Suppose I have a table named testdb which has the following values:
| Name | Phone |ID |
|------------------|------------|---|
| supriyo roy | 9038689236 | 2 |
| supriyo banerjee | 8013147879 | 3 |
| Alex ghosh | 8985855665 | 4 |
Now, I am performing a search by the name and the input given is just "supriyo" (no last name given).
The search result should show both the values:
| Name | Phone |ID |
|------------------|------------|---|
| supriyo roy | 9038689236 | 2 |
| supriyo banerjee | 8013147879 | 3 |
Is this possible to achieve using MySQL and php?
You are looking for LIKE:
select *
from your_table
where name like 'supriyo%';
Demo
Edit:
In php, use:
select *
from your_table
where name like '$name%';
Related
I have a table like this in my database.
| id | yes_answer | no_answer |
| a01 | a05 | a04 |
| a03 | a16 | a32 |
| a04 | c01 | a05 |
| a05 | a06 | c06 |
| a06 | a08 | a09 |
| a08 | c03 | a09 |
| a09 | a03 | |
| a16 | a33 | a02 |
| a32 | c04 | a16 |
| a33 | c05 | |
As An Explanation :
1.id column represent an id of question. it is linked to another table on my database.
2.yes_answer column represent the next question (like a01) or conclusion (like c04) you get when you answer the question represented by id column with yes or TRUE or 1 value.
3.no_answer is generally the same as yes_answer column except that you get it when you answer question represented by id column with no, FALSE, 0 value.
4. Every id, yes_answer, no_answer is connected each other. The Result is A Pattern. When you Want to find a path that lead to answer c01 it will be like c05 -> a33,a16,a32,a03,a09,a06,a05,a01.
And Here I am Trying To Bactrack The Pattern From answer column that marked with c like c01 or c02 like above. And I've been able to bactrack only the beginning value of it Like (c05 -> a33) and the rest is blank.
Here is My Code
$sqlQueryYes="SELECT * FROM tbl_path_inference WHERE yes_answer='c05'";
$execQueryYes=mysql_query($sqlQueryYes);<br />
$queryStatus=mysql_num_rows($execQueyYes); //Getting Query Status<br />
if($queryStatus == 1) {
$getDataYes=mysql_fetch_array($execQueryYes);
$ansPath=$ansPath." ".$getDataYes['id'];
} else { // if cant find answer on column yes_answer try on no_answer
$sqlQueryNo="SELECT * FROM tbl_path_inference WHERE no_answer='c05'";
$execQueryNo=mysql_query($sqlQueryNo);
$getDataNo=mysql_fetch_array($execQueryNo);
$ansPath=$ansPath." ".$getDataNo;
}
Anyone Have Solution On It. Im Still working It Now.
I have two different tables with different column name
Table 1 users
+-----+----------+---------+---------+------------+
| id | name | username| image | email |
+-----+----------+---------+---------+------------+
| 1 | John1 | exmple1 | img1 |a#gmail.com |
| 2 | John2 | exmple2 | img2 |b#gmail.com |
| 3 | John3 | exmple3 | img3 |c#gmail.com |
| 4 | John4 | exmple4 | img4 |d#gmail.com |
+-----+----------+---------+---------+------------+
Table 2nd Company
+-----+----------+------------+---------=------+-----------+
| id |company_name | username| description | founded |
+-----+-------------+---------+----------------+-----------|
| 1 | john1 | exmple1 |description1 | 2016 |
| 2 |CompanyName2 | exmple2 |description2 | 2016 |
| 3 |CompanyName3 | exmple3 |description3 | 2016 |
| 4 |CompanyName4 | exmple4 |description4 | 2016 |
+-----+-------------+---------+---------=------+-----------+
Now whenever a user type any input in search bar an ajax request is made to php file which checks for if that name of user exist in database or not
so for example if user type input john then a query should run which will check john in users table and company table & if there is a user name john & if there is a company named john it should fetch both the result.
