Instagram Fetch Amount of Images API - php

A friend of mine wrote this script, displaying the 20 most recent instagram images, and I was wondering, how can I change the amount of images it grabs to maybe, 6?
<?PHP
$token = 'token';
$username = 'username';
$userInfo = json_decode(file_get_contents('https://api.instagram.com/v1/users/search?q='.$username.'&access_token='.$token));
if($userInfo->meta->code==200){
$photoData = json_decode(file_get_contents('https://api.instagram.com/v1/users/'.$userInfo->data[0]->id.'/media/recent/?access_token='.$token));
if($photoData->meta->code==200){ ?>
<?PHP foreach($photoData->data as $img){
echo '<img src="'.$img->images->thumbnail->url.'">';
} ?>
<?PHP } // If
} // If
?>
Now, the script is functional now because I've been working on it all day, but I'm not sure how to change how many it sends out.
Also, would any of you know how to style this? I already have the CSS done for it, but whenever I try it, it doesn't work correctly.
And, would you know how to get the description of the photo using the API?
Thank you in advance :-)

You need to use Instagram's count= url parameter when requesting data from their endpoints.
For example: https://api.instagram.com/v1/users/search?count=6
Or in your code:
<?PHP
$token = 'token';
$username = 'username';
$userInfo = json_decode(file_get_contents('https://api.instagram.com/v1/users/search?count=6&q='.$username.'&access_token='.$token));
if($userInfo->meta->code==200){
$photoData = json_decode(file_get_contents('https://api.instagram.com/v1/users/'.$userInfo->data[0]->id.'/media/recent/?count=6&access_token='.$token));
if($photoData->meta->code==200){ ?>
<?PHP foreach($photoData->data as $img){
echo '<img src="'.$img->images->thumbnail->url.'">';
} ?>
<?PHP } // If
} // If
?>
Pseudo example for styling. You'll need to figure out the css styles for that, but shouldn't be to difficult.
<div class='myBorder'>
<img url=$img->link />
<div class='myCaption'>$img->caption->text</div>
</div>

To get the description
if (isset($img->caption)) {
if (get_magic_quotes_gpc()) {
$title = stripslashes($img->caption->text);
} else {
$title = $img->caption->text;
}
}

Related

Recieve Variable From php file Using fopen?

I've been working on a blogging system and I wish to receive information from external php files for a post's Title and Content, here is my code:
External (Blog Post's Content) File: 03-20-2018-This-Is-A-Test.php
<?php
$Title = 'This is a test!';
$Date = '03-20-2018';
$Content = 'Blog Post's content!';
?>
Client Side Page For Viewing Blog Posts: Post Home.php
<?php
$Title = '';
$Date = '';
$Content = '';
$GetDate = $_GET['d'];
$GetTitle = $_GET['t'];
$postPath = "Posts/$GetDate"."-"."$GetTitle.php";
$postFile = fopen($postPath,"rt");
$postContent = fgets($postFile,filesize($postPath));
?>
<!--Some HTML-->
<h2><? echo $Title; ?></2>
<b><? echo $Date; ?></b>
<p><? echo $Content; ?></p>
<!--Some More HTML-->
<? fclose($postFile); ?>
Client's Page URL: example.com/Post%20Home.php?d=03-20-2018&t=This-Is-A-Test
Reformatted as: example.com/03-20-2018/This-Is-A-Test
As you can see, I am using GET parameters to call the file that I wish to collect the information from.
I have tried using fopen which I wasn't able to get to work. Also include is forbidden with the particular server hosts I am using.
I am open to using file_get_contents if someone is able to help me get it to work.
Note: I have confirmed that my calling URL is correct and I get no errors from my php
So, I am trying to use fopen to collect the data of $Title $Date $Content from the file; 03-20-2018-This-Is-A-Test.php and use that information in the Client Side file; Post Home.php
I was able to find the answer using require().

How to determine whether my content has a instagram embed?

The posts in my site has video(single) from anyone of the following embeds.
Youtube
Facebook
Instagram
My question is while fetching them on front end I want to findo out whether my content has an embed, if so which of the following is embedded. (iframe presence checking is one (dirty)way still it own work for instagram)
PHPCODE:
$video_start = strpos($singlePost->post_content, "<iframe");//Get to the start of the iframe(video)
$video_stop = strpos($singlePost->post_content, "</iframe>");//Get to the end of the iframe(video)
$iframe_content = substr($singlePost->post_content, $video_start, $video_stop);
$xpath = new DOMXPath(#DOMDocument::loadHTML($iframe_content));
$iframe_src = $xpath->evaluate("string(//iframe/#src)");
$parsed_url = parse_url($iframe_src);
$host = $parsed_url['host'];
if(strpos($host, "youtube") !== false) { // If it is a youtube video append this
$iframe_src = $iframe_src."?rel=0";// This option has to be appended of youtube URL's
$related_social_icon = "youtube";
$related_social_media = "youtube";
}
<iframe class="<?php echo $iframe_class; ?>" src="<?php echo $iframe_src; ?>" style="background-size: cover;" allowfullscreen></iframe>
Above code works fine for youtube, but does not work for instagram coz when inserting instagram comes as blockquote tags,but if you echo them it will be straight away become iframe tags due to the script in it.
I would go for something like this:
add_filter('the_content', function($content) {
$identifier = '<embed';
if (strpos($content, $identifier) !== false) {
// identifier found
$content = '<h1>This page includes an embed</h1>'.$content;
}
return $content;
});
I'm not sure how your embeds look like, you are talking about iframes to. So you need to find some identifiers that you can check.
Your post probably got downvoted because it could have some more information?

