Date time difference miss to calculate the days to hour - php

Question

I have a date time difference-
I need to calculate those days also into hour.
$start = '2016-05-26 19:05:00';
$end = '2016-05-29 17:05:00';
$datetime1 = new DateTime($start);
$datetime2 = new DateTime($end);
$interval = $datetime1->diff($datetime2);
echo $interval->format("%h Hours %i Min %s Sec"); //22 Hours 0 Min 0 Sec
I know this:
echo $interval->format('%d days');
I try this:
echo $interval->format("(%h + %d * 24) Hours %i Min %s Sec"); //(22 + 8 * 24) Hours 0 Min 0 Sec

Answer 1

$start_date = new DateTime('2007-09-01 04:10:58');
$since_start = $start_date->diff(new DateTime('2012-09-11 10:25:00'));
echo $since_start->days.' days total<br>';
echo $since_start->y.' years<br>';
echo $since_start->m.' months<br>';
echo $since_start->d.' days<br>';
echo $since_start->h.' hours<br>';
echo $since_start->i.' minutes<br>';
echo $since_start->s.' seconds<br>';
echo (($since_start->days)*24)+$since_start->h.' Total Hours<br>';
Use this claculate the days and then multiple by 24 plus remaining hours

Answer 2

Its simple, all though it cannot be done automatically for you, you have to write code.
Here is all you need:
$start = '2016-05-26 19:05:00';
$end = '2016-05-29 17:05:00';
$datetime1 = new DateTime($start);
$datetime2 = new DateTime($end);
$interval = $datetime1->diff($datetime2);
// Below this line is where the magic takes place:
$hourDiff = ($interval->d*24)+($interval->h); //here we calculate the hours
echo $hourDiff //prints 77 because 2 days*24 hours each + 22 hours = 77
In my example I also take into account the years and months (y and m respectively) but you can delete those if you don't want them.