I have two different tables with different column name
Table 1 users
+-----+----------+---------+---------+------------+
| id | name | username| image | email |
+-----+----------+---------+---------+------------+
| 1 | John1 | exmple1 | img1 |a#gmail.com |
| 2 | John2 | exmple2 | img2 |b#gmail.com |
| 3 | John3 | exmple3 | img3 |c#gmail.com |
| 4 | John4 | exmple4 | img4 |d#gmail.com |
+-----+----------+---------+---------+------------+
Table 2nd Company
+-----+----------+------------+---------=------+-----------+
| id |company_name | username| description | founded |
+-----+-------------+---------+----------------+-----------|
| 1 | john1 | exmple1 |description1 | 2016 |
| 2 |CompanyName2 | exmple2 |description2 | 2016 |
| 3 |CompanyName3 | exmple3 |description3 | 2016 |
| 4 |CompanyName4 | exmple4 |description4 | 2016 |
+-----+-------------+---------+---------=------+-----------+
Now whenever a user type any input in search bar an ajax request is made to php file which checks for if that name of user exist in database or not
so for example if user type input john then a query should run which will check john in users table and company table & if there is a user name john & if there is a company named john it should fetch both the result.
how can i achieve this, i tried using UNION in my query but it said columns are different
Currently this is my query
$go = mysqli_query($connecDB, "SELECT name, img,username FROM users WHERE name LIKE '$q%' LIMIT 0,10");
Now people might be thinking what i really want!
i want a single query that will check for input in both table & fetch their details
You can use union
select id, name ,username, image, email, null, null
from users
where name LIKE concat('$q', '%')
union all
select id, company_name as name ,username, null, null, description, founded
from Company
where name LIKE concat('$q, '%')
order by name limit 10
Related
Is it possible to break a large MySQL table into smaller related tables?
for instance imagine the table:
x_data--
id | offer_price | offer_text | free_gift | free_gift_category | model_name | model_description | tariff_name | tariff_rental | tariff_minutes | tariff_texts | tariff_data | retailer_name | retailer_description
is it possible to split this out into separate tables and build relationships so the resulting tables look like:
offers--
id | offer_price | offer_text | free_gift_id | model_id | tariff_id | retailer_id
free_gifts--
id | free_gift | free_gift_category_id
free_gift_categories--
id | free_gift_category
models--
id | name | description
tariffs--
id | name | rental | minutes | texts | data
retailers--
id | name | description
i.e can I do an insert on a sub select or join?
something like:
$query = "INSERT INTO retailers (name,description)
(SELECT retailer_name, retailer_description FROM x_data) as retailer,
(SELECT MAX(id) as retailer_id FROM retailers) as retailer_id,
INSERT INTO tariffs (name, rental, minutes, texts, data) as tariffs, ...."
if this is possible how would I go about it?
Suppose I have a table named testdb which has the following values:
| Name | Phone |ID |
|------------------|------------|---|
| supriyo roy | 9038689236 | 2 |
| supriyo banerjee | 8013147879 | 3 |
| Alex ghosh | 8985855665 | 4 |
Now, I am performing a search by the name and the input given is just "supriyo" (no last name given).
The search result should show both the values:
| Name | Phone |ID |
|------------------|------------|---|
| supriyo roy | 9038689236 | 2 |
| supriyo banerjee | 8013147879 | 3 |
Is this possible to achieve using MySQL and php?
You are looking for LIKE:
select *
from your_table
where name like 'supriyo%';
Demo
Edit:
In php, use:
select *
from your_table
where name like '$name%';
I have two table 'users' and 'friends' I am having difficulty joining them
users table
id | name | usercode
--------------------
1 | david | 2WM
2 | Samme | E5N
3 | Awudu | C0Q
4 | John | VX6
5 | Jerem | FG3
Friends Table
id | actor | target
--------------------
1 | E5N | FG3
2 | 2WM | VX6
3 | FG3 | 2WM
4 | C0Q | VX6
5 | FG3 | VX6
Basically i want to select all users from USERS table who has 'FG3' in either target or actor column in the FRIENDS table.
The result will be
id | name | usercode | actor | target
--------------------------------------
2 | Samme | E5N | E5N | FG3
1 | david | 2WM | FG3 | 2WM
5 | John | VX6 | FG3 | VX6
I have triend everything i know but still i am not getting the correct results
I will be glad if anyone can help me since I need to present this work tomorrow morning. Thank you
Looks like you want to join on usercode equals actor or target, then put the 'FG3' part in a WHERE clause:
SELECT users.id, users.name, users.usercode, friends.actor, friends.target
FROM users
INNER JOIN friends
ON users.usercode = friends.actor OR users.usercode = friends.target
WHERE users.usercode != 'FG3'
AND (friends.actor = 'FG3' OR friends.target = 'FG3');
Using INNER JOIN limits your query to only records that exist in both tables.