how can i achieve this, i tried using UNION in my query but it said columns are different
Currently this is my query
$go = mysqli_query($connecDB, "SELECT name, img,username FROM users WHERE name LIKE '$q%' LIMIT 0,10");
Now people might be thinking what i really want!
i want a single query that will check for input in both table & fetch their details
You can use union
select id, name ,username, image, email, null, null
from users
where name LIKE concat('$q', '%')
union all
select id, company_name as name ,username, null, null, description, founded
from Company
where name LIKE concat('$q, '%')
order by name limit 10
i have two tables and column name are as :
Table 1
user | food | color | bike | car
Table 2
user | mobile | laptop
Now i want to get result by select single or multiple value.
For example, if i want select user which have bike and laptop . then i can get result it by query but for this all fields i have to use many condition . i have used if else where. and i also want to refine select with current selection . so what should i use ? Please help my previous question was same but i did not asked perfectly. so asked again. Thank You.
You can use multiple tables in your single SQL query. The act of joining in MySQL refers to smashing two or more tables into a single table.
You can use JOINS in SELECT, UPDATE and DELETE statements to join MySQL tables.
Example
+-----------------+----------------+
| tutorial_author | tutorial_count |
+-----------------+----------------+
| mahran | 20 |
| mahnaz | NULL |
| Jen | NULL |
| Gill | 20 |
| John Poul | 1 |
| Sanjay | 1 |
+-----------------+----------------+
SELECT * from tutorials_tbl;
+-------------+----------------+-----------------+-----------------+
| tutorial_id | tutorial_title | tutorial_author | submission_date |
+-------------+----------------+-----------------+-----------------+
| 1 | Learn PHP | John Poul | 2007-05-24 |
| 2 | Learn MySQL | Abdul S | 2007-05-24 |
| 3 | JAVA Tutorial | Sanjay | 2007-05-06 |
+-------------+----------------+-----------------+-----------------+
SELECT a.tutorial_id, a.tutorial_author, b.tutorial_count
-> FROM tutorials_tbl a, tcount_tbl b
-> WHERE a.tutorial_author = b.tutorial_author;
+-------------+-----------------+----------------+
| tutorial_id | tutorial_author | tutorial_count |
+-------------+-----------------+----------------+
| 1 | John Poul | 1 |
| 3 | Sanjay | 1 |
+-------------+-----------------+----------------+
http://www.tutorialspoint.com/mysql/mysql-using-joins.htm
I have 2 tables, the 'department' and 'document'.
Table department
| doc_id | dept_name |
----------------------------------
| 1 | Information Technology|
| 2 | Software Development |
| 3 | Human Resource |
| 4 | Accounting |
| 5 | Support |
Table document
| doc_id | doc_name | author | description | department |
----------------------------------------------------------------------------
| 1 | Maps | User1 | sample | Information Technology |
| 2 | Audits | User3 | sample | Software Development |
| 3 | Image | User1 | sample | Information Technology |
| 4 | Papers | User4 | sample | Human Resource |
| 5 | Print Screen| User1 | sample | Software Development |
| 6 | Transaction | User3 | sample | Accounting |
| 7 | Graph | User1 | sample | Support |
| 8 | Excel | User1 | sample | Information Technology |
Now, I want to display the table with two columns: department and total_doc.
Output:
| department |total_doc|
-----------------------------------
| Information Technology| 3 |
| Software Development | 2 |
| Human Resource | 1 |
| Accounting | 1 |
| Support | 1 |
I want to display the total document inside the department and arrange them in ascending order.
Here's my query.(not sure)
SELECT department, count(doc_name) as 'total_doc' FROM tbl_document GROUP BY doc_name
I'm using MVC pattern in Codeigniter.
$this->db->select("department, count(doc_name) as 'total_doc'");
$this->db->from('document');
$this->db->group_by('doc_name');
Also, How can I display this in table? like using foreach in html?