Show Twitter Feed on my website

Up until a few weeks ago the below code worked great to grab my last three tweets and display them on my website. now it's not working. I've looked through Twitter's messages boards to see if something changed to no avail.
Does anyone know how to effectively display your latest tweets on a website using php?
my original code is here. Like I said, this worked up until a few weeks ago:
$twitterUsername = "myUsername";
$amountToShow = 3;
$twitterRssFeedUrl = 'https://api.twitter.com/1/statuses/user_timeline.rss?screen_name='.$twitterUsername.'&count='.$amountToShow;
$twitterPosts = false;
$xml = #simplexml_load_file($twitterRssFeedUrl);
if(is_object($xml)){
foreach($xml->channel->item as $twit){
if(is_array($twitterPosts) && count($twitterPosts)==$amountToShow){
break;
}
$d['title'] = stripslashes(htmlentities($twit->title,ENT_QUOTES,'UTF-8'));
$description = stripslashes(htmlentities($twit->description,ENT_QUOTES,'UTF-8'));
if(strtolower(substr($description,0,strlen($twitterUsername))) == strtolower($twitterUsername)){
$description = substr($description,strlen($twitterUsername)+1);
}
$d['description'] = $description;
$d['pubdate'] = strtotime($twit->pubDate);
$d['guid'] = stripslashes(htmlentities($twit->guid,ENT_QUOTES,'UTF-8'));
$d['link'] = stripslashes(htmlentities($twit->link,ENT_QUOTES,'UTF-8'));
$twitterPosts[]=$d;
}
}else{
die('Can`t fetch the feed you requested');
}
and then it turns up in the html like so:
<dl class="twitter">
<dt>Twitter Feed</dt>
<?php
if(is_array($twitterPosts)){
echo '';
foreach($twitterPosts as $post){
$data = hyperlinks($post['description']);
$data = twitter_users($data);
echo '<dd>'.$data.'. ';
echo 'Posted '.time2str(date($post['pubdate'])).'</dd>';
}
echo '';
}else{
echo 'No Twitter posts have been made';//Error message
}
?>
<dd>
Twitter API 1.0 that you're using has been switched off, as of a few weeks ago.
Read up on the API 1.1 here: https://dev.twitter.com/docs/api
There are tonnes of PHP libraries for working with the new API, including mine.
The Twitter REST API v1 is no longer active. Please migrate to API v1.1. https://dev.twitter.com/docs/api/1.1/overview.

Turning simple php function into variable

I have a simple function, which I'm trying to turn turn into a query. The idea is to grab the number of facebook likes (which I've done), and pass it into a simple equation (which is ready) to work out the percentage of likes against a target number. I know that the php controling the percentage will return 0.0 at the moment - that's fine for now :) I just can't work out how to get from the function to a variable...
Code as follows:
<?php
function bfan() {
$pageID = 'VisitTywyn';
$info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
echo $info->likes;
} ?>
<?php bfan(); ?>
<?php
echo number_format(($num_amount/$num_total)*100, 1);
?>
Thanks for your help!
What you want to do is return your result so it can be passed to a variable.
<?php
function bfan() {
$pageID = 'VisitTywyn';
$info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
return $info->likes;
} ?>
<?php $something = bfan(); ?>

Echo Twitter share count with PHP?

I am trying to create some text based share buttons for my Wordpress that also output the shared amount. So far I got it working with Facebook and Delicious but I am not sure how to get it going with Twitter.
This is what I did for Delicious.
<?php
$shareUrl = urlencode(get_permalink($post->ID));
$shareTitle = urlencode($post->post_title);
$deliciousStats = json_decode(file_get_contents('http://feeds.delicious.com/v2/json/urlinfo/data?url='.$shareUrl));
?>
<a onclick='window.open("http://delicious.com/save?v=5&noui&jump=close&url=<?php echo $shareUrl; ?>&title=<?php echo $shareTitle; ?>", "facebook", "toolbar=no, width=550, height=550"); return false;' href='http://delicious.com/save?v=5&noui&jump=close&url=<?php echo $shareUrl; ?>&title=<?php echo $shareTitle; ?>' class='delicious'>
<?php
if($deliciousStats[0]->total_posts == 0) {
echo 'Save';
} elseif($deliciousStats[0]->total_posts == 1) {
echo 'One save';
} else {
echo $deliciousStats[0]->total_posts.' saves';
}
?>
</a>
I also got the API Url which calls the tweeted numbers and URL.
http://urls.api.twitter.com/1/urls/count.json?url=SOMESITEURLHERE&callback=twttr.receiveCount
Basically it calls the JSON encoded file, and then gives you the option to share the link in <A></A> tags but instead of showing some text such as Share, it will show the count instead. I'm basically creating some CSS share buttons.
Just use Twitter's own tweet button.
It does that for you and you can style it with .twitter-share-button
(I would post this as a reply but I don't have the privilege.)
Probably you have figured out a solution yourself by now. I just had the same problem and solved it this way:
$handle = fopen('http://urls.api.twitter.com/1/urls/count.json?url=nu.nl', 'rb');
$twitCount = json_decode(stream_get_contents($handle));
fclose($handle);
print_r($twitCount->count);
function get_tweets($url) {
$json_string = file_get_contents('http://urls.api.twitter.com/1/urls/count.json?url=' . $url);
$json = json_decode($json_string, true);
return intval( $json['count'] );
}
function total($url){
return get_tweets($url); }
Then, use this to get the twitte share count in required place.
<?php echo total("http://website.com/"); ?>

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