I am creating a search portal in PHP from which user can search for a specific cuisine. In MySQL I have multiple tables for each cuisine and the respective hotel names that offer the cuisine. For example, in table
How can I query a specific cuisine table based on the cuisine search keyword?
So if a user enters 'mexican' as the search query, how can it connect to the 'Table2 - Mexican' and return the hotel names from this table?
Table1 - Chinese
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table2 - Mexican
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table3 - Pizza
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Your database concept is very unflexible. I think you should put the cuisines into your database as information (i.e. table content) instead of metadata describing single tables. Tables should generally considered to be static just like the code you write to access the database and its tables. If you implement the cuisines as different tables you would have to hardwire every cuisine into your code.
Here is a suggestion for a better approach:
Create a hotels table to store all the hotels,
Create a cuisines table to store all the different types of cuisines,
Make an additional table to establish the n:m relationship between the hotel and the cuisine.
Example:
hotels: id, name, address, city, telno, email
cuisine: id, name, description
rel: cuisine, hotel (where both are the foreign keys to the
id columns of the respective tables above)
See also:
How to handle a Many-to-Many relationship with PHP and MySQL.
MySQL: Many To Many Relationships ยป Return True
You might want to check this question to create a many-to-many relationship:
many-to-many and many-to-many intersections
I guess what you would like to achieve is something like this:
Table1 - Hotel
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table2 - Cuisine
____________________________________________
| id | cuisine_name | keywords |
|______|______________|____________________|
| 1 | Chinese | Shandong,Noodles,. |
| 2 | Mexican | Tacos,Beans,... |
| 3 | Itarian | Pizza,Pasta,.. |
|______|______________|____________________|
Table3 - HotelCuisine
___________________________________
| id | hotel_id | cuisine_id |
|______|____________|______________
| 1 | 1 | 2 |
| 2 | 1 | 3 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 3 |
|______|____________|_____________|
SQL:
SELECT hotelname, cuisine_name FROM Hotel
INNER JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id
INNER JOIN Cuisine ON Cuisine.id = HotelCuisine.cuisine_id
WHERE keywords like '%pizza%'
Result:
________________________________________
| hotelname | cuisine_name |
|_______________|______________________|
| hotel1 | Itarian |
| hotel3 | Itarian |
|_______________|______________________|
DEMO: http://sqlfiddle.com/#!2/961de/1
Hope this helps
you can check SQL UNION. But instead of having multiple tables with the same fields, you can try normalization to minimize the redundancy and to make queries easier.
Something like:
Hotel Table
-----------------------------
id | hotelname | categoryID
------------------------------
1 | hotel name 1 | 1
2 | hotel name 2 | 2
-----------------------------
Category Table
-------------------
id | categoryname
-------------------
1 | chinese
2 | mexican
------------------
And query as simple as:
SELECT a.hotelname, b,categoryname
FROM hotel_table a
LEFT JOIN category_table b
ON a.categoryID = b.id AND b.categoryname LIKE '%mexican%';
I have 3 table:
tblNames:
| id | firstname | lastname |
+------+---------------+--------------+
| 1 | John | Smith |
tblJosbs (this table accepts multiple checkbox value at the same time):
| id | jobs |
+------+-----------------------+
| 1 | Nurse |
+------+-----------------------+
| 2 | Call Center Agent |
+------+-----------------------+
| 3 | Police |
tblNamesJobs (this table is used to JOIN the other 2 tables):
| id | name_id | jobs_id |
+------+-------------+-------------+
| 1 | 1 | 1 |
+------+-------------+-------------+
| 2 | 1 | 2 |
+------+-------------+-------------+
| 3 | 1 | 3 |
All is fine but can someone show me the INSERT statement for the 3rd table I should use to when I will add new information?
For example add record that John Smith is a Call Center Agent
insert into tblNamesJobs (name_id,jobs_id )
values (
select id from tblNames where
firstname='John'
and lastname='Smith' limit 1
,
select id from tblJosbs where jobs='Call Center Agent' limit 1
);
If you are already depending on tauto increment..you can get the lastinserid, depending on your adapter.
eg. mysql_insert_id
for PDO we can use --PDO::lastInsertId.
so you will have id's of earlier inserted tables, that you can save in the new one.
INSERT INTO tblNamesJobs (name_id, jobs_id) VALUES (XXXX,YYYY)
That is assuming the table's id is auto-incrementing.
It should be noted that both the name_id and jobs_id columns in the "joiner" table should be foreign keys to the respective columns in the other table.
Edit - Valex's answer goes into more detail about what to do if you don't already have the id values.
If possible, I would recommend using some sort of framework that would handle the "joiner" table for you.