You need to do group by with department not with doc_name.
$this->db->select("department, count(doc_name) as 'total_doc'");
$this->db->from('document');
$this->db->group_by('department');
$result = $this->db->get()->result();
Hope This will help you.
foreach ($result as $row)
{
echo $row->department."----".$row->total_doc;
}
here you go
SELECT dept_name,COUNT(td.department) FROM department d
LEFT JOIN tdocument td ON td.`department`=d.`dept_name`
GROUP BY td.`department` ORDER BY COUNT(td.`department`) DESC;
You want one line per department. IN SQL words: You want to group by department.
select department, count(*) as total_doc from document group by department;
(BTW: don't use single quotes for column aliases.)
I am creating a search portal in PHP from which user can search for a specific cuisine. In MySQL I have multiple tables for each cuisine and the respective hotel names that offer the cuisine. For example, in table
How can I query a specific cuisine table based on the cuisine search keyword?
So if a user enters 'mexican' as the search query, how can it connect to the 'Table2 - Mexican' and return the hotel names from this table?
Table1 - Chinese
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table2 - Mexican
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table3 - Pizza
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Your database concept is very unflexible. I think you should put the cuisines into your database as information (i.e. table content) instead of metadata describing single tables. Tables should generally considered to be static just like the code you write to access the database and its tables. If you implement the cuisines as different tables you would have to hardwire every cuisine into your code.
Here is a suggestion for a better approach:
Create a hotels table to store all the hotels,
Create a cuisines table to store all the different types of cuisines,
Make an additional table to establish the n:m relationship between the hotel and the cuisine.
Example:
hotels: id, name, address, city, telno, email
cuisine: id, name, description
rel: cuisine, hotel (where both are the foreign keys to the
id columns of the respective tables above)
See also:
How to handle a Many-to-Many relationship with PHP and MySQL.
MySQL: Many To Many Relationships ยป Return True
You might want to check this question to create a many-to-many relationship:
many-to-many and many-to-many intersections
I guess what you would like to achieve is something like this:
Table1 - Hotel
_______________________
| id | hotelname |
|______|______________|
| 1 | hotel1 |
| 2 | hotel2 |
| 3 | hotel3 |
| 4 | hotel4 |
| 5 | hotel5 |
|______|______________|
Table2 - Cuisine
____________________________________________
| id | cuisine_name | keywords |
|______|______________|____________________|
| 1 | Chinese | Shandong,Noodles,. |
| 2 | Mexican | Tacos,Beans,... |
| 3 | Itarian | Pizza,Pasta,.. |
|______|______________|____________________|
Table3 - HotelCuisine
___________________________________
| id | hotel_id | cuisine_id |
|______|____________|______________
| 1 | 1 | 2 |
| 2 | 1 | 3 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 3 |
|______|____________|_____________|
SQL:
SELECT hotelname, cuisine_name FROM Hotel
INNER JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id
INNER JOIN Cuisine ON Cuisine.id = HotelCuisine.cuisine_id
WHERE keywords like '%pizza%'
Result:
________________________________________
| hotelname | cuisine_name |
|_______________|______________________|
| hotel1 | Itarian |
| hotel3 | Itarian |
|_______________|______________________|
DEMO: http://sqlfiddle.com/#!2/961de/1
Hope this helps
you can check SQL UNION. But instead of having multiple tables with the same fields, you can try normalization to minimize the redundancy and to make queries easier.
Something like:
Hotel Table
-----------------------------
id | hotelname | categoryID
------------------------------
1 | hotel name 1 | 1
2 | hotel name 2 | 2
-----------------------------
Category Table
-------------------
id | categoryname
-------------------
1 | chinese
2 | mexican
------------------
And query as simple as:
SELECT a.hotelname, b,categoryname
FROM hotel_table a
LEFT JOIN category_table b
ON a.categoryID = b.id AND b.categoryname LIKE '%mexican%';