
$r = mysqli_query($dbc, $q);
$languages = array();
while($langs = mysqli_fetch_assoc($r))
{
$languages[] = $langs;
}
return $languages;
}
$languages = get_rows();
if($languages != false)
{
?>
<ul>
<?php
foreach($languages as $langs)
{
$l_id = $langs['id'];
$l_name = $langs['name_en'];
?>
<li <?php
if($l_id == '1')
{
echo 'class="active"';
}
?>><?php echo $l_name; ?></li>
<?php
}
?>
</ul>
<div class="tab-content">
<?php
foreach($languages as $langs)
{
$l_id = $langs['id'];
$l_lang = $langs['language'];
$l_name = $langs['name_en'];
?>
<div class="tab-pane fade <?php
if($l_id == '1')
{
echo 'in active';
}
?>" id="<?php echo $l_name; ?>">
<div class="form-group col-xs-4">
<label for="title_<?php echo $l_lang; ?>">Title:</label>
<input class="form-control" type="text" name="title_<?php echo $l_lang; ?>" id="title_<?php echo $l_lang; ?>" value="<?php echo $opened['title_' . $l_lang . '']; ?>" placeholder="Page Title">
</div>
<div class="form-group col-xs-4">
<label for="header_<?php echo $l_lang; ?>">Header:</label>
<input class="form-control" type="text" name="header_<?php echo $l_lang; ?>" id="header_<?php echo $l_lang; ?>" value="<?php echo $opened['header_' . $l_lang . '']; ?>" placeholder="Page Header">
</div>
<div class="form-group col-xs-<?php
if($page_type == 'tour')
{
echo 8;
}
else
{
echo 12;
}
?>">
<label for="body_<?php echo $l_lang; ?>">Body:</label>
<textarea class="form-control editor" name="body_<?php echo $l_lang; ?>" id="body_<?php echo $l_lang; ?>" rows="7" placeholder="Page Body"><?php echo $opened['body_' . $l_lang . '']; ?></textarea>
</div>
</div>
<?php } ?>
</div>
<?php
}
?>

Answer 3

Save results while first iterating in some array and the iterate over this array for the second time:
$tmp_array = array();
while ($langs = mysqli_fetch_assoc($r)){
$tmp_array[] = $langs;
}
//some code here
//and second array
foreach ($tmp_array as $langs) {
//more code here
}