php/ajax vote up down - php

Question

and sry in advance because i'm new here and i'm completly new in php/ajax coding.
I use a free script (Ajax vote up/down) from this site
I have a simple php page for my shoutcast server to show the song played
<?php
require_once "inc.php";
$array = array(); // Let's store our shoutcast variables into an array.
$array['host'] = "xxx.xxx.xx.xxx"; // Your Shoutcast Host
$array['port'] = "xxxx"; // Your Shoutcast Port
$array['extra'] = "/admin.cgi?sid=1&mode=viewxml&page=1"; // The bit that follows in the url to access the xml of the stats
$array['user'] = "xxxxx"; // Admin username (Default is usually "admin")
$array['password'] = "xxxxxxx"; // Admin Password
$radioStats = new radioStats( $array['host'], $array['port'], $array['extra'], $array['user'], $array['password']);
$returnStats = $radioStats->returnStats();
$song = $returnStats['currentSong'];
?>
<div align="center">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js">
</script>
<link href="votingfiles/voting.css" rel="stylesheet" type="text/css" />
<script src="votingfiles/voting.js" type="text/javascript"></script>
<script>
$(document).ready(function(){
setInterval(function(){cache_clear()},54000);
});
function cache_clear()
{
window.location.reload(true);
}
</script>
<div id="radio_stats">
<?php
if( $returnStats['serverStatus'] != 0 ) {
?>
<?php
if( $returnStats['currentSong'] != "" ) {
echo $returnStats['currentSong'];
} else {
echo "Undefined";
}
?></div>
<br /><br />
<div class="vot_updown1" id="vt_$song"></div>
<?php
}
else {
?>
This radio server appears to be offline.
<?php
}
?>
My problem is :
All request Php/ajax/mysql works but actually when i make a vote, it's registered in the db like :
vt_$song 1 0
How can i do to get the real name of the song like the original php request do :
echo $returnStats['currentSong']; or echo $song;
To register in the db like :
vt_Kidd Guti-Step Everything 1 0 (or any other song played)
Example : [HERE]
Thanks in advance for any help.

Answer 1

In this line the $song is not parsed as PHP so the literal text $song is showing:
<div class="vot_updown1" id="vt_$song"></div>
Try:
<div class="vot_updown1" id="vt_<?php echo $song; ?>"></div>